使用javascript URL:

var url = new URL(window.location);
(url.searchParams.has('rows') ? url.searchParams.set('rows', rows) : url.searchParams.append('rows', rows));
window.location = url;

let url= new url ("https://example.com/site.fwx?position=1&archiveid=5000&columns=5&rows=20&sorting=ModifiedTimeAsc") url.searchParams。设置(“行”,10) console.log (url.toString ())

我只是写了一个简单的模块来处理读取和更新当前url查询参数。

使用示例:

import UrlParams from './UrlParams'

UrlParams.remove('foo') //removes all occurences of foo=?
UrlParams.set('foo', 'bar') //set all occurences of foo equal to bar
UrlParams.add('foo', 'bar2') //add bar2 to foo result: foo=bar&foo=bar2
UrlParams.get('foo') //returns bar
UrlParams.get('foo', true) //returns [bar, bar2]

下面是我的代码UrlParams.(js/ts):

class UrlParams {

    /**
     * Get params from current url
     * 
     * @returns URLSearchParams
     */
    static getParams(){
        let url = new URL(window.location.href)
        return new URLSearchParams(url.search.slice(1))
    }

    /**
     * Update current url with params
     * 
     * @param params URLSearchParams
     */
    static update(params){
        if(`${params}`){
            window.history.replaceState({}, '', `${location.pathname}?${params}`)
        } else {
            window.history.replaceState({}, '', `${location.pathname}`)
        }
    }

    /**
     * Remove key from url query
     * 
     * @param param string
     */
    static remove(param){
        let params = this.getParams()
        if(params.has(param)){
            params.delete(param)
            this.update(params)
        }
    }

    /**
     * Add key value pair to current url
     * 
     * @param key string
     * @param value string
     */
    static add(key, value){
        let params = this.getParams()
        params.append(key, value)
        this.update(params)
    }

    /**
     * Get value or values of key
     * 
     * @param param string
     * @param all string | string[]
     */
    static get(param, all=false){
        let params = this.getParams()
        if(all){
            return params.getAll(param)
        }
        return params.get(param)
    }

    /**
     * Set value of query param
     * 
     * @param key string
     * @param value string
     */
    static set(key, value){
        let params = this.getParams()
        params.set(key, value)
        this.update(params)
    }

}
export default UrlParams
export { UrlParams }

一个可行的替代字符串操作的方法是建立一个html表单，只修改rows元素的值吗?

html就像是

<form id='myForm' target='site.fwx'>
    <input type='hidden' name='position' value='1'/>
    <input type='hidden' name='archiveid' value='5000'/>
    <input type='hidden' name='columns' value='5'/>
    <input type='hidden' name='rows' value='20'/>
    <input type='hidden' name='sorting' value='ModifiedTimeAsc'/>
</form>

使用下面的JavaScript提交表单

var myForm = document.getElementById('myForm');
myForm.rows.value = yourNewValue;
myForm.submit();

可能不适合所有情况，但可能比解析URL字符串更好。

在这里，我引用了Adil Malik的回答，并修正了我认为的3个问题。

/**
 * Adds or updates a URL parameter.
 *
 * @param {string} url  the URL to modify
 * @param {string} param  the name of the parameter
 * @param {string} paramVal  the new value for the parameter
 * @return {string}  the updated URL
 */
self.setParameter = function (url, param, paramVal){
  // http://stackoverflow.com/a/10997390/2391566
  var parts = url.split('?');
  var baseUrl = parts[0];
  var oldQueryString = parts[1];
  var newParameters = [];
  if (oldQueryString) {
    var oldParameters = oldQueryString.split('&');
    for (var i = 0; i < oldParameters.length; i++) {
      if(oldParameters[i].split('=')[0] != param) {
        newParameters.push(oldParameters[i]);
      }
    }
  }
  if (paramVal !== '' && paramVal !== null && typeof paramVal !== 'undefined') {
    newParameters.push(param + '=' + encodeURI(paramVal));
  }
  if (newParameters.length > 0) {
    return baseUrl + '?' + newParameters.join('&');
  } else {
    return baseUrl;
  }
}

如果您想在地址栏中更改url:

const search = new URLSearchParams(location.search);
search.set('rows', 10);
location.search = search.toString();

注意，改变位置。搜索重新加载页面。