我翻遍了苹果的iBook,找不到任何关于它的定义:

有人能解释一下dispatch_after的结构吗?

dispatch_after(<#when: dispatch_time_t#>, <#queue: dispatch_queue_t?#>, <#block: dispatch_block_t?#>)

当前回答

dispatch_after(dispatch_time(DISPATCH_TIME_NOW, (int64_t)(10 * NSEC_PER_SEC)), dispatch_get_main_queue(), ^{
    // ...
});

dispatch_after(_:_:_:)函数有三个参数:

延迟 调度队列 块或闭包

dispatch_after(_:_:_:)函数调用在给定延迟后传递给函数的调度队列上的块或闭包。注意,延迟是使用dispatch_time(_:_:)函数创建的。记住这一点,因为我们在Swift中也使用了这个函数。

我建议你通过Raywenderlich调度教程

其他回答

我总是喜欢使用扩展而不是自由函数。

斯威夫特4

public extension DispatchQueue {

  private class func delay(delay: TimeInterval, closure: @escaping () -> Void) {
    let when = DispatchTime.now() + delay
    DispatchQueue.main.asyncAfter(deadline: when, execute: closure)
  }

  class func performAction(after seconds: TimeInterval, callBack: @escaping (() -> Void) ) {
    DispatchQueue.delay(delay: seconds) {
      callBack()
    }
  }

}

按以下方法使用。

DispatchQueue.performAction(after: 0.3) {
  // Code Here
}

Apple为Objective-C提供了dispatch_after代码段:

dispatch_after(dispatch_time(DISPATCH_TIME_NOW, (int64_t)(<#delayInSeconds#> * NSEC_PER_SEC)), dispatch_get_main_queue(), ^{
    <#code to be executed after a specified delay#>
});

以下是移植到Swift 3的相同代码片段:

DispatchQueue.main.asyncAfter(deadline: DispatchTime.now() + <#delayInSeconds#>) {
  <#code to be executed after a specified delay#>
}

对于多个函数使用这个。这对于静态函数或任何UI更新使用动画或活动加载器非常有帮助。

DispatchQueue.main.asyncAfter(deadline: .now() + 0.9) {
            // Call your function 1
            DispatchQueue.main.asyncAfter(deadline: .now() + 0.5) {
                // Call your function 2
            }
        }

例如-在tableView重新加载之前使用动画。或任何其他UI更新后的动画。

*// Start your amination* 
self.startAnimation()
DispatchQueue.main.asyncAfter(deadline: .now() + 0.9) {
                *// The animation will execute depending on the delay time*
                self.stopAnimation()
                DispatchQueue.main.asyncAfter(deadline: .now() + 0.5) {
                    *// Now update your view*
                     self.fetchData()
                     self.updateUI()
                }
            }

Matt的语法非常好,如果你需要使块失效,你可能想使用这个:

typealias dispatch_cancelable_closure = (cancel : Bool) -> Void

func delay(time:NSTimeInterval, closure:()->Void) ->  dispatch_cancelable_closure? {

    func dispatch_later(clsr:()->Void) {
        dispatch_after(
            dispatch_time(
                DISPATCH_TIME_NOW,
                Int64(time * Double(NSEC_PER_SEC))
            ),
            dispatch_get_main_queue(), clsr)
    }

    var closure:dispatch_block_t? = closure
    var cancelableClosure:dispatch_cancelable_closure?

    let delayedClosure:dispatch_cancelable_closure = { cancel in
        if closure != nil {
            if (cancel == false) {
                dispatch_async(dispatch_get_main_queue(), closure!);
            }
        }
        closure = nil
        cancelableClosure = nil
    }

    cancelableClosure = delayedClosure

    dispatch_later {
        if let delayedClosure = cancelableClosure {
            delayedClosure(cancel: false)
        }
    }

    return cancelableClosure;
}

func cancel_delay(closure:dispatch_cancelable_closure?) {

    if closure != nil {
        closure!(cancel: true)
    }
}

使用方法如下

let retVal = delay(2.0) {
    println("Later")
}
delay(1.0) {
    cancel_delay(retVal)
}

学分

上面的链接似乎坏了。来自Github的原始Objc代码

Swift 3.0 & Swift 4.0 & Swift 5.0中最简单的解决方案

func delayWithSeconds(_ seconds: Double, completion: @escaping () -> ()) {
    DispatchQueue.main.asyncAfter(deadline: .now() + seconds) { 
        completion()
    }
}

使用

delayWithSeconds(1) {
   //Do something
}