系统。Json现在工作了…

安装 nuget https://www.nuget.org/packages/System.Json

PM> Install-Package System.Json -Version 4.5.0

示例:

// PM>Install-Package System.Json -Version 4.5.0

using System;
using System.Json;

namespace NetCoreTestConsoleApp
{
    class Program
    {
        static void Main(string[] args)
        {
            // Note that JSON keys are case sensitive, a is not same as A.

            // JSON Sample
            string jsonString = "{\"a\": 1,\"b\": \"string value\",\"c\":[{\"Value\": 1}, {\"Value\": 2,\"SubObject\":[{\"SubValue\":3}]}]}";

            // You can use the following line in a beautifier/JSON formatted for better view
            // {"a": 1,"b": "string value","c":[{"Value": 1}, {"Value": 2,"SubObject":[{"SubValue":3}]}]}

            /* Formatted jsonString for viewing purposes:
            {
               "a":1,
               "b":"string value",
               "c":[
                  {
                     "Value":1
                  },
                  {
                     "Value":2,
                     "SubObject":[
                        {
                           "SubValue":3
                        }
                     ]
                  }
               ]
            }
            */

            // Verify your JSON if you get any errors here
            JsonValue json = JsonValue.Parse(jsonString);

            // int test
            if (json.ContainsKey("a"))
            {
                int a = json["a"]; // type already set to int
                Console.WriteLine("json[\"a\"]" + " = " + a);
            }

            // string test
            if (json.ContainsKey("b"))
            {
                string b = json["b"];  // type already set to string
                Console.WriteLine("json[\"b\"]" + " = " + b);
            }

            // object array test
            if (json.ContainsKey("c") && json["c"].JsonType == JsonType.Array)
            {
                // foreach loop test
                foreach (JsonValue j in json["c"])
                {
                    Console.WriteLine("j[\"Value\"]" + " = " + j["Value"].ToString());
                }

                // multi level key test
                Console.WriteLine("json[\"c\"][0][\"Value\"]" + " = " + json["c"][0]["Value"].ToString());
                Console.WriteLine("json[\"c\"][0][\"Value\"]" + " = " + json["c"][1]["Value"].ToString());
                Console.WriteLine("json[\"c\"][1][\"SubObject\"][0][\"SubValue\"]" + " = " + json["c"][1]["SubObject"][0]["SubValue"].ToString());
            }

            Console.WriteLine();
            Console.Write("Press any key to exit.");
            Console.ReadKey();
        }
    }
}

如果JSON是动态的，如下所示

{
 "Items": [{
        "Name": "Apple",
        "Price": 12.3
    },
    {
        "Name": "Grape",
        "Price": 3.21
    }
   ],
   "Date": "21/11/2010"
}

然后，一旦你安装了NewtonSoft。Json从NuGet和包括它在你的项目，你可以序列化它为

string jsonString = "{\"Items\": [{\"Name\": \"Apple\",\"Price\": 12.3},{\"Name\": \"Grape\",\"Price\": 3.21}],\"Date\": \"21/11/2010\"}";

        dynamic DynamicData = JsonConvert.DeserializeObject(jsonString);

        Console.WriteLine(   DynamicData.Date); // "21/11/2010"
        Console.WriteLine(DynamicData.Items.Count); // 2
        Console.WriteLine(DynamicData.Items[0].Name); // "Apple"

来源:如何在c#中读取JSON数据(使用控制台应用程序和ASP的例子)。净MVC) ?

使用这个工具在json中生成一个类:

http://json2csharp.com/

然后使用类来反序列化json。例子:

public class Account
{
    public string Email { get; set; }
    public bool Active { get; set; }
    public DateTime CreatedDate { get; set; }
    public IList<string> Roles { get; set; }
}


string json = @"{
  'Email': 'james@example.com',
  'Active': true,
  'CreatedDate': '2013-01-20T00:00:00Z',
  'Roles': [
    'User',
    'Admin'
  ]
}";

Account account = JsonConvert.DeserializeObject<Account>(json);

Console.WriteLine(account.Email);
// james@example.com

引用: https://forums.asp.net/t/1992996.aspx?Nested+Json+Deserialization+to+C+object+and+using+that+object https://www.newtonsoft.com/json/help/html/DeserializeObject.htm

var result = controller.ActioName(objParams);
IDictionary<string, object> data = (IDictionary<string, object>)new System.Web.Routing.RouteValueDictionary(result.Data);
Assert.AreEqual("Table already exists.", data["Message"]);

正如这里的回答-反序列化JSON到c#动态对象?

使用Json非常简单。NET:

dynamic stuff = JsonConvert.DeserializeObject("{ 'Name': 'Jon Smith', 'Address': { 'City': 'New York', 'State': 'NY' }, 'Age': 42 }");

string name = stuff.Name;
string address = stuff.Address.City;

或者使用Newtonsoft.Json.Linq:

dynamic stuff = JObject.Parse("{ 'Name': 'Jon Smith', 'Address': { 'City': 'New York', 'State': 'NY' }, 'Age': 42 }");

string name = stuff.Name;
string address = stuff.Address.City;

我假设你没有使用Json。净(Newtonsoft。Json NuGet包)。如果是这样的话，你应该试试。

它具有以下特点:

LINQ到JSON JsonSerializer用于快速将.NET对象转换为JSON并再转换回来 Json。NET可以选择生成格式良好、缩进的JSON以供调试或显示 可以将JsonIgnore和JsonProperty等属性添加到类中，以自定义类的序列化方式 能够将JSON转换为XML 支持多种平台:.NET、Silverlight和Compact Framework

请看下面的例子。在本例中，JsonConvert类用于将对象与JSON进行转换。它有两个用于此目的的静态方法。它们是SerializeObject(Object obj)和DeserializeObject<T>(String json):

using Newtonsoft.Json;

Product product = new Product();
product.Name = "Apple";
product.Expiry = new DateTime(2008, 12, 28);
product.Price = 3.99M;
product.Sizes = new string[] { "Small", "Medium", "Large" };

string json = JsonConvert.SerializeObject(product);
//{
//  "Name": "Apple",
//  "Expiry": "2008-12-28T00:00:00",
//  "Price": 3.99,
//  "Sizes": [
//    "Small",
//    "Medium",
//    "Large"
//  ]
//}

Product deserializedProduct = JsonConvert.DeserializeObject<Product>(json);