如何查看后台服务是否正在运行?

我想要一个切换服务状态的Android活动——它让我打开它,如果它是关闭的,如果它是关闭的。


当前回答

检查服务是否正在运行的正确方法是简单地询问它。在您的服务中实现一个BroadcastReceiver来响应来自活动的ping。在服务启动时注册BroadcastReceiver,在服务被销毁时注销它。从您的活动(或任何组件)发送一个本地广播意图到服务,如果它响应,您就知道它正在运行。注意下面代码中ACTION_PING和ACTION_PONG之间的细微差别。

public class PingableService extends Service {
    public static final String ACTION_PING = PingableService.class.getName() + ".PING";
    public static final String ACTION_PONG = PingableService.class.getName() + ".PONG";

    public int onStartCommand (Intent intent, int flags, int startId) {
        LocalBroadcastManager.getInstance(this).registerReceiver(mReceiver, new IntentFilter(ACTION_PING));
        return super.onStartCommand(intent, flags, startId);
    }

    @Override
    public void onDestroy () {
        LocalBroadcastManager.getInstance(this).unregisterReceiver(mReceiver);
        super.onDestroy();
    }

    private BroadcastReceiver mReceiver = new BroadcastReceiver() {
        @Override
        public void onReceive (Context context, Intent intent) {
            if (intent.getAction().equals(ACTION_PING)) {
                LocalBroadcastManager manager = LocalBroadcastManager.getInstance(getApplicationContext());
                manager.sendBroadcast(new Intent(ACTION_PONG));
            }
        }
    };
}

public class MyActivity extends Activity {
    private boolean isSvcRunning = false;

    @Override
    protected void onStart() {
        LocalBroadcastManager manager = LocalBroadcastManager.getInstance(getApplicationContext());
        manager.registerReceiver(mReceiver, new IntentFilter(PingableService.ACTION_PONG));
        // the service will respond to this broadcast only if it's running
        manager.sendBroadcast(new Intent(PingableService.ACTION_PING));
        super.onStart();
    }

    @Override
    protected void onStop() {
        LocalBroadcastManager.getInstance(this).unregisterReceiver(mReceiver);
        super.onStop();
    }

    protected BroadcastReceiver mReceiver = new BroadcastReceiver() {
        @Override
        public void onReceive (Context context, Intent intent) {
            // here you receive the response from the service
            if (intent.getAction().equals(PingableService.ACTION_PONG)) {
                isSvcRunning = true;
            }
        }
    };
}

其他回答

你可以使用这个(我还没有尝试过,但我希望它能工作):

if(startService(someIntent) != null) {
    Toast.makeText(getBaseContext(), "Service is already running", Toast.LENGTH_SHORT).show();
}
else {
    Toast.makeText(getBaseContext(), "There is no service running, starting service..", Toast.LENGTH_SHORT).show();
}

如果已经有一个正在运行的服务,startService方法将返回ComponentName对象。如果不是,则返回null。

参见公共抽象ComponentName startService (Intent服务)。

这和检查不一样,因为它正在启动服务,所以你可以添加stopService(someIntent);按照规定。

请使用这个密码。

if (isMyServiceRunning(MainActivity.this, xyzService.class)) { // Service class name
    // Service running
} else {
    // Service Stop
}


public static boolean isMyServiceRunning(Activity activity, Class<?> serviceClass) {
        ActivityManager manager = (ActivityManager) activity.getSystemService(Context.ACTIVITY_SERVICE);
        for (ActivityManager.RunningServiceInfo service : manager.getRunningServices(Integer.MAX_VALUE)) {
            if (serviceClass.getName().equals(service.service.getClassName())) {
                return true;
            }
        }
        return false;
    }

你可以使用Android开发者选项中的这个选项来查看你的服务是否仍然在后台运行。

1. Open Settings in your Android device.
2. Find Developer Options.
3. Find Running Services option.
4. Find your app icon.
5. You will then see all the service that belongs to your app running in the background.
/**
 * Check if the service is Running 
 * @param serviceClass the class of the Service
 *
 * @return true if the service is running otherwise false
 */
public boolean checkServiceRunning(Class<?> serviceClass){
    ActivityManager manager = (ActivityManager) getSystemService(ACTIVITY_SERVICE);
    for (RunningServiceInfo service : manager.getRunningServices(Integer.MAX_VALUE))
    {
        if (serviceClass.getName().equals(service.service.getClassName()))
        {
            return true;
        }
    }
    return false;
}

这更适用于Intent Service调试,因为它们会生成一个线程,但也适用于常规服务。我找到这个线程感谢宾

在我的例子中,我摆弄了调试器并找到了线程视图。它看起来有点像微软Word里的项目符号图标。无论如何,您不必在调试器模式下使用它。单击该流程并单击该按钮。任何Intent服务都会在运行时显示出来,至少在模拟器上是这样。