我试图返回一个状态代码304未修改的web api控制器中的GET方法。

我成功的唯一方法是这样的:

public class TryController : ApiController
{
    public User GetUser(int userId, DateTime lastModifiedAtClient)
    {
        var user = new DataEntities().Users.First(p => p.Id == userId);
        if (user.LastModified <= lastModifiedAtClient)
        {
             throw new HttpResponseException(HttpStatusCode.NotModified);
        }
        return user;
    }
}

这里的问题是,它不是一个异常,它只是没有修改,所以客户端缓存是OK的。 我还希望返回类型是一个用户(所有的web api示例显示与GET)不返回HttpResponseMessage或类似的东西。


当前回答

试试这个:

return new ContentResult() { 
    StatusCode = 404, 
    Content = "Not found" 
};

其他回答

在MVC 5中,事情变得更简单了:

return new StatusCodeResult(HttpStatusCode.NotModified, this);

我不喜欢改变我的签名来使用HttpCreateResponse类型,所以我提出了一个扩展的解决方案来隐藏它。

public class HttpActionResult : IHttpActionResult
{
    public HttpActionResult(HttpRequestMessage request) : this(request, HttpStatusCode.OK)
    {
    }

    public HttpActionResult(HttpRequestMessage request, HttpStatusCode code) : this(request, code, null)
    {
    }

    public HttpActionResult(HttpRequestMessage request, HttpStatusCode code, object result)
    {
        Request = request;
        Code = code;
        Result = result;
    }

    public HttpRequestMessage Request { get; }
    public HttpStatusCode Code { get; }
    public object Result { get; }

    public Task<HttpResponseMessage> ExecuteAsync(CancellationToken cancellationToken)
    {
        return Task.FromResult(Request.CreateResponse(Code, Result));
    }
}

然后你可以添加一个方法到你的ApiController(或者更好的是你的基本控制器),像这样:

protected IHttpActionResult CustomResult(HttpStatusCode code, object data) 
{
    // Request here is the property on the controller.
    return new HttpActionResult(Request, code, data);
}

然后你可以像任何内置方法一样返回它:

[HttpPost]
public IHttpActionResult Post(Model model)
{
    return model.Id == 1 ?
                Ok() :
                CustomResult(HttpStatusCode.NotAcceptable, new { 
                    data = model, 
                    error = "The ID needs to be 1." 
                });
}
public HttpResponseMessage Post(Article article)
{
    HttpResponseMessage response = Request.CreateResponse<Article>(HttpStatusCode.Created, article);

    string uriToTheCreatedItem = Url.Route(null, new { id = article.Id });
    response.Headers.Location = new Uri(Request.RequestUri, uriToTheCreatedItem);

    return response;
}

更改GetXxx API方法以返回HttpResponseMessage,然后返回完整响应的类型化版本和NotModified响应的非类型化版本。

    public HttpResponseMessage GetComputingDevice(string id)
    {
        ComputingDevice computingDevice =
            _db.Devices.OfType<ComputingDevice>()
                .SingleOrDefault(c => c.AssetId == id);

        if (computingDevice == null)
        {
            return this.Request.CreateResponse(HttpStatusCode.NotFound);
        }

        if (this.Request.ClientHasStaleData(computingDevice.ModifiedDate))
        {
            return this.Request.CreateResponse<ComputingDevice>(
                HttpStatusCode.OK, computingDevice);
        }
        else
        {
            return this.Request.CreateResponse(HttpStatusCode.NotModified);
        }
    }

* ClientHasStale数据是我的扩展检查ETag和IfModifiedSince头。

MVC框架仍然应该序列化并返回您的对象。

NOTE

我认为通用版本将在未来的Web API版本中被删除。

.net core 2.2返回304状态码。这是使用ApiController。

    [HttpGet]
    public ActionResult<YOUROBJECT> Get()
    {
        return StatusCode(304);
    }

您还可以选择返回带有响应的对象

    [HttpGet]
    public ActionResult<YOUROBJECT> Get()
    {
        return StatusCode(304, YOUROBJECT); 
    }