你不能在一个PHP类中放入两个具有唯一参数签名的__construct函数。我想这样做:
class Student
{
protected $id;
protected $name;
// etc.
public function __construct($id){
$this->id = $id;
// other members are still uninitialized
}
public function __construct($row_from_database){
$this->id = $row_from_database->id;
$this->name = $row_from_database->name;
// etc.
}
}
PHP中最好的方法是什么?
当前回答
另一种选择是像这样在构造函数中使用默认参数
class Student {
private $id;
private $name;
//...
public function __construct($id, $row=array()) {
$this->id = $id;
foreach($row as $key => $value) $this->$key = $value;
}
}
这意味着你需要实例化一行像这样:$student = new student ($row['id']， $row)，但保持你的构造函数漂亮和干净。
另一方面，如果你想利用多态性，那么你可以创建两个类，像这样:
class Student {
public function __construct($row) {
foreach($row as $key => $value) $this->$key = $value;
}
}
class EmptyStudent extends Student {
public function __construct($id) {
parent::__construct(array('id' => $id));
}
}
其他回答
你可以这样做:
public function __construct($param)
{
if(is_int($param)) {
$this->id = $param;
} elseif(is_object($param)) {
// do something else
}
}
public function __construct() {
$parameters = func_get_args();
...
}
$o = new MyClass('One', 'Two', 3);
现在$ parameters将是一个值为'One'， 'Two'， 3的数组。
编辑,
我可以加上
func_num_args()
会给出函数的参数个数。
这是我对它的看法(为php 5.6构建)。
它将查看构造函数参数类型(数组，类名，无描述)并比较给定的参数。构造函数必须在最后以最少的特异性给出。例子:
// demo class
class X {
public $X;
public function __construct($x) {
$this->X = $x;
}
public function __toString() {
return 'X'.$this->X;
}
}
// demo class
class Y {
public $Y;
public function __construct($y) {
$this->Y = $y;
}
public function __toString() {
return 'Y'.$this->Y;
}
}
// here be magic
abstract class MultipleConstructors {
function __construct() {
$__get_arguments = func_get_args();
$__number_of_arguments = func_num_args();
$__reflect = new ReflectionClass($this);
foreach($__reflect->getMethods() as $__reflectmethod) {
$__method_name = $__reflectmethod->getName();
if (substr($__method_name, 0, strlen('__construct')) === '__construct') {
$__parms = $__reflectmethod->getParameters();
if (count($__parms) == $__number_of_arguments) {
$__argsFit = true;
foreach ($__parms as $__argPos => $__param) {
$__paramClass= $__param->getClass();
$__argVar = func_get_arg($__argPos);
$__argVarType = gettype($__argVar);
$__paramIsArray = $__param->isArray() == true;
$__argVarIsArray = $__argVarType == 'array';
// parameter is array and argument isn't, or the other way around.
if (($__paramIsArray && !$__argVarIsArray) ||
(!$__paramIsArray && $__argVarIsArray)) {
$__argsFit = false;
continue;
}
// class check
if ((!is_null($__paramClass) && $__argVarType != 'object') ||
(is_null($__paramClass) && $__argVarType == 'object')){
$__argsFit = false;
continue;
}
if (!is_null($__paramClass) && $__argVarType == 'object') {
// class type check
$__paramClassName = "N/A";
if ($__paramClass)
$__paramClassName = $__paramClass->getName();
if ($__paramClassName != get_class($__argVar)) {
$__argsFit = false;
}
}
}
if ($__argsFit) {
call_user_func_array(array($this, $__method_name), $__get_arguments);
return;
}
}
}
}
throw new Exception("No matching constructors");
}
}
// how to use multiple constructors
class A extends MultipleConstructors {
public $value;
function __constructB(array $hey) {
$this->value = 'Array#'.count($hey).'<br/>';
}
function __construct1(X $first) {
$this->value = $first .'<br/>';
}
function __construct2(Y $second) {
$this->value = $second .'<br/>';
}
function __constructA($hey) {
$this->value = $hey.'<br/>';
}
function __toString() {
return $this->value;
}
}
$x = new X("foo");
$y = new Y("bar");
$aa = new A(array("one", "two", "three"));
echo $aa;
$ar = new A("baz");
echo $ar;
$ax = new A($x);
echo $ax;
$ay = new A($y);
echo $ay;
结果:
Array#3
baz
Xfoo
Ybar
如果没有找到构造函数，可以将其删除并允许构造函数为“空”，而不是终止异常。或者你喜欢什么都行。
在创建具有不同签名的多个构造函数时，我也面临着同样的问题，但不幸的是，PHP没有提供直接的方法来这样做。然而，我发现了一个技巧来克服它。希望也适用于你们所有人。
<?PHP
class Animal
{
public function __construct()
{
$arguments = func_get_args();
$numberOfArguments = func_num_args();
if (method_exists($this, $function = '__construct'.$numberOfArguments)) {
call_user_func_array(array($this, $function), $arguments);
}
}
public function __construct1($a1)
{
echo('__construct with 1 param called: '.$a1.PHP_EOL);
}
public function __construct2($a1, $a2)
{
echo('__construct with 2 params called: '.$a1.','.$a2.PHP_EOL);
}
public function __construct3($a1, $a2, $a3)
{
echo('__construct with 3 params called: '.$a1.','.$a2.','.$a3.PHP_EOL);
}
}
$o = new Animal('sheep');
$o = new Animal('sheep','cat');
$o = new Animal('sheep','cat','dog');
// __construct with 1 param called: sheep
// __construct with 2 params called: sheep,cat
// __construct with 3 params called: sheep,cat,dog
让我在这里加一粒沙子
我个人喜欢将构造函数作为返回类(对象)实例的静态函数添加。代码示例如下:
class Person
{
private $name;
private $email;
public static function withName($name)
{
$person = new Person();
$person->name = $name;
return $person;
}
public static function withEmail($email)
{
$person = new Person();
$person->email = $email;
return $person;
}
}
注意，现在你可以像这样创建Person类的实例:
$person1 = Person::withName('Example');
$person2 = Person::withEmail('yo@mi_email.com');
我的代码来自:
http://alfonsojimenez.com/post/30377422731/multiple-constructors-in-php
