我在玩苹果的新Swift编程语言，遇到了一些问题…
目前我试图读取一个plist文件，在Objective-C中，我会做以下工作来获取内容作为NSDictionary:
NSString *filePath = [[NSBundle mainBundle] pathForResource:@"Config" ofType:@"plist"];
NSDictionary *dict = [[NSDictionary alloc] initWithContentsOfFile:filePath];
我如何得到一个plist作为一个字典在Swift?
我假设我可以得到路径到plist:
let path = NSBundle.mainBundle().pathForResource("Config", ofType: "plist")
当这工作(如果它是正确的?):我如何获得内容作为一个字典?
还有一个更普遍的问题:
是否可以使用默认的NS*类?我想是的……还是我遗漏了什么?据我所知，默认框架NS*类仍然有效，可以使用吗?
当前回答
这个答案使用Swift本机对象而不是NSDictionary。
斯威夫特3.0
//get the path of the plist file
guard let plistPath = Bundle.main.path(forResource: "level1", ofType: "plist") else { return }
//load the plist as data in memory
guard let plistData = FileManager.default.contents(atPath: plistPath) else { return }
//use the format of a property list (xml)
var format = PropertyListSerialization.PropertyListFormat.xml
//convert the plist data to a Swift Dictionary
guard let plistDict = try! PropertyListSerialization.propertyList(from: plistData, options: .mutableContainersAndLeaves, format: &format) as? [String : AnyObject] else { return }
//access the values in the dictionary
if let value = plistDict["aKey"] as? String {
//do something with your value
print(value)
}
//you can also use the coalesce operator to handle possible nil values
var myValue = plistDict["aKey"] ?? ""
其他回答
因为这个答案还没有在这里，只是想指出，你也可以使用infoDictionary属性来获取信息plist作为字典，Bundle.main.infoDictionary。
比如bundle。main。如果您只对info plist中的特定项感兴趣，则可以使用kCFBundleNameKey作为String)。
// Swift 4
// Getting info plist as a dictionary
let dictionary = Bundle.main.infoDictionary
// Getting the app display name from the info plist
Bundle.main.infoDictionary?[kCFBundleNameKey as String]
// Getting the app display name from the info plist (another way)
Bundle.main.object(forInfoDictionaryKey: kCFBundleNameKey as String)
斯威夫特3.0
如果你想从.plist读取一个“二维数组”，你可以这样尝试:
if let path = Bundle.main.path(forResource: "Info", ofType: "plist") {
if let dimension1 = NSDictionary(contentsOfFile: path) {
if let dimension2 = dimension1["key"] as? [String] {
destination_array = dimension2
}
}
}
在我的情况下，我创建了一个NSDictionary称为appSettings并添加所有需要的键。对于这种情况，解决方案是:
if let dict = NSBundle.mainBundle().objectForInfoDictionaryKey("appSettings") {
if let configAppToken = dict["myKeyInsideAppSettings"] as? String {
}
}
在swift 3.0从Plist读取。
func readPropertyList() {
var propertyListFormat = PropertyListSerialization.PropertyListFormat.xml //Format of the Property List.
var plistData: [String: AnyObject] = [:] //Our data
let plistPath: String? = Bundle.main.path(forResource: "data", ofType: "plist")! //the path of the data
let plistXML = FileManager.default.contents(atPath: plistPath!)!
do {//convert the data to a dictionary and handle errors.
plistData = try PropertyListSerialization.propertyList(from: plistXML, options: .mutableContainersAndLeaves, format: &propertyListFormat) as! [String:AnyObject]
} catch {
print("Error reading plist: \(error), format: \(propertyListFormat)")
}
}
阅读更多 如何在swift中使用属性列表(. plist)。
通过尼克的回答转换成一个方便的扩展:
extension Dictionary {
static func contentsOf(path: URL) -> Dictionary<String, AnyObject> {
let data = try! Data(contentsOf: path)
let plist = try! PropertyListSerialization.propertyList(from: data, options: .mutableContainers, format: nil)
return plist as! [String: AnyObject]
}
}
用法:
let path = Bundle.main.path(forResource: "plistName", ofType: "plist")!
let url = URL(fileURLWithPath: path)
let dict = Dictionary<String, AnyObject>.contentsOf(path: url)
我敢打赌，它也可以为数组创建类似的扩展
