你不能在一个PHP类中放入两个具有唯一参数签名的__construct函数。我想这样做:
class Student
{
protected $id;
protected $name;
// etc.
public function __construct($id){
$this->id = $id;
// other members are still uninitialized
}
public function __construct($row_from_database){
$this->id = $row_from_database->id;
$this->name = $row_from_database->name;
// etc.
}
}
PHP中最好的方法是什么?
为了回应Kris的最佳答案(顺便说一句,他帮助我设计了自己的课程),这里有一个修改过的版本,供那些可能会觉得有用的人使用。包括用于从任何列中进行选择和从数组中转储对象数据的方法。干杯!
public function __construct() {
$this -> id = 0;
//...
}
public static function Exists($id) {
if (!$id) return false;
$id = (int)$id;
if ($id <= 0) return false;
$mysqli = Mysql::Connect();
if (mysqli_num_rows(mysqli_query($mysqli, "SELECT id FROM users WHERE id = " . $id)) == 1) return true;
return false;
}
public static function FromId($id) {
$u = new self();
if (!$u -> FillFromColumn("id", $id)) return false;
return $u;
}
public static function FromColumn($column, $value) {
$u = new self();
if (!$u -> FillFromColumn($column, $value)) return false;
return $u;
}
public static function FromArray($row = array()) {
if (!is_array($row) || $row == array()) return false;
$u = new self();
$u -> FillFromArray($row);
return $u;
}
protected function FillFromColumn($column, $value) {
$mysqli = Mysql::Connect();
//Assuming we're only allowed to specified EXISTENT columns
$result = mysqli_query($mysqli, "SELECT * FROM users WHERE " . $column . " = '" . $value . "'");
$count = mysqli_num_rows($result);
if ($count == 0) return false;
$row = mysqli_fetch_assoc($result);
$this -> FillFromArray($row);
}
protected function FillFromArray(array $row) {
foreach($row as $i => $v) {
if (isset($this -> $i)) {
$this -> $i = $v;
}
}
}
public function ToArray() {
$m = array();
foreach ($this as $i => $v) {
$m[$i] = $v;
}
return $m;
}
public function Dump() {
print_r("<PRE>");
print_r($this -> ToArray());
print_r("</PRE>");
}
Kris的回答很好,但正如Buttle Butku评论的那样,新的static()将在PHP 5.3+中被首选。
所以我会这样做(根据克里斯的回答修改):
<?php
class Student
{
public function __construct() {
// allocate your stuff
}
public static function withID( $id ) {
$instance = new static();
$instance->loadByID( $id );
return $instance;
}
public static function withRow( array $row ) {
$instance = new static();
$instance->fill( $row );
return $instance;
}
protected function loadByID( $id ) {
// do query
$row = my_awesome_db_access_stuff( $id );
$this->fill( $row );
}
protected function fill( array $row ) {
// fill all properties from array
}
}
?>
用法:
<?php
$student1 = Student::withID($id);
$student2 = Student::withRow($row);
?>
我还在php.net OOP文档中找到了一个有用的例子。
在创建具有不同签名的多个构造函数时,我也面临着同样的问题,但不幸的是,PHP没有提供直接的方法来这样做。然而,我发现了一个技巧来克服它。希望也适用于你们所有人。
<?PHP
class Animal
{
public function __construct()
{
$arguments = func_get_args();
$numberOfArguments = func_num_args();
if (method_exists($this, $function = '__construct'.$numberOfArguments)) {
call_user_func_array(array($this, $function), $arguments);
}
}
public function __construct1($a1)
{
echo('__construct with 1 param called: '.$a1.PHP_EOL);
}
public function __construct2($a1, $a2)
{
echo('__construct with 2 params called: '.$a1.','.$a2.PHP_EOL);
}
public function __construct3($a1, $a2, $a3)
{
echo('__construct with 3 params called: '.$a1.','.$a2.','.$a3.PHP_EOL);
}
}
$o = new Animal('sheep');
$o = new Animal('sheep','cat');
$o = new Animal('sheep','cat','dog');
// __construct with 1 param called: sheep
// __construct with 2 params called: sheep,cat
// __construct with 3 params called: sheep,cat,dog
从PHP 8开始,我们可以使用命名参数:
class Student {
protected int $id;
protected string $name;
public function __construct(int $id = null, string $name = null, array $row_from_database = null) {
if ($id !== null && $name !== null && $row_from_database === null) {
$this->id = $id;
$this->name = $name;
} elseif ($id === null && $name === null
&& $row_from_database !== null
&& array_keys($row_from_database) === [ 'id', 'name' ]
&& is_int($row_from_database['id'])
&& is_string($row_from_database['name'])) {
$this->id = $row_from_database['id'];
$this->name = $row_from_database['name'];
} else {
throw new InvalidArgumentException('Invalid arguments');
}
}
}
$student1 = new Student(id: 3, name: 'abc');
$student2 = new Student(row_from_database: [ 'id' => 4, 'name' => 'def' ]);
通过适当的检查,可以排除无效的参数组合,这样创建的实例在构造函数的末尾是一个有效的实例(但错误只会在运行时检测到)。