如何在Python中实现通用树?这有内置的数据结构吗?


当前回答

class Tree(dict):
    """A tree implementation using python's autovivification feature."""
    def __missing__(self, key):
        value = self[key] = type(self)()
        return value

    #cast a (nested) dict to a (nested) Tree class
    def __init__(self, data={}):
        for k, data in data.items():
            if isinstance(data, dict):
                self[k] = type(self)(data)
            else:
                self[k] = data

作为一个字典,但提供尽可能多的嵌套字典。 试试下面的方法:

your_tree = Tree()

your_tree['a']['1']['x']  = '@'
your_tree['a']['1']['y']  = '#'
your_tree['a']['2']['x']  = '$'
your_tree['a']['3']       = '%'
your_tree['b']            = '*'

将传递一个嵌套的字典…就像树一样。

{'a': {'1': {'x': '@', 'y': '#'}, '2': {'x': '$'}, '3': '%'}, 'b': '*'}

... 如果你已经有字典了,它会把每一层都投射到一棵树上:

d = {'foo': {'amy': {'what': 'runs'} } }
tree = Tree(d)

print(d['foo']['amy']['what']) # returns 'runs'
d['foo']['amy']['when'] = 'now' # add new branch

这样,你就可以随心所欲地编辑/添加/删除每个词典级别。 遍历等所有dict方法仍然适用。

其他回答

class Node:
    """
    Class Node
    """
    def __init__(self, value):
        self.left = None
        self.data = value
        self.right = None

class Tree:
    """
    Class tree will provide a tree as well as utility functions.
    """

    def createNode(self, data):
        """
        Utility function to create a node.
        """
        return Node(data)

    def insert(self, node , data):
        """
        Insert function will insert a node into tree.
        Duplicate keys are not allowed.
        """
        #if tree is empty , return a root node
        if node is None:
            return self.createNode(data)
        # if data is smaller than parent , insert it into left side
        if data < node.data:
            node.left = self.insert(node.left, data)
        elif data > node.data:
            node.right = self.insert(node.right, data)

        return node


    def search(self, node, data):
        """
        Search function will search a node into tree.
        """
        # if root is None or root is the search data.
        if node is None or node.data == data:
            return node

        if node.data < data:
            return self.search(node.right, data)
        else:
            return self.search(node.left, data)



    def deleteNode(self,node,data):
        """
        Delete function will delete a node into tree.
        Not complete , may need some more scenarion that we can handle
        Now it is handling only leaf.
        """

        # Check if tree is empty.
        if node is None:
            return None

        # searching key into BST.
        if data < node.data:
            node.left = self.deleteNode(node.left, data)
        elif data > node.data:
            node.right = self.deleteNode(node.right, data)
        else: # reach to the node that need to delete from BST.
            if node.left is None and node.right is None:
                del node
            if node.left == None:
                temp = node.right
                del node
                return  temp
            elif node.right == None:
                temp = node.left
                del node
                return temp

        return node

    def traverseInorder(self, root):
        """
        traverse function will print all the node in the tree.
        """
        if root is not None:
            self.traverseInorder(root.left)
            print(root.data)
            self.traverseInorder(root.right)

    def traversePreorder(self, root):
        """
        traverse function will print all the node in the tree.
        """
        if root is not None:
            print(root.data)
            self.traversePreorder(root.left)
            self.traversePreorder(root.right)

    def traversePostorder(self, root):
        """
        traverse function will print all the node in the tree.
        """
        if root is not None:
            self.traversePostorder(root.left)
            self.traversePostorder(root.right)
            print(root.data)


def main():
    root = None
    tree = Tree()
    root = tree.insert(root, 10)
    print(root)
    tree.insert(root, 20)
    tree.insert(root, 30)
    tree.insert(root, 40)
    tree.insert(root, 70)
    tree.insert(root, 60)
    tree.insert(root, 80)

    print("Traverse Inorder")
    tree.traverseInorder(root)

    print("Traverse Preorder")
    tree.traversePreorder(root)

    print("Traverse Postorder")
    tree.traversePostorder(root)


if __name__ == "__main__":
    main()

如果您已经在使用networkx库,那么您可以使用它实现一个树。

NetworkX是一个用于创建、操作和研究的Python包 复杂网络的结构、动力学和功能。

因为“树”是(通常根)连接无环图的另一个术语,这些在NetworkX中被称为“树状图”。

你可能想要实现一个平面树(又名有序树),其中每个兄弟姐妹都有一个唯一的秩,这通常通过标记节点来完成。

然而,图语言看起来不同于树语言,“扎根”树的方法通常是使用有向图,因此,虽然有一些非常酷的功能和相应的可视化可用,但如果你还没有使用networkx,它可能不是一个理想的选择。

一个构建树的例子:

import networkx as nx
G = nx.Graph()
G.add_edge('A', 'B')
G.add_edge('B', 'C')
G.add_edge('B', 'D')
G.add_edge('A', 'E')
G.add_edge('E', 'F')

该库允许每个节点是任何可哈希对象,并且不限制每个节点拥有的子节点的数量。

嗨,你可以试试itertree(我是作者)。

该包与任何树包的方向相同,但关注点略有不同。在巨大的树(>100000个项目)上的性能要好得多,它处理迭代器具有有效的过滤机制。

>>>from itertree import *
>>>root=iTree('root')

