任务:打印从1到1000的数字,不使用任何循环或条件语句。不要只写printf()或cout语句1000次。
用C或c++怎么做呢?
任务:打印从1到1000的数字,不使用任何循环或条件语句。不要只写printf()或cout语句1000次。
用C或c++怎么做呢?
当前回答
下面是一个使用setjmp/longjmp的版本,因为必须有人这样做:
#include <stdio.h>
#include <stdlib.h>
#include <setjmp.h>
void print(int i) {
printf("%d\n", i);
}
typedef void (*func_t)(int);
int main() {
jmp_buf buf;
func_t f[] = {print, exit};
int i = setjmp(buf)+1;
f[i/1001](i);
longjmp(buf, i);
return 0;
}
其他回答
也可以通过简单的动态调度来实现(在Java中也适用):
#include<iostream>
using namespace std;
class U {
public:
virtual U* a(U* x) = 0;
virtual void p(int i) = 0;
static U* t(U* x) { return x->a(x->a(x->a(x))); }
};
class S : public U {
public:
U* h;
S(U* h) : h(h) {}
virtual U* a(U* x) { return new S(new S(new S(h->a(x)))); }
virtual void p(int i) { cout << i << endl; h->p(i+1); }
};
class Z : public U {
public:
virtual U* a(U* x) { return x; }
virtual void p(int i) {}
};
int main(int argc, char** argv) {
U::t(U::t(U::t(new S(new Z()))))->p(1);
}
将1到1000放入文件file中
int main()
{
system("cat file");
return 0;
}
只需使用std::copy()和一个特殊的迭代器。
#include <algorithm>
#include <iostream>
#include <iterator>
struct number_iterator
{
typedef std::input_iterator_tag iterator_category;
typedef int value_type;
typedef std::size_t difference_type;
typedef int* pointer;
typedef int& reference;
number_iterator(int v): value(v) {}
bool operator != (number_iterator const& rhs) { return value != rhs.value;}
number_iterator operator++() { ++value; return *this;}
int operator*() { return value; }
int value;
};
int main()
{
std::copy(number_iterator(1),
number_iterator(1001),
std::ostream_iterator<int>(std::cout, " "));
}
如果POSIX解决方案被接受:
#include <stdio.h>
#include <signal.h>
#include <stdlib.h>
#include <sys/time.h>
#include <pthread.h>
static void die(int sig) {
exit(0);
}
static void wakeup(int sig) {
static int counter = 1;
struct itimerval timer;
float i = 1000 / (1000 - counter);
printf("%d\n", counter++);
timer.it_interval.tv_sec = 0;
timer.it_interval.tv_usec = 0;
timer.it_value.tv_sec = 0;
timer.it_value.tv_usec = i; /* Avoid code elimination */
setitimer(ITIMER_REAL, &timer, 0);
}
int main() {
pthread_mutex_t mutex = PTHREAD_MUTEX_INITIALIZER;
signal(SIGFPE, die);
signal(SIGALRM, wakeup);
wakeup(0);
pthread_mutex_lock(&mutex);
pthread_mutex_lock(&mutex); /* Deadlock, YAY! */
return 0;
}
#include <stdio.h>
#define Out(i) printf("%d\n", i++);
#define REP(N) N N N N N N N N N N
#define Out1000(i) REP(REP(REP(Out(i))));
void main()
{
int i = 1;
Out1000(i);
}