以下是它在Android中的实现方式。

作为概念的证明，我将这段代码翻译成c#:

var request = (HttpWebRequest)WebRequest.Create("http://g.cn/generate_204");
request.UserAgent = "Android";
request.KeepAlive = false;
request.Timeout = 1500;

using (var response = (HttpWebResponse)request.GetResponse())
{
    if (response.ContentLength == 0 && response.StatusCode == HttpStatusCode.NoContent)
    {
        //Connection to internet available
    }
    else
    {
        //Connection to internet not available
    }
}

我不同意有人说:“在执行任务之前检查连接有什么意义，因为检查之后连接可能会丢失”。 当然，我们作为开发人员承担的许多编程任务中都存在一定程度的不确定性，但将不确定性降低到可接受的水平是挑战的一部分。

我最近遇到了这个问题，使一个应用程序，其中包括一个映射功能，链接到一个在线瓷砖服务器。这一功能将在缺乏互联网连接时被禁用。

本页上的一些响应非常好，但确实导致了许多性能问题，例如挂起，主要是在没有连接的情况下。

以下是我最终使用的解决方案，在这些答案和我同事的帮助下:

         // Insert this where check is required, in my case program start
         ThreadPool.QueueUserWorkItem(CheckInternetConnectivity);
    }

    void CheckInternetConnectivity(object state)
    {
        if (System.Net.NetworkInformation.NetworkInterface.GetIsNetworkAvailable())
        {
            using (WebClient webClient = new WebClient())
            {
                webClient.CachePolicy = new System.Net.Cache.RequestCachePolicy(System.Net.Cache.RequestCacheLevel.BypassCache);
                webClient.Proxy = null;
                webClient.OpenReadCompleted += webClient_OpenReadCompleted;
                webClient.OpenReadAsync(new Uri("<url of choice here>"));
            }
        }
    }

    volatile bool internetAvailable = false; // boolean used elsewhere in code

    void webClient_OpenReadCompleted(object sender, OpenReadCompletedEventArgs e)
    {
        if (e.Error == null)
        {
            internetAvailable = true;
            Dispatcher.Invoke(DispatcherPriority.Normal, new Action(() =>
            {
                // UI changes made here
            }));
        }
    }

如果你想在网络/连接发生变化时通知用户/采取行动。 使用NLM API:

https://msdn.microsoft.com/en-us/library/ee264321.aspx http://www.codeproject.com/Articles/34650/How-to-use-the-Windows-NLM-API-to-get-notified-of

public static bool HasConnection()
{
    try
    {
        System.Net.IPHostEntry i = System.Net.Dns.GetHostEntry("www.google.com");
        return true;
    }
    catch
    {
        return false;
    }
}

工作

使用NetworkMonitor监控网络状态和internet连接。

示例:

namespace AmRoNetworkMonitor.Demo
{
    using System;

    internal class Program
    {
        private static void Main()
        {
            NetworkMonitor.StateChanged += NetworkMonitor_StateChanged;
            NetworkMonitor.StartMonitor();

            Console.WriteLine("Press any key to stop monitoring.");
            Console.ReadKey();
            NetworkMonitor.StopMonitor();

            Console.WriteLine("Press any key to close program.");
            Console.ReadKey();
        }

        private static void NetworkMonitor_StateChanged(object sender, StateChangeEventArgs e)
        {
            Console.WriteLine(e.IsAvailable ? "Is Available" : "Is Not Available");
        }
    }
}

ping google.com会引入一个DNS解析依赖。ping 8.8.8.8很好，但谷歌离我很远。我所需要做的就是在互联网上ping离我最近的东西。

我可以使用Ping的TTL功能来Ping跳#1，然后跳#2，等等，直到我从一个可路由地址上的某个东西得到回复;如果该节点在一个可路由地址上，那么它就在因特网上。对于我们大多数人来说，跳点1将是我们的本地网关/路由器，跳点2将是光纤连接或其他设备的另一侧的第一个点。

这段代码对我有用，比这个线程中的其他一些建议反应更快，因为它是在互联网上ping离我最近的任何东西。

using System.Diagnostics;
using System.Net;
using System.Net.NetworkInformation;
using System.Net.Sockets;
using System.Threading.Tasks;
    
public static async Task<bool> IsConnectedToInternetAsync()
{
    const int maxHops = 30;
    const string someFarAwayIpAddress = "8.8.8.8";
    
    // Keep pinging further along the line from here to google 
    // until we find a response that is from a routable address
    for (int ttl = 1; ttl <= maxHops; ttl++)
    {
        var options = new PingOptions(ttl, true);
        byte[] buffer = new byte[32];
        PingReply reply;
        try
        {
            using (var pinger = new Ping())
            {
                reply = await pinger.SendPingAsync(someFarAwayIpAddress, 10000, buffer, options);
            }
        }
        catch (PingException pingex)
        {
            Debug.Print($"Ping exception (probably due to no network connection or recent change in network conditions), hence not connected to internet. Message: {pingex.Message}");
            return false;
        }
    
        string address = reply.Address?.ToString() ?? null;
        Debug.Print($"Hop #{ttl} is {address}, {reply.Status}");
    
        if (reply.Status != IPStatus.TtlExpired && reply.Status != IPStatus.Success)
        {
            Debug.Print($"Hop #{ttl} is {reply.Status}, hence we are not connected.");
            return false;
        }
    
        if (IsRoutableAddress(reply.Address))
        {
            Debug.Print("That's routable, so we must be connected to the internet.");
            return true;
        }
    }
    
    return false;
}
    
private static bool IsRoutableAddress(IPAddress addr)
{
    if (addr == null)
    {
        return false;
    }
    else if (addr.AddressFamily == AddressFamily.InterNetworkV6)
    {
        return !addr.IsIPv6LinkLocal && !addr.IsIPv6SiteLocal;
    }
    else // IPv4
    {
        byte[] bytes = addr.GetAddressBytes();
        if (bytes[0] == 10)
        {   // Class A network
            return false;
        }
        else if (bytes[0] == 172 && bytes[1] >= 16 && bytes[1] <= 31)
        {   // Class B network
            return false;
        }
        else if (bytes[0] == 192 && bytes[1] == 168)
        {   // Class C network
            return false;
        }
        else
        {   // None of the above, so must be routable
            return true;
        }
    }
}