>>># add some children:
>>>root.append(iTree('Africa',data={'surface':30200000,'inhabitants':1257000000}))
>>>root.append(iTree('Asia', data={'surface': 44600000, 'inhabitants': 4000000000}))
>>>root.append(iTree('America', data={'surface': 42549000, 'inhabitants': 1009000000}))
>>>root.append(iTree('Australia&Oceania', data={'surface': 8600000, 'inhabitants': 36000000}))
>>>root.append(iTree('Europe', data={'surface': 10523000 , 'inhabitants': 746000000}))
>>># you might use __iadd__ operator for adding too:
>>>root+=iTree('Antarktika', data={'surface': 14000000, 'inhabitants': 1100})

>>># for building next level we select per index:
>>>root[0]+=iTree('Ghana',data={'surface':238537,'inhabitants':30950000})
>>>root[0]+=iTree('Niger', data={'surface': 1267000, 'inhabitants': 23300000})
>>>root[1]+=iTree('China', data={'surface': 9596961, 'inhabitants': 1411780000})
>>>root[1]+=iTree('India', data={'surface': 3287263, 'inhabitants': 1380004000})
>>>root[2]+=iTree('Canada', data={'type': 'country', 'surface': 9984670, 'inhabitants': 38008005})    
>>>root[2]+=iTree('Mexico', data={'surface': 1972550, 'inhabitants': 127600000 })
>>># extend multiple items:
>>>root[3].extend([iTree('Australia', data={'surface': 7688287, 'inhabitants': 25700000 }), iTree('New Zealand', data={'surface': 269652, 'inhabitants': 4900000 })])
>>>root[4]+=iTree('France', data={'surface': 632733, 'inhabitants': 67400000 }))
>>># select parent per TagIdx - remember in itertree you might put items with same tag multiple times:
>>>root[TagIdx('Europe'0)]+=iTree('Finland', data={'surface': 338465, 'inhabitants': 5536146 })

创建的树可以被渲染:

>>>root.render()
iTree('root')
     └──iTree('Africa', data=iTData({'surface': 30200000, 'inhabitants': 1257000000}))
         └──iTree('Ghana', data=iTData({'surface': 238537, 'inhabitants': 30950000}))
         └──iTree('Niger', data=iTData({'surface': 1267000, 'inhabitants': 23300000}))
     └──iTree('Asia', data=iTData({'surface': 44600000, 'inhabitants': 4000000000}))
         └──iTree('China', data=iTData({'surface': 9596961,  'inhabitants': 1411780000}))
         └──iTree('India', data=iTData({'surface': 3287263, 'inhabitants': 1380004000}))
     └──iTree('America', data=iTData({'surface': 42549000, 'inhabitants': 1009000000}))
         └──iTree('Canada', data=iTData({'surface': 9984670, 'inhabitants': 38008005}))
         └──iTree('Mexico', data=iTData({'surface': 1972550, 'inhabitants': 127600000}))
     └──iTree('Australia&Oceania', data=iTData({'surface': 8600000, 'inhabitants': 36000000}))
         └──iTree('Australia', data=iTData({'surface': 7688287, 'inhabitants': 25700000}))
         └──iTree('New Zealand', data=iTData({'surface': 269652, 'inhabitants': 4900000}))
     └──iTree('Europe', data=iTData({'surface': 10523000, 'inhabitants': 746000000}))
         └──iTree('France', data=iTData({'surface': 632733, 'inhabitants': 67400000}))
         └──iTree('Finland', data=iTData({'surface': 338465, 'inhabitants': 5536146}))
     └──iTree('Antarktika', data=iTData({'surface': 14000000, 'inhabitants': 1100}))

过滤可以这样做:

>>>item_filter = Filter.iTFilterData(data_key='inhabitants', data_value=iTInterval(0, 20000000))
>>>iterator=root.iter_all(item_filter=item_filter)
>>>for i in iterator:
>>>    print(i)
iTree("'New Zealand'", data=iTData({'surface': 269652, 'inhabitants': 4900000}), subtree=[])
iTree("'Finland'", data=iTData({'surface': 338465, 'inhabitants': 5536146}), subtree=[])
iTree("'Antarktika'", data=iTData({'surface': 14000000, 'inhabitants': 1100}), subtree=[])

我将根树实现为字典{child:parent}。比如根节点为0,树可能是这样的:

tree={1:0, 2:0, 3:1, 4:2, 5:3}

这种结构使得沿着一条路径从任意节点向上到根结点非常容易,这与我正在处理的问题有关。

class Tree(dict):
    """A tree implementation using python's autovivification feature."""
    def __missing__(self, key):
        value = self[key] = type(self)()
        return value

    #cast a (nested) dict to a (nested) Tree class
    def __init__(self, data={}):
        for k, data in data.items():
            if isinstance(data, dict):
                self[k] = type(self)(data)
            else:
                self[k] = data

作为一个字典,但提供尽可能多的嵌套字典。 试试下面的方法:

your_tree = Tree()

your_tree['a']['1']['x']  = '@'
your_tree['a']['1']['y']  = '#'
your_tree['a']['2']['x']  = '$'
your_tree['a']['3']       = '%'
your_tree['b']            = '*'

将传递一个嵌套的字典…就像树一样。

{'a': {'1': {'x': '@', 'y': '#'}, '2': {'x': '$'}, '3': '%'}, 'b': '*'}

... 如果你已经有字典了,它会把每一层都投射到一棵树上:

d = {'foo': {'amy': {'what': 'runs'} } }
tree = Tree(d)

print(d['foo']['amy']['what']) # returns 'runs'
d['foo']['amy']['when'] = 'now' # add new branch

这样,你就可以随心所欲地编辑/添加/删除每个词典级别。 遍历等所有dict方法仍然适用。