我有以下代码:
var user = (Dictionary<string, object>)serializer.DeserializeObject(responsecontent);
responsecontent中的输入是JSON,但它没有正确地反序列化为对象。我应该如何正确地反序列化它?
我有以下代码:
var user = (Dictionary<string, object>)serializer.DeserializeObject(responsecontent);
responsecontent中的输入是JSON,但它没有正确地反序列化为对象。我应该如何正确地反序列化它?
当前回答
我认为我所见过的最好的回答是@MD_Sayem_Ahmed。
你的问题是“如何用c#解析Json”,但看起来你想解码Json。如果你想要解读它,艾哈迈德的答案很好。
如果您试图在ASP中完成此任务。NET Web Api,最简单的方法是创建一个数据传输对象,其中包含你想要分配的数据:
public class MyDto{
public string Name{get; set;}
public string Value{get; set;}
}
您只需将application/json头添加到您的请求(例如,如果您使用Fiddler)。 然后在ASP中使用它。NET Web API如下:
//controller method -- assuming you want to post and return data
public MyDto Post([FromBody] MyDto myDto){
MyDto someDto = myDto;
/*ASP.NET automatically converts the data for you into this object
if you post a json object as follows:
{
"Name": "SomeName",
"Value": "SomeValue"
}
*/
//do some stuff
}
这在我开发Web Api时给了我很大的帮助,使我的生活变得超级简单。
其他回答
using (var ms = new MemoryStream(Encoding.Unicode.GetBytes(user)))
{
// Deserialization from JSON
DataContractJsonSerializer deserializer = new DataContractJsonSerializer(typeof(UserListing))
DataContractJsonSerializer(typeof(UserListing));
UserListing response = (UserListing)deserializer.ReadObject(ms);
}
public class UserListing
{
public List<UserList> users { get; set; }
}
public class UserList
{
public string FirstName { get; set; }
public string LastName { get; set; }
}
string json = @"{
'Name': 'Wide Web',
'Url': 'www.wideweb.com.br'}";
JavaScriptSerializer jsonSerializer = new JavaScriptSerializer();
dynamic j = jsonSerializer.Deserialize<dynamic>(json);
string name = j["Name"].ToString();
string url = j["Url"].ToString();
试试下面的代码:
HttpWebRequest request = (HttpWebRequest)WebRequest.Create("URL");
JArray array = new JArray();
using (var twitpicResponse = (HttpWebResponse)request.GetResponse())
using (var reader = new StreamReader(twitpicResponse.GetResponseStream()))
{
JavaScriptSerializer js = new JavaScriptSerializer();
var objText = reader.ReadToEnd();
JObject joResponse = JObject.Parse(objText);
JObject result = (JObject)joResponse["result"];
array = (JArray)result["Detail"];
string statu = array[0]["dlrStat"].ToString();
}
这里有一些不使用第三方库的选项:
// For that you will need to add reference to System.Runtime.Serialization
var jsonReader = JsonReaderWriterFactory.CreateJsonReader(Encoding.UTF8.GetBytes(@"{ ""Name"": ""Jon Smith"", ""Address"": { ""City"": ""New York"", ""State"": ""NY"" }, ""Age"": 42 }"), new System.Xml.XmlDictionaryReaderQuotas());
// For that you will need to add reference to System.Xml and System.Xml.Linq
var root = XElement.Load(jsonReader);
Console.WriteLine(root.XPathSelectElement("//Name").Value);
Console.WriteLine(root.XPathSelectElement("//Address/State").Value);
// For that you will need to add reference to System.Web.Helpers
dynamic json = System.Web.Helpers.Json.Decode(@"{ ""Name"": ""Jon Smith"", ""Address"": { ""City"": ""New York"", ""State"": ""NY"" }, ""Age"": 42 }");
Console.WriteLine(json.Name);
Console.WriteLine(json.Address.State);
有关System.Web.Helpers.Json的更多信息,请参阅链接。
更新:现在最简单的上网方式。helper是使用NuGet包的。
如果你不关心早期的windows版本,你可以使用windows . data . json命名空间的类:
// minimum supported version: Win 8
JsonObject root = Windows.Data.Json.JsonValue.Parse(jsonString).GetObject();
Console.WriteLine(root["Name"].GetString());
Console.WriteLine(root["Address"].GetObject()["State"].GetString());
您可以使用以下扩展
public static class JsonExtensions
{
public static T ToObject<T>(this string jsonText)
{
return JsonConvert.DeserializeObject<T>(jsonText);
}
public static string ToJson<T>(this T obj)
{
return JsonConvert.SerializeObject(obj);
}
}