是否有一种方法可以方便地在Python中定义类c结构?我厌倦了写这样的东西:
class MyStruct():
def __init__(self, field1, field2, field3):
self.field1 = field1
self.field2 = field2
self.field3 = field3
是否有一种方法可以方便地在Python中定义类c结构?我厌倦了写这样的东西:
class MyStruct():
def __init__(self, field1, field2, field3):
self.field1 = field1
self.field2 = field2
self.field3 = field3
当前回答
还可以按位置将初始化参数传递给实例变量
# Abstract struct class
class Struct:
def __init__ (self, *argv, **argd):
if len(argd):
# Update by dictionary
self.__dict__.update (argd)
else:
# Update by position
attrs = filter (lambda x: x[0:2] != "__", dir(self))
for n in range(len(argv)):
setattr(self, attrs[n], argv[n])
# Specific class
class Point3dStruct (Struct):
x = 0
y = 0
z = 0
pt1 = Point3dStruct()
pt1.x = 10
print pt1.x
print "-"*10
pt2 = Point3dStruct(5, 6)
print pt2.x, pt2.y
print "-"*10
pt3 = Point3dStruct (x=1, y=2, z=3)
print pt3.x, pt3.y, pt3.z
print "-"*10
其他回答
你可以通过以下方式在python中访问C-Style struct。
class cstruct:
var_i = 0
var_f = 0.0
var_str = ""
如果你只想使用cstruct的对象
obj = cstruct()
obj.var_i = 50
obj.var_f = 50.00
obj.var_str = "fifty"
print "cstruct: obj i=%d f=%f s=%s" %(obj.var_i, obj.var_f, obj.var_str)
如果你想创建一个cstruct对象的数组
obj_array = [cstruct() for i in range(10)]
obj_array[0].var_i = 10
obj_array[0].var_f = 10.00
obj_array[0].var_str = "ten"
#go ahead and fill rest of array instaces of struct
#print all the value
for i in range(10):
print "cstruct: obj_array i=%d f=%f s=%s" %(obj_array[i].var_i, obj_array[i].var_f, obj_array[i].var_str)
注意: 请使用你的struct名称,而不是'cstruct'名称 请定义结构的成员变量,而不是var_i, var_f, var_str。
我在这里没有看到这个答案,所以我想我将添加它,因为我现在正在学习Python,并且刚刚发现它。Python教程(在本例中是Python 2)给出了以下简单而有效的示例:
class Employee:
pass
john = Employee() # Create an empty employee record
# Fill the fields of the record
john.name = 'John Doe'
john.dept = 'computer lab'
john.salary = 1000
也就是说,创建一个空类对象,然后实例化,动态添加字段。
这样做的好处是非常简单。缺点是它不是特别自记录的(在类“定义”中没有列出预期的成员),并且未设置字段在访问时可能会导致问题。这两个问题可以通过以下方法解决:
class Employee:
def __init__ (self):
self.name = None # or whatever
self.dept = None
self.salary = None
现在,您至少可以一目了然地看到程序将期望哪些字段。
两者都很容易打错别字,约翰。Slarly = 1000将成功。不过,它还是有效的。
我发现做到这一点的最好方法是使用自定义字典类,如本文所述:https://stackoverflow.com/a/14620633/8484485
如果需要iPython自动补全支持,只需像这样定义dir()函数:
class AttrDict(dict):
def __init__(self, *args, **kwargs):
super(AttrDict, self).__init__(*args, **kwargs)
self.__dict__ = self
def __dir__(self):
return self.keys()
然后像这样定义你的伪结构(这个是嵌套的)
my_struct=AttrDict ({
'com1':AttrDict ({
'inst':[0x05],
'numbytes':2,
'canpayload':False,
'payload':None
})
})
然后你可以像这样访问my_struct中的值:
打印(my_struct.com1.inst)
= > [5]
我能想到的最干净的方法是使用一个类装饰器,它可以让你声明一个静态类,并将其重写为一个具有正常命名属性的结构体:
from as_struct import struct
@struct
class Product():
name = 'unknown product'
quantity = -1
sku = '-'
# create instance
p = Product('plush toy', sku='12-345-6789')
# check content:
p.name # plush toy
p.quantity # -1
p.sku # 12-345-6789
使用以下装饰器代码:
def struct(struct_class):
# create a new init
def struct_init(self, *args, **kwargs):
i = 0 # we really don't need enumerate() here...
for value in args:
name = member_names[i]
default_value = member_values[i]
setattr(self, name, value if value is not None else default_value)
i += 1 # ...we just need to inc an int
for key,value in kwargs.items():
i = member_names.index(key)
default_value = member_values[i]
setattr(self, key, value if value is not None else default_value)
# extract the struct members
member_names = []
member_values = []
for attr_name in dir(struct_class):
if not attr_name.startswith('_'):
value = getattr(struct_class, attr_name)
if not callable(value):
member_names.append(attr_name)
member_values.append(value)
# rebind and return
struct_class.init = struct_init
return struct_class
它的工作原理是获取类,提取字段名及其默认值,然后重写类的__init__函数,根据知道哪个参数索引映射到哪个属性名来设置self属性。
如果您没有3.7的@dataclass,并且需要可变性,那么下面的代码可能适合您。它是非常自文档化和ide友好的(自动完成),防止编写两次内容,易于扩展,并且非常简单地测试所有实例变量都被完全初始化:
class Params():
def __init__(self):
self.var1 : int = None
self.var2 : str = None
def are_all_defined(self):
for key, value in self.__dict__.items():
assert (value is not None), "instance variable {} is still None".format(key)
return True
params = Params()
params.var1 = 2
params.var2 = 'hello'
assert(params.are_all_defined)