是否可以使用一些代码获得设备的IP地址?
当前回答
根据我的测试,这是我的建议
import java.net.*;
import java.util.*;
public class hostUtil
{
public static String HOST_NAME = null;
public static String HOST_IPADDRESS = null;
public static String getThisHostName ()
{
if (HOST_NAME == null) obtainHostInfo ();
return HOST_NAME;
}
public static String getThisIpAddress ()
{
if (HOST_IPADDRESS == null) obtainHostInfo ();
return HOST_IPADDRESS;
}
protected static void obtainHostInfo ()
{
HOST_IPADDRESS = "127.0.0.1";
HOST_NAME = "localhost";
try
{
InetAddress primera = InetAddress.getLocalHost();
String hostname = InetAddress.getLocalHost().getHostName ();
if (!primera.isLoopbackAddress () &&
!hostname.equalsIgnoreCase ("localhost") &&
primera.getHostAddress ().indexOf (':') == -1)
{
// Got it without delay!!
HOST_IPADDRESS = primera.getHostAddress ();
HOST_NAME = hostname;
//System.out.println ("First try! " + HOST_NAME + " IP " + HOST_IPADDRESS);
return;
}
for (Enumeration<NetworkInterface> netArr = NetworkInterface.getNetworkInterfaces(); netArr.hasMoreElements();)
{
NetworkInterface netInte = netArr.nextElement ();
for (Enumeration<InetAddress> addArr = netInte.getInetAddresses (); addArr.hasMoreElements ();)
{
InetAddress laAdd = addArr.nextElement ();
String ipstring = laAdd.getHostAddress ();
String hostName = laAdd.getHostName ();
if (laAdd.isLoopbackAddress()) continue;
if (hostName.equalsIgnoreCase ("localhost")) continue;
if (ipstring.indexOf (':') >= 0) continue;
HOST_IPADDRESS = ipstring;
HOST_NAME = hostName;
break;
}
}
} catch (Exception ex) {}
}
}
其他回答
WifiManager wm = (WifiManager) getSystemService(WIFI_SERVICE);
String ipAddress = BigInteger.valueOf(wm.getDhcpInfo().netmask).toString();
我使用以下代码: 我使用hashCode的原因是因为当我使用getHostAddress时,我得到了一些垃圾值附加到ip地址。但是hashCode对我来说工作得很好,这样我就可以使用Formatter来获得具有正确格式的ip地址。
下面是示例输出:
1.使用 getHostAddress : ***** IP=fe80::65ca:a13d:ea5a:233d%rmnet_sdio0
2.使用hashCode和Formatter: ***** IP=238.194.77.212
如你所见,第二种方法正好满足了我的需求。
public String getLocalIpAddress() {
try {
for (Enumeration<NetworkInterface> en = NetworkInterface.getNetworkInterfaces(); en.hasMoreElements();) {
NetworkInterface intf = en.nextElement();
for (Enumeration<InetAddress> enumIpAddr = intf.getInetAddresses(); enumIpAddr.hasMoreElements();) {
InetAddress inetAddress = enumIpAddr.nextElement();
if (!inetAddress.isLoopbackAddress()) {
String ip = Formatter.formatIpAddress(inetAddress.hashCode());
Log.i(TAG, "***** IP="+ ip);
return ip;
}
}
}
} catch (SocketException ex) {
Log.e(TAG, ex.toString());
}
return null;
}
虽然有一个正确的答案,我在这里分享我的答案,希望这样会更方便。
WifiManager wifiMan = (WifiManager) context.getSystemService(Context.WIFI_SERVICE);
WifiInfo wifiInf = wifiMan.getConnectionInfo();
int ipAddress = wifiInf.getIpAddress();
String ip = String.format("%d.%d.%d.%d", (ipAddress & 0xff),(ipAddress >> 8 & 0xff),(ipAddress >> 16 & 0xff),(ipAddress >> 24 & 0xff));
在Kotlin中,没有Formatter
private fun getIPAddress(useIPv4 : Boolean): String {
try {
var interfaces = Collections.list(NetworkInterface.getNetworkInterfaces())
for (intf in interfaces) {
var addrs = Collections.list(intf.getInetAddresses());
for (addr in addrs) {
if (!addr.isLoopbackAddress()) {
var sAddr = addr.getHostAddress();
var isIPv4: Boolean
isIPv4 = sAddr.indexOf(':')<0
if (useIPv4) {
if (isIPv4)
return sAddr;
} else {
if (!isIPv4) {
var delim = sAddr.indexOf('%') // drop ip6 zone suffix
if (delim < 0) {
return sAddr.toUpperCase()
}
else {
return sAddr.substring(0, delim).toUpperCase()
}
}
}
}
}
}
} catch (e: java.lang.Exception) { }
return ""
}
请检查这个代码…使用此代码。我们将从移动互联网获得IP…
for (Enumeration<NetworkInterface> en = NetworkInterface.getNetworkInterfaces(); en.hasMoreElements(); ) {
NetworkInterface intf = en.nextElement();
for (Enumeration<InetAddress> enumIpAddr = intf.getInetAddresses(); enumIpAddr.hasMoreElements(); ) {
InetAddress inetAddress = enumIpAddr.nextElement();
if (!inetAddress.isLoopbackAddress()) {
return inetAddress.getHostAddress().toString();
}
}
}
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