我用TextFormField收集用户输入,当用户按下FloatingActionButton表示他们已经完成时,我想解散屏幕上的键盘。

如何让键盘自动消失?

import 'package:flutter/material.dart';

class MyHomePage extends StatefulWidget {
  MyHomePageState createState() => new MyHomePageState();
}

class MyHomePageState extends State<MyHomePage> {
  TextEditingController _controller = new TextEditingController();

  @override
  Widget build(BuildContext context) {
    return new Scaffold(
      appBar: new AppBar(),
      floatingActionButton: new FloatingActionButton(
        child: new Icon(Icons.send),
        onPressed: () {
          setState(() {
            // send message
            // dismiss on screen keyboard here
            _controller.clear();
          });
        },
      ),
      body: new Container(
        alignment: FractionalOffset.center,
        padding: new EdgeInsets.all(20.0),
        child: new TextFormField(
          controller: _controller,
          decoration: new InputDecoration(labelText: 'Example Text'),
        ),
      ),
    );
  }
}

class MyApp extends StatelessWidget {
  @override
  Widget build(BuildContext context) {
    return new MaterialApp(
      home: new MyHomePage(),
    );
  }
}

void main() {
  runApp(new MyApp());
}

当前回答

取消键盘(1.7.8+热修复。2和以上)只需调用下面的方法:

FocusScope.of(context).unfocus();

一旦FocusScope.of(context).unfocus()方法在解散键盘之前检查是否有焦点,就不需要检查它了。但如果你需要它,只需调用另一个上下文方法:FocusScope.of(context).hasPrimaryFocus

其他回答

FocusScope.of(上下文).unfocus ();是行不通的。

这段代码为我工作在颤振2.2.3和零安全。

WidgetsBinding.instance?.focusManager.primaryFocus?.unfocus()

来源:https://github.com/flutter/flutter/issues/20227 # issuecomment - 512860882

例如,把这段代码放在MyAppState中,当整个应用程序触摸外部时应用隐藏键盘。

return GestureDetector(
  onTap: () =>
      WidgetsBinding.instance?.focusManager.primaryFocus?.unfocus(),
  child: MaterialApp(
    title: 'Flutter Demo',
    theme: getTheme(),
    home: _body(),
  ),
);

对于Flutter版本2或最新版本:

由于颤振2零安全,这是最好的方法:

FocusManager.instance.primaryFocus?.unfocus();

注意:使用旧的方法会导致一些问题,如保持重建状态;


对于颤动版本< 2:

自Flutter v1.7.8+热修复。2、要走的路是:

FocusScope.of(context).unfocus();

评论一下PR:

现在#31909 (be75fb3)已经着陆,您应该使用 FocusScope.of(context).unfocus()代替 FocusScope.of(context).requestFocus(FocusNode()),因为FocusNodes ChangeNotifiers,并且应该正确地处理。

- >不使用q r e̶̶̶̶̶u e̶s t F c o̶̶̶̶̶u s̶̶(F c o̶̶̶̶̶u s e N o d̶̶̶̶̶̶̶了。

 F̶o̶c̶u̶s̶S̶c̶o̶p̶e̶.̶o̶f̶(̶c̶o̶n̶t̶e̶x̶t̶)̶.̶r̶e̶q̶u̶e̶s̶t̶F̶o̶c̶u̶s̶(̶F̶o̶c̶u̶s̶N̶o̶d̶e̶(̶)̶)̶;̶

在flutter文档中阅读有关FocusScope类的更多信息。

你可以用"GestureDetector"来包装你的小部件,然后将"FocusScope.of(context).unfocus()"赋值给它的onTap函数

GestureDetector(
 onTap: () => FocusScope.of(context).unfocus(),
 child: child,
);

对我来说,上面的App小部件监听器是我发现的最好的方法:

Listener(
  onPointerUp: (_) {
    FocusScopeNode currentFocus = FocusScope.of(context);
    if (!currentFocus.hasPrimaryFocus && currentFocus.focusedChild != null) {
      currentFocus.focusedChild.unfocus();
    }
  },
  child: MaterialApp(
    title: 'Flutter Test App',
    theme: theme,
    ...
  ),
)

您可以使用FocusNode类中的unfocus()方法。

import 'package:flutter/material.dart';

class MyHomePage extends StatefulWidget {
  MyHomePageState createState() => new MyHomePageState();
}

class MyHomePageState extends State<MyHomePage> {
  TextEditingController _controller = new TextEditingController();
  FocusNode _focusNode = new FocusNode(); //1 - declare and initialize variable

  @override
  Widget build(BuildContext context) {
    return new Scaffold(
      appBar: new AppBar(),
      floatingActionButton: new FloatingActionButton(
        child: new Icon(Icons.send),
        onPressed: () {
            _focusNode.unfocus(); //3 - call this method here
        },
      ),
      body: new Container(
        alignment: FractionalOffset.center,
        padding: new EdgeInsets.all(20.0),
        child: new TextFormField(
          controller: _controller,
          focusNode: _focusNode, //2 - assign it to your TextFormField
          decoration: new InputDecoration(labelText: 'Example Text'),
        ),
      ),
    );
  }
}

class MyApp extends StatelessWidget {
  @override
  Widget build(BuildContext context) {
    return new MaterialApp(
      home: new MyHomePage(),
    );
  }
}

void main() {
  runApp(new MyApp());
}