你不能在一个PHP类中放入两个具有唯一参数签名的__construct函数。我想这样做:

class Student 
{
   protected $id;
   protected $name;
   // etc.

   public function __construct($id){
       $this->id = $id;
      // other members are still uninitialized
   }

   public function __construct($row_from_database){
       $this->id = $row_from_database->id;
       $this->name = $row_from_database->name;
       // etc.
   }
}

PHP中最好的方法是什么?


当前回答

为了回应Kris的最佳答案(顺便说一句,他帮助我设计了自己的课程),这里有一个修改过的版本,供那些可能会觉得有用的人使用。包括用于从任何列中进行选择和从数组中转储对象数据的方法。干杯!

public function __construct() {
    $this -> id = 0;
    //...
}

public static function Exists($id) {
    if (!$id) return false;
    $id = (int)$id;
    if ($id <= 0) return false;
    $mysqli = Mysql::Connect();
    if (mysqli_num_rows(mysqli_query($mysqli, "SELECT id FROM users WHERE id = " . $id)) == 1) return true;
    return false;
}

public static function FromId($id) {
    $u = new self();
    if (!$u -> FillFromColumn("id", $id)) return false;
    return $u;
}

public static function FromColumn($column, $value) {
    $u = new self();
    if (!$u -> FillFromColumn($column, $value)) return false;
    return $u;
}

public static function FromArray($row = array()) {
    if (!is_array($row) || $row == array()) return false;
    $u = new self();
    $u -> FillFromArray($row);
    return $u;
}

protected function FillFromColumn($column, $value) {
    $mysqli = Mysql::Connect();
    //Assuming we're only allowed to specified EXISTENT columns
    $result = mysqli_query($mysqli, "SELECT * FROM users WHERE " . $column . " = '" . $value . "'");
    $count = mysqli_num_rows($result);
    if ($count == 0) return false;
    $row = mysqli_fetch_assoc($result);
    $this -> FillFromArray($row);
}

protected function FillFromArray(array $row) {
    foreach($row as $i => $v) {
        if (isset($this -> $i)) {
            $this -> $i = $v;
        }
    }
}

public function ToArray() {
    $m = array();
    foreach ($this as $i => $v) {
        $m[$i] = $v;    
    }
    return $m;
}

public function Dump() {
    print_r("<PRE>");
    print_r($this -> ToArray());
    print_r("</PRE>");  
}

其他回答

为了回应Kris的最佳答案(顺便说一句,他帮助我设计了自己的课程),这里有一个修改过的版本,供那些可能会觉得有用的人使用。包括用于从任何列中进行选择和从数组中转储对象数据的方法。干杯!

public function __construct() {
    $this -> id = 0;
    //...
}

public static function Exists($id) {
    if (!$id) return false;
    $id = (int)$id;
    if ($id <= 0) return false;
    $mysqli = Mysql::Connect();
    if (mysqli_num_rows(mysqli_query($mysqli, "SELECT id FROM users WHERE id = " . $id)) == 1) return true;
    return false;
}

public static function FromId($id) {
    $u = new self();
    if (!$u -> FillFromColumn("id", $id)) return false;
    return $u;
}

public static function FromColumn($column, $value) {
    $u = new self();
    if (!$u -> FillFromColumn($column, $value)) return false;
    return $u;
}

public static function FromArray($row = array()) {
    if (!is_array($row) || $row == array()) return false;
    $u = new self();
    $u -> FillFromArray($row);
    return $u;
}

protected function FillFromColumn($column, $value) {
    $mysqli = Mysql::Connect();
    //Assuming we're only allowed to specified EXISTENT columns
    $result = mysqli_query($mysqli, "SELECT * FROM users WHERE " . $column . " = '" . $value . "'");
    $count = mysqli_num_rows($result);
    if ($count == 0) return false;
    $row = mysqli_fetch_assoc($result);
    $this -> FillFromArray($row);
}

protected function FillFromArray(array $row) {
    foreach($row as $i => $v) {
        if (isset($this -> $i)) {
            $this -> $i = $v;
        }
    }
}

public function ToArray() {
    $m = array();
    foreach ($this as $i => $v) {
        $m[$i] = $v;    
    }
    return $m;
}

public function Dump() {
    print_r("<PRE>");
    print_r($this -> ToArray());
    print_r("</PRE>");  
}

