是否可以使用一些代码获得设备的IP地址?
当前回答
在Kotlin中,没有Formatter
private fun getIPAddress(useIPv4 : Boolean): String {
try {
var interfaces = Collections.list(NetworkInterface.getNetworkInterfaces())
for (intf in interfaces) {
var addrs = Collections.list(intf.getInetAddresses());
for (addr in addrs) {
if (!addr.isLoopbackAddress()) {
var sAddr = addr.getHostAddress();
var isIPv4: Boolean
isIPv4 = sAddr.indexOf(':')<0
if (useIPv4) {
if (isIPv4)
return sAddr;
} else {
if (!isIPv4) {
var delim = sAddr.indexOf('%') // drop ip6 zone suffix
if (delim < 0) {
return sAddr.toUpperCase()
}
else {
return sAddr.substring(0, delim).toUpperCase()
}
}
}
}
}
}
} catch (e: java.lang.Exception) { }
return ""
}
其他回答
引用 // get设备Ip地址
open fun getLocalIpAddress(): String? {
try {
val en: Enumeration<NetworkInterface> = NetworkInterface.getNetworkInterfaces()
while (en.hasMoreElements()) {
val networkInterface: NetworkInterface = en.nextElement()
val enumerationIpAddress: Enumeration<InetAddress> = networkInterface.inetAddresses
while (enumerationIpAddress.hasMoreElements()) {
val inetAddress: InetAddress = enumerationIpAddress.nextElement()
if (!inetAddress.isLoopbackAddress && inetAddress is Inet4Address) {
return inetAddress.getHostAddress()
}
}
}
} catch (ex: SocketException) {
ex.printStackTrace()
}
return null
}
下面的代码可能会帮助你..不要忘记添加权限..
public String getLocalIpAddress(){
try {
for (Enumeration<NetworkInterface> en = NetworkInterface.getNetworkInterfaces();
en.hasMoreElements();) {
NetworkInterface intf = en.nextElement();
for (Enumeration<InetAddress> enumIpAddr = intf.getInetAddresses(); enumIpAddr.hasMoreElements();) {
InetAddress inetAddress = enumIpAddr.nextElement();
if (!inetAddress.isLoopbackAddress()) {
return inetAddress.getHostAddress();
}
}
}
} catch (Exception ex) {
Log.e("IP Address", ex.toString());
}
return null;
}
在清单文件中添加以下权限。
<uses-permission android:name="android.permission.INTERNET" />
<uses-permission android:name="android.permission.ACCESS_NETWORK_STATE" />
编码快乐! !
这是我的助手util读取IP和MAC地址。实现是纯java,但我在getMACAddress()中有一个注释块,可以从特殊的Linux(Android)文件读取值。我只在少数设备和模拟器上运行了这段代码,但如果你发现奇怪的结果,请告诉我。
// AndroidManifest.xml permissions
<uses-permission android:name="android.permission.INTERNET" />
<uses-permission android:name="android.permission.ACCESS_NETWORK_STATE" />
// test functions
Utils.getMACAddress("wlan0");
Utils.getMACAddress("eth0");
Utils.getIPAddress(true); // IPv4
Utils.getIPAddress(false); // IPv6
Utils.java
import java.io.*;
import java.net.*;
import java.util.*;
//import org.apache.http.conn.util.InetAddressUtils;
public class Utils {
/**
* Convert byte array to hex string
* @param bytes toConvert
* @return hexValue
*/
public static String bytesToHex(byte[] bytes) {
StringBuilder sbuf = new StringBuilder();
for(int idx=0; idx < bytes.length; idx++) {
int intVal = bytes[idx] & 0xff;
if (intVal < 0x10) sbuf.append("0");
sbuf.append(Integer.toHexString(intVal).toUpperCase());
}
return sbuf.toString();
}
/**
* Get utf8 byte array.
* @param str which to be converted
* @return array of NULL if error was found
*/
public static byte[] getUTF8Bytes(String str) {
try { return str.getBytes("UTF-8"); } catch (Exception ex) { return null; }
}
/**
* Load UTF8withBOM or any ansi text file.
