下面是我找到包含一些我感兴趣的内容的文件名的方法，只是一个简单的bash行，很好地处理文件名中的空格:

find . -name \*.xml | while read i; do grep '<?xml' "$i" >/dev/null; [ $? == 0 ] && echo $i; done

Piping to another process (although this won't accomplish what you said you are trying to do): command1 | command2 This will send the output of command1 as the input of command2. -exec on a find (this will do what you want to do, but it's specific to find): find . -name '*.foo' -exec cat {} \; Everything between find and -exec are the find predicates you were already using. {} will substitute the particular file you found into the command (cat {} in this case); the \; is to end the -exec command. Send output of one process as command line arguments to another process: command2 `command1` For example: cat `find . -name '*.foo' -print` Note these are backquotes not regular quotes (they are under the tilde ~ on my keyboard). This will send the output of command1 into command2 as command line arguments. It's called command substitution. Note that file names containing spaces (newlines, etc) will be broken into separate arguments, though.

使用ggrep。

ggrep -H -R -I "mysearchstring" *

在Unix中搜索包含位于当前目录或子目录中的文本的文件

对我来说，听起来像是shell脚本的工作:

for file in 'find -name *.xml'
do
   grep 'hello' file
done

或者类似的东西

为了实现这一点(使用bash)，我将这样做:

cat $(find . -name '*.foo')

这就是所谓的“命令替换”，它在默认情况下去掉换行，这真的很方便!

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下面是我找到包含一些我感兴趣的内容的文件名的方法，只是一个简单的bash行，很好地处理文件名中的空格:

find . -name \*.xml | while read i; do grep '<?xml' "$i" >/dev/null; [ $? == 0 ] && echo $i; done