使用npm ip模块:

var ip = require('ip');

console.log(ip.address());

> '192.168.0.117'

调用ifconfig是非常依赖于平台的，而且网络层知道套接字所在的IP地址，所以最好是询问它。

Node.js并没有公开这样做的直接方法，但是你可以打开任何套接字，并询问正在使用的本地IP地址。例如，打开www.google.com的套接字:

var net = require('net');
function getNetworkIP(callback) {
  var socket = net.createConnection(80, 'www.google.com');
  socket.on('connect', function() {
    callback(undefined, socket.address().address);
    socket.end();
  });
  socket.on('error', function(e) {
    callback(e, 'error');
  });
}

使用情况:

getNetworkIP(function (error, ip) {
    console.log(ip);
    if (error) {
        console.log('error:', error);
    }
});

这里有一个简洁的小命令行，它实现了这个功能:

const ni = require('os').networkInterfaces();
Object
  .keys(ni)
  .map(interf =>
    ni[interf].map(o => !o.internal && o.family === 'IPv4' && o.address))
  .reduce((a, b) => a.concat(b))
  .filter(o => o)
  [0];

使用npm ip模块:

var ip = require('ip');

console.log(ip.address());

> '192.168.0.117'

下面是前面例子的一个变种。它会小心过滤掉VMware接口等。如果你不传递索引，它会返回所有地址。否则，您可能希望将其默认值设置为0，然后传递null以获取所有值，但您将整理这些。如果想要添加的话，还可以为regex过滤器传入另一个参数。

function getAddress(idx) {

    var addresses = [],
        interfaces = os.networkInterfaces(),
        name, ifaces, iface;

    for (name in interfaces) {
        if(interfaces.hasOwnProperty(name)){
            ifaces = interfaces[name];
            if(!/(loopback|vmware|internal)/gi.test(name)){
                for (var i = 0; i < ifaces.length; i++) {
                    iface = ifaces[i];
                    if (iface.family === 'IPv4' &&  !iface.internal && iface.address !== '127.0.0.1') {
                        addresses.push(iface.address);
                    }
                }
            }
        }
    }

    // If an index is passed only return it.
    if(idx >= 0)
        return addresses[idx];
    return addresses;
}

下面是一个允许你获取本地IP地址的变体(在Mac和Windows上测试):

var
    // Local IP address that we're trying to calculate
    address
    // Provides a few basic operating-system related utility functions (built-in)
    ,os = require('os')
    // Network interfaces
    ,ifaces = os.networkInterfaces();


// Iterate over interfaces ...
for (var dev in ifaces) {

    // ... and find the one that matches the criteria
    var iface = ifaces[dev].filter(function(details) {
        return details.family === 'IPv4' && details.internal === false;
    });

    if(iface.length > 0)
        address = iface[0].address;
}

// Print the result
console.log(address); // 10.25.10.147