我想根据是否显示虚拟键盘来改变布局。我已经搜索了API和各种博客,但似乎找不到任何有用的东西。

这可能吗?

谢谢!


当前回答

如果你想从你的活动中处理IMM(虚拟)键盘窗口的显示/隐藏,你需要子类化你的布局并覆盖onMesure方法(这样你就可以确定你的布局的测量宽度和测量高度)。之后,通过setContentView()将子类布局设置为Activity的主视图。现在您将能够处理IMM显示/隐藏窗口事件。也许这听起来很复杂,但事实并非如此。代码如下:

main。xml

   <?xml version="1.0" encoding="utf-8"?>
   <LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
        android:layout_width="fill_parent"
        android:layout_height="fill_parent"
        android:orientation="horizontal" >
        <EditText
             android:id="@+id/SearchText" 
             android:text="" 
             android:inputType="text"
             android:layout_width="fill_parent"
             android:layout_height="34dip"
             android:singleLine="True"
             />
        <Button
             android:id="@+id/Search" 
             android:layout_width="60dip"
             android:layout_height="34dip"
             android:gravity = "center"
             />
    </LinearLayout>

现在在布局的Activity声明子类中(main.xml)

    public class MainSearchLayout extends LinearLayout {

    public MainSearchLayout(Context context, AttributeSet attributeSet) {
        super(context, attributeSet);
        LayoutInflater inflater = (LayoutInflater) context.getSystemService(Context.LAYOUT_INFLATER_SERVICE);
        inflater.inflate(R.layout.main, this);
    }

    @Override
    protected void onMeasure(int widthMeasureSpec, int heightMeasureSpec) {
        Log.d("Search Layout", "Handling Keyboard Window shown");

        final int proposedheight = MeasureSpec.getSize(heightMeasureSpec);
        final int actualHeight = getHeight();

        if (actualHeight > proposedheight){
            // Keyboard is shown

        } else {
            // Keyboard is hidden
        }
        super.onMeasure(widthMeasureSpec, heightMeasureSpec);
    }
}

您可以从代码中看到,我们在子类构造函数中为Activity扩展布局

inflater.inflate(R.layout.main, this);

现在只需设置Activity的子类布局的内容视图。

public class MainActivity extends Activity {

    /** Called when the activity is first created. */
    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);

        MainSearchLayout searchLayout = new MainSearchLayout(this, null);

        setContentView(searchLayout);
    }

    // rest of the Activity code and subclassed layout...

}

其他回答

Nebojsa的解决方案几乎对我有效。当我在一个多行EditText中单击时,它知道键盘被显示出来,但是当我开始在EditText中输入时,actualHeight和proposedHeight仍然是相同的,所以它不知道键盘仍然被显示出来。我做了一个轻微的修改,以存储最大高度,它工作得很好。下面是修改后的子类:

public class CheckinLayout extends RelativeLayout {

    private int largestHeight;

    public CheckinLayout(Context context, AttributeSet attributeSet) {
        super(context, attributeSet);
        LayoutInflater inflater = (LayoutInflater) context.getSystemService(Context.LAYOUT_INFLATER_SERVICE);
        inflater.inflate(R.layout.checkin, this);
    }

    @Override
    protected void onMeasure(int widthMeasureSpec, int heightMeasureSpec) {
        final int proposedheight = MeasureSpec.getSize(heightMeasureSpec);
        largestHeight = Math.max(largestHeight, getHeight());

        if (largestHeight > proposedheight)
            // Keyboard is shown
        else
            // Keyboard is hidden

        super.onMeasure(widthMeasureSpec, heightMeasureSpec);
    }
}

Nebojsa Tomcic的回答对我没有帮助。我有RelativeLayout与TextView和AutoCompleteTextView里面。我需要滚动TextView到底部时,键盘显示,当它被隐藏。为了实现这一点,我重写了onLayout方法,它对我来说很好。

public class ExtendedLayout extends RelativeLayout
{
    public ExtendedLayout(Context context, AttributeSet attributeSet)
    {
        super(context, attributeSet);
        LayoutInflater inflater = (LayoutInflater)
                context.getSystemService(Context.LAYOUT_INFLATER_SERVICE);
        inflater.inflate(R.layout.main, this);
    }

    @Override
    protected void onLayout(boolean changed, int l, int t, int r, int b)
    {
        super.onLayout(changed, l, t, r, b);

        if (changed)
        {
            int scrollEnd = (textView.getLineCount() - textView.getHeight() /
                textView.getLineHeight()) * textView.getLineHeight();
            textView.scrollTo(0, scrollEnd);
        }
    }
}

不确定是否有人发布这篇文章。发现这个解决方案简单易用!SoftKeyboard类在gi.github.com上。但是当键盘弹出/隐藏事件回调时,我们需要一个处理程序来正确地在UI上做事情:

/*
Somewhere else in your code
*/
RelativeLayout mainLayout = findViewById(R.layout.main_layout); // You must use your root layout
InputMethodManager im = (InputMethodManager) getSystemService(Service.INPUT_METHOD_SERVICE);

/*
Instantiate and pass a callback
*/
SoftKeyboard softKeyboard;
softKeyboard = new SoftKeyboard(mainLayout, im);
softKeyboard.setSoftKeyboardCallback(new SoftKeyboard.SoftKeyboardChanged()
{

    @Override
    public void onSoftKeyboardHide() 
    {
        // Code here
        new Handler(Looper.getMainLooper()).post(new Runnable() {
                @Override
                public void run() {
                    // Code here will run in UI thread
                    ...
                }
            });
    }

    @Override
    public void onSoftKeyboardShow() 
    {
        // Code here
        new Handler(Looper.getMainLooper()).post(new Runnable() {
                @Override
                public void run() {
                    // Code here will run in UI thread
                    ...
                }
            });

    }   
});

你也可以检查第一个DecorView的子底部填充。当键盘显示时,它将被设置为非零值。

@Override
protected void onLayout(boolean changed, int left, int top, int right, int bottom) {
    View view = getRootView();
    if (view != null && (view = ((ViewGroup) view).getChildAt(0)) != null) {
        setKeyboardVisible(view.getPaddingBottom() > 0);
    }
    super.onLayout(changed, left, top, right, bottom);
}

android 11之前的解决方案:

androidx。Core 1.5.0发布了,这是我在android 11之前的设备上监听键盘显示/隐藏事件的方法。

gradle:

implementation "androidx.core:core-ktx:1.5.0"

片段:

   override fun onViewCreated(view: View, savedInstanceState: Bundle?) {
        super.onViewCreated(view, savedInstanceState)
        val view  = activity?.window?.decorView ?: return
        ViewCompat.setOnApplyWindowInsetsListener(view) { v, insets ->
            val showingKeyboard = insets.isVisible(WindowInsetsCompat.Type.ime())
            if(showingKeyboard){
                //do something
            }
            insets
        }
    }

确保在视图销毁时删除侦听器,以避免内存泄漏。这个解决方案也只适用于软件输入模式为adjuststresize时,如果它是adjustPan, setOnApplyWindowInsetsListener将不会触发,如果任何人有关于如何使它与adjustPan一起工作的想法,请分享。

注意,根据医生的说法

* When running on devices with API Level 29 and before, the returned value is an
* approximation based on the information available. This is especially true for the {@link
* Type#ime IME} type, which currently only works when running on devices with SDK level 23
* and above.
*

insets.isVisible(ime)应该只在SDK级别高于23的设备上工作