现在您可以使用常量来实现这一点，而不必像以前那样使用字符串类型的代码，这使得事情变得更加方便。

var appVersion: String {
    return Bundle.main.infoDictionary![kCFBundleVersionKey as String] as! String
}

OP同时要求版本号和版本号。不幸的是，大多数答案都不提供这两个选项。另外，还有一些添加了不必要的扩展方法。这里有一个非常简单的方法，可以解决OP的问题:

// Example output: "1.0 (234)"
private func versionAndBuildNumber() -> String {
  let versionNumber = Bundle.main.infoDictionary?["CFBundleShortVersionString"] as? String
  let buildNumber = Bundle.main.infoDictionary?["CFBundleVersion"] as? String
  if let versionNumber = versionNumber, let buildNumber = buildNumber {
    return "\(versionNumber) (\(buildNumber))"
  } else if let versionNumber = versionNumber {
    return versionNumber
  } else if let buildNumber = buildNumber {
    return buildNumber
  } else {
    return ""
  }
}

斯威夫特5.3

let infoDictionaryKey = kCFBundleVersionKey as String
guard let currentVersion = Bundle.main.object(forInfoDictionaryKey: infoDictionaryKey) as? String
else { fatalError("Expected to find a bundle version in the info dictionary") }

针对Swift 2.0

//First get the nsObject by defining as an optional anyObject

let nsObject: AnyObject? = NSBundle.mainBundle().infoDictionary!["CFBundleShortVersionString"]
let version = nsObject as! String

鉴于Swift一直在发展，我的回答(截至2015年8月):

let version = NSBundle.mainBundle().infoDictionary!["CFBundleVersion"] as! String

Xcode 8, Swift 3:

let gAppVersion = Bundle.main.object(forInfoDictionaryKey: "CFBundleShortVersionString") ?? "0"
let gAppBuild = Bundle.main.object(forInfoDictionaryKey: "CFBundleVersion") ?? "0"