我有一个类似的问题与WPF应用程序，从访问应用程序通过Shell对象调用。

我的解决方案如下-工作在XP和Win7 x64应用程序编译到x86目标。

我宁愿这样做，而不是模拟一个alt选项卡。

void Window_Loaded(object sender, RoutedEventArgs e)
{
    // make sure the window is normal or maximised
    // this was the core of the problem for me;
    // even though the default was "Normal", starting it via shell minimised it
    this.WindowState = WindowState.Normal;

    // only required for some scenarios
    this.Activate();
}

既然这是个热门话题…以下是对我有效的方法。如果我不这样做，我就会得到错误，因为如果你看不到窗口，Activate()就会出错。

Xaml:

<Window .... 
        Topmost="True" 
        .... 
        ContentRendered="mainWindow_ContentRendered"> .... </Window>

后台代码:

private void mainWindow_ContentRendered(object sender, EventArgs e)
{
    this.Topmost = false;
    this.Activate();
    _UsernameTextBox.Focus();
}

这是唯一能让窗口在顶部显示的方法。然后激活它，这样你就可以在框中输入，而不必用鼠标设置焦点。control.Focus()不会工作，除非窗口是Active();

让这个快速复制粘贴- 使用这个类的DoOnProcess方法将进程的主窗口移动到前台(但不是从其他窗口窃取焦点)

public class MoveToForeground
{
    [DllImportAttribute("User32.dll")]
    private static extern int FindWindow(String ClassName, String WindowName);

    const int SWP_NOMOVE        = 0x0002;
    const int SWP_NOSIZE        = 0x0001;            
    const int SWP_SHOWWINDOW    = 0x0040;
    const int SWP_NOACTIVATE    = 0x0010;
    [DllImport("user32.dll", EntryPoint = "SetWindowPos")]
    public static extern IntPtr SetWindowPos(IntPtr hWnd, int hWndInsertAfter, int x, int Y, int cx, int cy, int wFlags);

    public static void DoOnProcess(string processName)
    {
        var allProcs = Process.GetProcessesByName(processName);
        if (allProcs.Length > 0)
        {
            Process proc = allProcs[0];
            int hWnd = FindWindow(null, proc.MainWindowTitle.ToString());
            // Change behavior by settings the wFlags params. See http://msdn.microsoft.com/en-us/library/ms633545(VS.85).aspx
            SetWindowPos(new IntPtr(hWnd), 0, 0, 0, 0, 0, SWP_NOMOVE | SWP_NOSIZE | SWP_SHOWWINDOW | SWP_NOACTIVATE);
        }
    }
}

HTH

只是想给这个问题加上一个解。这个实现适用于我的场景，其中CaliBurn负责显示主窗口。

protected override void OnStartup(object sender, StartupEventArgs e)
{
    DisplayRootViewFor<IMainWindowViewModel>();

    Application.MainWindow.Topmost = true;
    Application.MainWindow.Activate();
    Application.MainWindow.Activated += OnMainWindowActivated;
}

private static void OnMainWindowActivated(object sender, EventArgs e)
{
    var window = sender as Window;
    if (window != null)
    {
        window.Activated -= OnMainWindowActivated;
        window.Topmost = false;
        window.Focus();
    }
}

这些代码在任何时候都能正常工作。

首先在XAML中设置激活事件处理器:

Activated="Window_Activated"

在主窗口构造函数块中添加以下行:

public MainWindow()
{
    InitializeComponent();
    this.LocationChanged += (sender, e) => this.Window_Activated(sender, e);
}

并在激活事件处理程序中复制以下代码:

private void Window_Activated(object sender, EventArgs e)
{
    if (Application.Current.Windows.Count > 1)
    {
        foreach (Window win in Application.Current.Windows)
            try
            {
                if (!win.Equals(this))
                {
                    if (!win.IsVisible)
                    {
                        win.ShowDialog();
                    }

                    if (win.WindowState == WindowState.Minimized)
                    {
                        win.WindowState = WindowState.Normal;
                    }

                    win.Activate();
                    win.Topmost = true;
                    win.Topmost = false;
                    win.Focus();
                }
            }
            catch { }
    }
    else
        this.Focus();
}

这些步骤将工作良好，并将前面所有其他窗口进入他们的父母窗口。

如果你需要窗口在第一次加载时在前面，那么你应该使用以下方法:

private void Window_ContentRendered(object sender, EventArgs e)
{
    this.Topmost = false;
}

private void Window_Initialized(object sender, EventArgs e)
{
    this.Topmost = true;
}

或者重写方法:

protected override void OnContentRendered(EventArgs e)
{
    base.OnContentRendered(e);
    Topmost = false;
}

protected override void OnInitialized(EventArgs e)
{
    base.OnInitialized(e);
    Topmost = true;
}