其实有一种更短更容易理解的方法。

为什么不直接分拆加入呢?

"s t r i n g".split(" ").join()

我个人倾向于使用.tr方法

如:

string = "this is a string to smash together"

string.tr(' ', '') # => "thisisastringtosmashtogether"

感谢@FrankScmitt指出，要删除所有空白(不仅仅是空格)，你需要这样写:

string = "this is a string with tabs\t and a \nnewline"

string.tr(" \n\t", '') # => "thisisastringwithtabsandanewline"

Ruby的.strip方法执行与trim()相当的PHP功能。

删除所有空白:

"  leading    trailing   ".squeeze(' ').strip
=> "leading trailing"

@塔斯让我意识到我原来的答案连续删除重复的字母-恶心!从那以后，我改用了压缩方法，如果使用Rails框架，这种方法对这种情况更聪明。

require 'active_support/all'
"  leading    trailing   ".squish
=> "leading trailing"

"  good    men   ".squish
=> "good men"

引用:http://apidock.com/rails/String/squish

我会用这样的方法:

my_string = "Foo bar\nbaz quux"

my_string.split.join
=> "Foobarbazquux"

使用gsub或delete。区别在于gsub可以删除制表符，而delete不能。有时文件中确实有编辑器添加的选项卡。

a = "\tI have some whitespaces.\t"
a.gsub!(/\s/, '')  #=>  "Ihavesomewhitespaces."
a.gsub!(/ /, '')   #=>  "\tIhavesomewhitespaces.\t"
a.delete!(" ")     #=>  "\tIhavesomewhitespaces.\t"
a.delete!("/\s/")  #=>  "\tIhavesomewhitespaces.\t"
a.delete!('/\s/')  #=>  using single quote is unexpected, and you'll get "\tI have ome whitepace.\t"

s = "I have white space".delete(' ')

并模拟PHP的trim()函数:

s = "   I have leading and trailing white space   ".strip