* @param filename which to be converted to string
* @return String value of File
* @throws java.io.IOException if error occurs
*/
public static String loadFileAsString(String filename) throws java.io.IOException {
final int BUFLEN=1024;
BufferedInputStream is = new BufferedInputStream(new FileInputStream(filename), BUFLEN);
try {
ByteArrayOutputStream baos = new ByteArrayOutputStream(BUFLEN);
byte[] bytes = new byte[BUFLEN];
boolean isUTF8=false;
int read,count=0;
while((read=is.read(bytes)) != -1) {
if (count==0 && bytes[0]==(byte)0xEF && bytes[1]==(byte)0xBB && bytes[2]==(byte)0xBF ) {
isUTF8=true;
baos.write(bytes, 3, read-3); // drop UTF8 bom marker
} else {
baos.write(bytes, 0, read);
}
count+=read;
}
return isUTF8 ? new String(baos.toByteArray(), "UTF-8") : new String(baos.toByteArray());
} finally {
try{ is.close(); } catch(Exception ignored){}
}
}
/**
* Returns MAC address of the given interface name.
* @param interfaceName eth0, wlan0 or NULL=use first interface
* @return mac address or empty string
*/
public static String getMACAddress(String interfaceName) {
try {
List<NetworkInterface> interfaces = Collections.list(NetworkInterface.getNetworkInterfaces());
for (NetworkInterface intf : interfaces) {
if (interfaceName != null) {
if (!intf.getName().equalsIgnoreCase(interfaceName)) continue;
}
byte[] mac = intf.getHardwareAddress();
if (mac==null) return "";
StringBuilder buf = new StringBuilder();
for (byte aMac : mac) buf.append(String.format("%02X:",aMac));
if (buf.length()>0) buf.deleteCharAt(buf.length()-1);
return buf.toString();
}
} catch (Exception ignored) { } // for now eat exceptions
return "";
/*try {
// this is so Linux hack
return loadFileAsString("/sys/class/net/" +interfaceName + "/address").toUpperCase().trim();
} catch (IOException ex) {
return null;
}*/
}
/**
* Get IP address from first non-localhost interface
* @param useIPv4 true=return ipv4, false=return ipv6
* @return address or empty string
*/
public static String getIPAddress(boolean useIPv4) {
try {
List<NetworkInterface> interfaces = Collections.list(NetworkInterface.getNetworkInterfaces());
for (NetworkInterface intf : interfaces) {
List<InetAddress> addrs = Collections.list(intf.getInetAddresses());
for (InetAddress addr : addrs) {
if (!addr.isLoopbackAddress()) {
String sAddr = addr.getHostAddress();
//boolean isIPv4 = InetAddressUtils.isIPv4Address(sAddr);
boolean isIPv4 = sAddr.indexOf(':')<0;
if (useIPv4) {
if (isIPv4)
return sAddr;
} else {
if (!isIPv4) {
int delim = sAddr.indexOf('%'); // drop ip6 zone suffix
return delim<0 ? sAddr.toUpperCase() : sAddr.substring(0, delim).toUpperCase();
}
}
}
}
}
} catch (Exception ignored) { } // for now eat exceptions
return "";
}
}
免责声明:这个Utils类的想法和示例代码来自 几个SO帖子和谷歌。我已经清理和合并了所有的例子。
我不使用Android,但我会用完全不同的方式来解决这个问题。
发送一个查询到谷歌,像这样: https://www.google.com/webhp?sourceid=chrome-instant&ion=1&espv=2&ie=UTF-8#q=my%20ip
并引用发布响应的HTML字段。您也可以直接查询到源。
谷歌最可能比你的应用程序存在的时间长。
只要记住,这可能是你的用户在这个时候没有互联网,你希望发生什么!
祝你好运
简单地使用凌空从这个网站获得ip
RequestQueue queue = Volley.newRequestQueue(this);
String urlip = "http://checkip.amazonaws.com/";
StringRequest stringRequest = new StringRequest(Request.Method.GET, urlip, new Response.Listener<String>() {
@Override
public void onResponse(String response) {
txtIP.setText(response);
}
}, new Response.ErrorListener() {
@Override
public void onErrorResponse(VolleyError error) {
txtIP.setText("didnt work");
}
});
queue.add(stringRequest);
推荐文章
- 如何隐藏动作栏之前的活动被创建,然后再显示它?
- 是否有一种方法以编程方式滚动滚动视图到特定的编辑文本?
- 在Android中将字符串转换为Uri
- 如何在NestedScrollView内使用RecyclerView ?
- 移动到另一个EditText时,软键盘下一步点击Android
- Android应用中的GridView VS GridLayout
- Activity和FragmentActivity的区别
- 右对齐文本在android TextView
- 权限拒绝:start前台需要android.permission.FOREGROUND_SERVICE
- 如何更改android操作栏的标题和图标
- Android Split字符串
- 让一个链接在安卓浏览器启动我的应用程序?
- 如何在Android工作室的外部库中添加一个jar ?
- GridLayout(不是GridView)如何均匀地拉伸所有子元素
- 如何让一个片段删除自己,即它的等效完成()?