如果没有退出函数，应用程序开发人员就可以杀死自己的应用程序，这是非常糟糕的设计。

我的应用程序需要允许用户在运行时动态地更改数据，用户需要重新启动我的应用程序才能使更改生效，但Android不允许我的应用程序自行重新启动。Android操作系统有一个非常糟糕的设计应用程序生命周期。

我认为关键是没有必要退出应用程序，除非你的软件有问题。Android会在用户不使用该应用且设备需要更多内存时退出该应用。如果你有一个需要在后台运行服务的应用程序，你可能需要一种方法来关闭服务。

For example, Google Listen continues to play podcast when the app is not visible. But there is always the pause button to turn the podcast off when the user is done with it. If I remember correctly, Listen, even puts a shortcut in the notification bar so you can always get to the pause button quickly. Another example is an app like a twitter app for instance which constantly polls a service on the internet. These types of apps should really allow the user to choose how often to poll the server, or whether even to poll in a background thread.

如果你需要在退出时运行的代码，你可以根据需要重写onPause()， onStop()或onDestroy()。 http://developer.android.com/reference/android/app/Activity.html#ActivityLifecycle

博客文章“何时在Android应用程序中包含退出按钮”(提示:永远不要)解释得比我好得多。我希望每个Android开发者都读过这本书。

摘录:

In my experience what [the users] really want is: An unambiguous way to guarantee that an app will stop consuming resources (battery, CPU cycles, data transfer, etc.). Many users perceive that an exit button implements this requirement and ask for it to be added. Developers, looking to please their users, obligingly add one. Shortly thereafter they both fail. In most cases the exit button simply calls Activity.finish(). This is exactly equivalent to hitting the back button. Exactly. Services keep running and polling keeps happening. Users may think they've killed the app but they haven't, and soon they'll be even more annoyed. Exit behavior is now ambiguous. Should your exit button just close the Activity, or should it also stop all associated Services, Receivers, and Alarms? What should Back do? What happens if they hit Home instead? What happens if your app has a widget? Should the exit button stop that from updating too? The solution is to make the back button behave as you'd expect the exit button to. Better yet, simply stop consuming resources whenever the app isn't visible.

继续阅读完整的文章。

嗯……

我认为你只是没有以正确的方式看待Android应用。你可以很容易地做一些你想做的事情:

像开发者生命周期文档中鼓励的那样，执行应用程序活动的保存/恢复状态。 如果在恢复阶段需要一些登录(没有可用的登录/会话信息)，那么就这样做。 最终添加一个按钮/菜单/超时，在这种情况下，你将执行finish()而不保存登录和其他会话信息，隐式地结束应用程序会话:因此，如果应用程序再次启动/带到前面，它将开始一个新的会话。

这样你就不关心应用是否真的从内存中删除了。

如果你真的想从内存中删除它(这是不鼓励的，顺便问一下，为了什么目的?)，你可以在onDestroy()的末尾有条件地杀死它，使用java.lang.System.exit(0)(或者restartPackage(..)?)当然，只有在你想“真正结束应用程序”的情况下才这样做，因为onDestroy()是活动正常生命周期的一部分，而不是应用程序的结束。

这很简单。只要遵循我要告诉你的这些指示:

比如你有多个活动，从一个活动到另一个活动。你可能会像这样使用intent:

Intent i1 = new Intent(this, AnotherActivity);
startActivity(i1) 

你只需要添加finish();例如，从头到尾在每个活动上启动intent活动后，

Intent i1=new Intent(this, AnotherActivity);
startActivity(i1) 
finish();

所以当你点击退出按钮时使用的是finish()或System.exit(0)必须完全关闭你的应用程序。

如果你有10个，20个…有多个活动正在运行，你想要完成所有活动并退出系统。

在应用程序类或常量类中创建静态数组。

常量

public class Constants {

public static ArrayList<Activity> activities = new ArrayList<Activity>();

}

在此数组中添加当前活动引用

activity = MainActivity.this; Constants.activities.add(活动);

public class MainActivity extends Activity {

    private ImageView imageButton;
    private Activity activity;


    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);

        activity = MainActivity.this;
        Constants.activities.add(activity);

        imageButton = (ImageView) findViewById(R.id.camera);
        imageButton.setOnClickListener(new View.OnClickListener() {
            @Override
            public void onClick(View v) {

                // existing app.
                if (Constants.activities != null) {
                    for (int i = 0; i < Constants.activities.size(); i++) {
                        Activity s = Constants.activities.get(i);
                        s.finish();
                    }
                }
                //super.finish();
                finish();
                android.os.Process.killProcess(android.os.Process.myPid());
                System.exit(1);
            }
        });
    }
}