去除所有空白的Ruby函数是什么?我正在寻找一些类似于PHP的trim()?


当前回答

"1232 23 2 23 232 232".delete(' ')
=> "123223223232232"

删除工作更快=)

user         system     total      real
gsub, s      0.180000   0.010000   0.190000 (0.193014)
gsub, s+     0.200000   0.000000   0.200000 (0.196408)
gsub, space  0.220000   0.000000   0.220000 (0.222711)
gsub, join   0.200000   0.000000   0.200000 (0.193478)
delete       0.040000   0.000000   0.040000 (0.045157)

其他回答

我试图这样做,因为我想使用记录“标题”作为视图中的id,但标题有空格。

解决方案是:

record.value.delete(' ') # Foo Bar -> FooBar

gsub方法就可以了。 gsub方法可以在字符串上调用,并说:

a = "this is a string"
a = a.gsub(" ","")
puts a
#Output: thisisastring

gsub方法搜索第一个参数的每一次出现 然后用第二个参数替换它。在这种情况下,它将替换字符串中的每个空格并删除它。

另一个例子:

b = "the white fox has a torn tail"

我们把所有出现的字母t都换成大写的t

b = b.gsub("t","T")
puts b 
#Output: The whiTe fox has a Torn Tail
s = "I have white space".delete(' ')

并模拟PHP的trim()函数:

s = "   I have leading and trailing white space   ".strip

使用gsub或delete。区别在于gsub可以删除制表符,而delete不能。有时文件中确实有编辑器添加的选项卡。

a = "\tI have some whitespaces.\t"
a.gsub!(/\s/, '')  #=>  "Ihavesomewhitespaces."
a.gsub!(/ /, '')   #=>  "\tIhavesomewhitespaces.\t"
a.delete!(" ")     #=>  "\tIhavesomewhitespaces.\t"
a.delete!("/\s/")  #=>  "\tIhavesomewhitespaces.\t"
a.delete!('/\s/')  #=>  using single quote is unexpected, and you'll get "\tI have ome whitepace.\t"
"1232 23 2 23 232 232".delete(' ')
=> "123223223232232"

删除工作更快=)

user         system     total      real
gsub, s      0.180000   0.010000   0.190000 (0.193014)
gsub, s+     0.200000   0.000000   0.200000 (0.196408)
gsub, space  0.220000   0.000000   0.220000 (0.222711)
gsub, join   0.200000   0.000000   0.200000 (0.193478)
delete       0.040000   0.000000   0.040000 (0.045157)