我有一个简单的Node.js程序在我的机器上运行,我想获得我的程序正在运行的PC的本地IP地址。我如何在Node.js中获得它?
当前回答
这是对已接受答案的修改,它不考虑vEthernet IP地址,如Docker等。
/**
* Get local IP address, while ignoring vEthernet IP addresses (like from Docker, etc.)
*/
let localIP;
var os = require('os');
var ifaces = os.networkInterfaces();
Object.keys(ifaces).forEach(function (ifname) {
var alias = 0;
ifaces[ifname].forEach(function (iface) {
if ('IPv4' !== iface.family || iface.internal !== false) {
// Skip over internal (i.e. 127.0.0.1) and non-IPv4 addresses
return;
}
if(ifname === 'Ethernet') {
if (alias >= 1) {
// This single interface has multiple IPv4 addresses
// console.log(ifname + ':' + alias, iface.address);
} else {
// This interface has only one IPv4 address
// console.log(ifname, iface.address);
}
++alias;
localIP = iface.address;
}
});
});
console.log(localIP);
这将返回一个类似192.168.2.169的IP地址,而不是10.55.1.1。
其他回答
我写了一个Node.js模块,通过查看包含默认网关的网络接口来确定您的本地IP地址。
这比从os.networkInterfaces()或DNS查找主机名更可靠。它可以忽略VMware虚拟接口、环回接口和VPN接口,它可以在Windows、Linux、Mac OS和FreeBSD上工作。在底层,它执行route.exe或netstat并解析输出。
var localIpV4Address = require("local-ipv4-address");
localIpV4Address().then(function(ipAddress){
console.log("My IP address is " + ipAddress);
// My IP address is 10.4.4.137
});
下面是一个允许你获取本地IP地址的变体(在Mac和Windows上测试):
var
// Local IP address that we're trying to calculate
address
// Provides a few basic operating-system related utility functions (built-in)
,os = require('os')
// Network interfaces
,ifaces = os.networkInterfaces();
// Iterate over interfaces ...
for (var dev in ifaces) {
// ... and find the one that matches the criteria
var iface = ifaces[dev].filter(function(details) {
return details.family === 'IPv4' && details.internal === false;
});
if(iface.length > 0)
address = iface[0].address;
}
// Print the result
console.log(address); // 10.25.10.147
这是我的变体,允许以可移植的方式获得IPv4和IPv6地址:
/**
* Collects information about the local IPv4/IPv6 addresses of
* every network interface on the local computer.
* Returns an object with the network interface name as the first-level key and
* "IPv4" or "IPv6" as the second-level key.
* For example you can use getLocalIPs().eth0.IPv6 to get the IPv6 address
* (as string) of eth0
*/
getLocalIPs = function () {
var addrInfo, ifaceDetails, _len;
var localIPInfo = {};
//Get the network interfaces
var networkInterfaces = require('os').networkInterfaces();
//Iterate over the network interfaces
for (var ifaceName in networkInterfaces) {
ifaceDetails = networkInterfaces[ifaceName];
//Iterate over all interface details
for (var _i = 0, _len = ifaceDetails.length; _i < _len; _i++) {
addrInfo = ifaceDetails[_i];
if (addrInfo.family === 'IPv4') {
//Extract the IPv4 address
if (!localIPInfo[ifaceName]) {
localIPInfo[ifaceName] = {};
}
localIPInfo[ifaceName].IPv4 = addrInfo.address;
} else if (addrInfo.family === 'IPv6') {
//Extract the IPv6 address
if (!localIPInfo[ifaceName]) {
localIPInfo[ifaceName] = {};
}
localIPInfo[ifaceName].IPv6 = addrInfo.address;
}
}
}
return localIPInfo;
};
下面是同一个函数的CoffeeScript版本:
getLocalIPs = () =>
###
Collects information about the local IPv4/IPv6 addresses of
every network interface on the local computer.
Returns an object with the network interface name as the first-level key and
"IPv4" or "IPv6" as the second-level key.
For example you can use getLocalIPs().eth0.IPv6 to get the IPv6 address
(as string) of eth0
###
networkInterfaces = require('os').networkInterfaces();
localIPInfo = {}
for ifaceName, ifaceDetails of networkInterfaces
for addrInfo in ifaceDetails
if addrInfo.family=='IPv4'
if !localIPInfo[ifaceName]
localIPInfo[ifaceName] = {}
localIPInfo[ifaceName].IPv4 = addrInfo.address
else if addrInfo.family=='IPv6'
if !localIPInfo[ifaceName]
localIPInfo[ifaceName] = {}
localIPInfo[ifaceName].IPv6 = addrInfo.address
return localIPInfo
console.log(getLocalIPs())的示例输出
{ lo: { IPv4: '127.0.0.1', IPv6: '::1' },
wlan0: { IPv4: '192.168.178.21', IPv6: 'fe80::aa1a:2eee:feba:1c39' },
tap0: { IPv4: '10.1.1.7', IPv6: 'fe80::ddf1:a9a1:1242:bc9b' } }
根据注释,以下是当前版本Node.js的工作原理:
var os = require('os');
var _ = require('lodash');
var ip = _.chain(os.networkInterfaces())
.values()
.flatten()
.filter(function(val) {
return (val.family == 'IPv4' && val.internal == false)
})
.pluck('address')
.first()
.value();
上面一个答案的注释缺少对values()的调用。看起来os.networkInterfaces()现在返回一个对象而不是数组。
以下是jhurliman回答的多ip地址版本:
function getIPAddresses() {
var ipAddresses = [];
var interfaces = require('os').networkInterfaces();
for (var devName in interfaces) {
var iface = interfaces[devName];
for (var i = 0; i < iface.length; i++) {
var alias = iface[i];
if (alias.family === 'IPv4' && alias.address !== '127.0.0.1' && !alias.internal) {
ipAddresses.push(alias.address);
}
}
}
return ipAddresses;
}