我使用的是Json。将类序列化为JSON。
我的课程是这样的:
class Test1
{
[JsonProperty("id")]
public string ID { get; set; }
[JsonProperty("label")]
public string Label { get; set; }
[JsonProperty("url")]
public string URL { get; set; }
[JsonProperty("item")]
public List<Test2> Test2List { get; set; }
}
我想仅当Test2List为空时才向Test2List属性添加JsonIgnore()属性。如果它不是空的，那么我想包括它在我的json。
当前回答
在我的情况下，使用。net 6这是解决方案:
[JsonIgnore(Condition = JsonIgnoreCondition.WhenWritingNull)]
更多信息请点击这里。
其他回答
JSON。NET也尊重DataMemberAttribute上的EmitDefaultValue属性，以防你不想将newtonsoft特定的属性添加到你的模型中:
[DataMember(Name="property_name", EmitDefaultValue=false)]
使用JsonProperty属性的替代解决方案:
[JsonProperty(NullValueHandling=NullValueHandling.Ignore)]
// or
[JsonProperty("property_name", NullValueHandling=NullValueHandling.Ignore)]
// or for all properties in a class
[JsonObject(ItemNullValueHandling = NullValueHandling.Ignore)]
在这个在线文档中可以看到。
@Mrchief / @amit的答案的改编，但适用于使用VB的人
Dim JSONOut As String = JsonConvert.SerializeObject(
myContainerObject,
New JsonSerializerSettings With {
.NullValueHandling = NullValueHandling.Ignore
}
)
看到的: 对象初始化器:命名和匿名类型(Visual Basic)
https://msdn.microsoft.com/en-us/library/bb385125.aspx
这里有一个类似的选项，但提供了另一种选择:
public class DefaultJsonSerializer : JsonSerializerSettings
{
public DefaultJsonSerializer()
{
NullValueHandling = NullValueHandling.Ignore;
}
}
然后，我这样使用它:
JsonConvert.SerializeObject(postObj, new DefaultJsonSerializer());
不同之处在于:
Reduces repeated code by instantiating and configuring JsonSerializerSettings each place it's used. Saves time in configuring every property of every object to be serialized. Still gives other developers flexibility in serialization options, rather than having the property explicitly specified on a reusable object. My use-case is that the code is a 3rd party library and I don't want to force serialization options on developers who would want to reuse my classes. Potential drawbacks are that it's another object that other developers would need to know about, or if your application is small and this approach wouldn't matter for a single serialization.
与Json。网
public class Movie
{
public string Name { get; set; }
public string Description { get; set; }
public string Classification { get; set; }
public string Studio { get; set; }
public DateTime? ReleaseDate { get; set; }
public List<string> ReleaseCountries { get; set; }
}
Movie movie = new Movie();
movie.Name = "Bad Boys III";
movie.Description = "It's no Bad Boys";
string ignored = JsonConvert.SerializeObject(movie,
Formatting.Indented,
new JsonSerializerSettings { NullValueHandling = NullValueHandling.Ignore });
结果将是:
{
"Name": "Bad Boys III",
"Description": "It's no Bad Boys"
}
