我正在查找文件列表。

我如何将它输送到另一个实用程序,如cat,以便cat显示所有这些文件的内容?

然后,我将使用grep来搜索这些文件中的一些文本。


当前回答

对我来说,听起来像是shell脚本的工作:

for file in 'find -name *.xml'
do
   grep 'hello' file
done

或者类似的东西

其他回答

您正在尝试在文件中查找文本吗?你可以简单地使用grep…

grep searchterm *

这对我很有用

find _CACHE_* | while read line; do
    cat "$line" | grep "something"
done

find命令有一个-exec参数,你可以用它来做类似的事情,你可以直接用它来做grep。

例如(从这里,其他好的例子在本页):

find . -exec grep "www.athabasca" '{}' \; -print 

Piping to another process (although this won't accomplish what you said you are trying to do): command1 | command2 This will send the output of command1 as the input of command2. -exec on a find (this will do what you want to do, but it's specific to find): find . -name '*.foo' -exec cat {} \; Everything between find and -exec are the find predicates you were already using. {} will substitute the particular file you found into the command (cat {} in this case); the \; is to end the -exec command. Send output of one process as command line arguments to another process: command2 `command1` For example: cat `find . -name '*.foo' -print` Note these are backquotes not regular quotes (they are under the tilde ~ on my keyboard). This will send the output of command1 into command2 as command line arguments. It's called command substitution. Note that file names containing spaces (newlines, etc) will be broken into separate arguments, though.

以下是我的常用镜头:

grep YOURSTRING `find .`

它将打印文件名