使用URLSearchParams检查，获取并设置参数值为URL

下面是获取当前URL并设置新参数并根据需要更新URL或重新加载页面的示例

var rows = 5; // value that you want to set
var url = new URL(window.location);
(url.searchParams.has('rows') ? url.searchParams.set('rows', rows) : url.searchParams.append('rows', rows));

url.search = url.searchParams;
url        = url.toString();

// if you want to append into URL without reloading the page
history.pushState({}, null, url);

// want to reload the window with a new param
window.location = url;

var url = new URL(window.location.href);
var search_params = url.searchParams;
search_params.set("param", value);
url.search = search_params.toString();
var new_url = url.pathname + url.search;
window.history.replaceState({}, '', new_url);

四年后，在我学到了很多东西之后，来回答我自己的问题。特别是你不应该对所有事情都使用jQuery。我已经创建了一个简单的模块，可以解析/stringify查询字符串。这使得修改查询字符串变得很容易。

query-string的用法如下:

// parse the query string into an object
var q = queryString.parse(location.search);
// set the `row` property
q.rows = 10;
// convert the object to a query string
// and overwrite the existing query string
location.search = queryString.stringify(q);

在URLSearchParams文档中，有一种非常干净的方法可以做到这一点，而且不会影响历史堆栈。

// URL: https://example.com?version=1.0
const params = new URLSearchParams(location.search);
params.set('version', 2.0);

window.history.replaceState({}, '', `${location.pathname}?${params}`);
// URL: https://example.com?version=2.0

类似地，删除参数

params.delete('version')
window.history.replaceState({}, '', `${location.pathname}?${params}`);
// URL: https://example.com?

我只是写了一个简单的模块来处理读取和更新当前url查询参数。

使用示例:

import UrlParams from './UrlParams'

UrlParams.remove('foo') //removes all occurences of foo=?
UrlParams.set('foo', 'bar') //set all occurences of foo equal to bar
UrlParams.add('foo', 'bar2') //add bar2 to foo result: foo=bar&foo=bar2
UrlParams.get('foo') //returns bar
UrlParams.get('foo', true) //returns [bar, bar2]

下面是我的代码UrlParams.(js/ts):

class UrlParams {

    /**
     * Get params from current url
     * 
     * @returns URLSearchParams
     */
    static getParams(){
        let url = new URL(window.location.href)
        return new URLSearchParams(url.search.slice(1))
    }

    /**
     * Update current url with params
     * 
     * @param params URLSearchParams
     */
    static update(params){
        if(`${params}`){
            window.history.replaceState({}, '', `${location.pathname}?${params}`)
        } else {
            window.history.replaceState({}, '', `${location.pathname}`)
        }
    }

    /**
     * Remove key from url query
     * 
     * @param param string
     */
    static remove(param){
        let params = this.getParams()
        if(params.has(param)){
            params.delete(param)
            this.update(params)
        }
    }

    /**
     * Add key value pair to current url
     * 
     * @param key string
     * @param value string
     */
    static add(key, value){
        let params = this.getParams()
        params.append(key, value)
        this.update(params)
    }

    /**
     * Get value or values of key
     * 
     * @param param string
     * @param all string | string[]
     */
    static get(param, all=false){
        let params = this.getParams()
        if(all){
            return params.getAll(param)
        }
        return params.get(param)
    }

    /**
     * Set value of query param
     * 
     * @param key string
     * @param value string
     */
    static set(key, value){
        let params = this.getParams()
        params.set(key, value)
        this.update(params)
    }

}
export default UrlParams
export { UrlParams }

我知道这是一个老问题。我增强了上面的功能，以添加或更新查询参数。仍然是一个纯JS解决方案。

                      function addOrUpdateQueryParam(param, newval, search) {

                        var questionIndex = search.indexOf('?');

                        if (questionIndex < 0) {
                            search = search + '?';
                            search = search + param + '=' + newval;
                            return search;
                        }

                        var regex = new RegExp("([?;&])" + param + "[^&;]*[;&]?");
                        var query = search.replace(regex, "$1").replace(/&$/, '');

                        var indexOfEquals = query.indexOf('=');

                        return (indexOfEquals >= 0 ? query + '&' : query + '') + (newval ? param + '=' + newval : '');
                    }