PHP是一种动态语言,因此不能重载方法。你必须像这样检查参数的类型:

class Student 
{
   protected $id;
   protected $name;
   // etc.

   public function __construct($idOrRow){
    if(is_int($idOrRow))
    {
        $this->id = $idOrRow;
        // other members are still uninitialized
    }
    else if(is_array($idOrRow))
    {
       $this->id = $idOrRow->id;
       $this->name = $idOrRow->name;
       // etc.  
    }
}

Kris的回答很好,但正如Buttle Butku评论的那样,新的static()将在PHP 5.3+中被首选。

所以我会这样做(根据克里斯的回答修改):

<?php

class Student
{
    public function __construct() {
        // allocate your stuff
    }

    public static function withID( $id ) {
        $instance = new static();
        $instance->loadByID( $id );
        return $instance;
    }

    public static function withRow( array $row ) {
        $instance = new static();
        $instance->fill( $row );
        return $instance;
    }

    protected function loadByID( $id ) {
        // do query
        $row = my_awesome_db_access_stuff( $id );
        $this->fill( $row );
    }

    protected function fill( array $row ) {
        // fill all properties from array
    }
}

?>

用法:

<?php

$student1 = Student::withID($id);
$student2 = Student::withRow($row);

?>

我还在php.net OOP文档中找到了一个有用的例子。

我知道我在这方面非常晚,但我提出了一个相当灵活的模式,应该允许一些真正有趣和通用的实现。

像往常一样设置类,使用您喜欢的任何变量。

class MyClass{ protected $myVar1; protected $myVar2; public function __construct($obj = null){ if($obj){ foreach (((object)$obj) as $key => $value) { if(isset($value) && in_array($key, array_keys(get_object_vars($this)))){ $this->$key = $value; } } } } } When you make your object just pass an associative array with the keys of the array the same as the names of your vars, like so... $sample_variable = new MyClass([ 'myVar2'=>123, 'i_dont_want_this_one'=> 'This won\'t make it into the class' ]); print_r($sample_variable); The print_r($sample_variable); after this instantiation yields the following: MyClass Object ( [myVar1:protected] => [myVar2:protected] => 123 ) Because we've initialize $group to null in our __construct(...), it is also valid to pass nothing whatsoever into the constructor as well, like so... $sample_variable = new MyClass(); print_r($sample_variable); Now the output is exactly as expected: MyClass Object ( [myVar1:protected] => [myVar2:protected] => ) The reason I wrote this was so that I could directly pass the output of json_decode(...) to my constructor, and not worry about it too much. This was executed in PHP 7.1. Enjoy!

你总是可以在构造函数中添加一个额外的参数,比如mode,然后对它执行一个switch语句……

class myClass 
{
    var $error ;
    function __construct ( $data, $mode )
    {
        $this->error = false
        switch ( $mode )
        {
            'id' : processId ( $data ) ; break ;
            'row' : processRow ( $data ); break ;
            default : $this->error = true ; break ;
         }
     }

     function processId ( $data ) { /* code */ }
     function processRow ( $data ) { /* code */ }
}

$a = new myClass ( $data, 'id' ) ;
$b = new myClass ( $data, 'row' ) ;
$c = new myClass ( $data, 'something' ) ;

if ( $a->error )
   exit ( 'invalid mode' ) ;
if ( $b->error )
   exit ('invalid mode' ) ;
if ( $c->error )
   exit ('invalid mode' ) ;

Also with that method at any time if you wanted to add more functionality you can just add another case to the switch statement, and you can also check to make sure someone has sent the right thing through - in the above example all the data is ok except for C as that is set to "something" and so the error flag in the class is set and control is returned back to the main program for it to decide what to do next (in the example I just told it to exit with an error message "invalid mode" - but alternatively you could loop it back round until valid data is found).