一轮下来

function round_down(value, decPlaces) {
    return Math.floor(value * Math.pow(10, decPlaces)) / Math.pow(10, decPlaces);
}

围捕

function round_up(value, decPlaces) {
    return Math.ceil(value * Math.pow(10, decPlaces)) / Math.pow(10, decPlaces);
}

圆的

function round_nearest(value, decPlaces) {
    return Math.round(value * Math.pow(10, decPlaces)) / Math.pow(10, decPlaces);
}

合并https://stackoverflow.com/a/7641824/1889449和 https://www.kirupa.com/html5/rounding_numbers_in_javascript.htm谢谢 他们。

我从几个月前的这篇文章中得到了一些想法，但这里的答案，以及其他文章/博客的答案都不能处理所有的场景(例如负数和我们的测试人员发现的一些“幸运数字”)。最后，我们的测试人员没有发现下面这个方法有任何问题。粘贴我的代码片段:

fixPrecision: function (value) {
    var me = this,
        nan = isNaN(value),
        precision = me.decimalPrecision;

    if (nan || !value) {
        return nan ? '' : value;
    } else if (!me.allowDecimals || precision <= 0) {
        precision = 0;
    }

    //[1]
    //return parseFloat(Ext.Number.toFixed(parseFloat(value), precision));
    precision = precision || 0;
    var negMultiplier = value < 0 ? -1 : 1;

    //[2]
    var numWithExp = parseFloat(value + "e" + precision);
    var roundedNum = parseFloat(Math.round(Math.abs(numWithExp)) + 'e-' + precision) * negMultiplier;
    return parseFloat(roundedNum.toFixed(precision));
},

我也有代码注释(对不起，我已经忘记了所有的细节)…我把我的答案贴在这里，以供将来参考:

9.995 * 100 = 999.4999999999999
Whereas 9.995e2 = 999.5
This discrepancy causes Math.round(9.995 * 100) = 999 instead of 1000.
Use e notation instead of multiplying /dividing by Math.Pow(10,precision).

(Math.round((10.2)*100)/100).toFixed(2)

结果应该是10.20

(Math.round((.05)*100)/100).toFixed(2)

结果应该是:0.05

(Math.round((4.04)*100)/100).toFixed(2)

结果应该是:4.04

etc.

又快又简单

parseFloat(number.toFixed(2))

例子

let number = 2.55435930

let roundedString = number.toFixed(2)    // "2.55"

let twoDecimalsNumber = parseFloat(roundedString)    // 2.55

let directly = parseFloat(number.toFixed(2))    // 2.55

/*Due to all told stuff. You may do 2 things for different purposes: When showing/printing stuff use this in your alert/innerHtml= contents: YourRebelNumber.toFixed(2)*/ var aNumber=9242.16; var YourRebelNumber=aNumber-9000; alert(YourRebelNumber); alert(YourRebelNumber.toFixed(2)); /*and when comparing use: Number(YourRebelNumber.toFixed(2))*/ if(YourRebelNumber==242.16)alert("Not Rounded"); if(Number(YourRebelNumber.toFixed(2))==242.16)alert("Rounded"); /*Number will behave as you want in that moment. After that, it'll return to its defiance. */

我没有找到这个问题的准确解决方案，所以我自己创造了一个:

function inprecise_round(value, decPlaces) {
  return Math.round(value*Math.pow(10,decPlaces))/Math.pow(10,decPlaces);
}

function precise_round(value, decPlaces){
    var val = value * Math.pow(10, decPlaces);
    var fraction = (Math.round((val-parseInt(val))*10)/10);

    //this line is for consistency with .NET Decimal.Round behavior
    // -342.055 => -342.06
    if(fraction == -0.5) fraction = -0.6;

    val = Math.round(parseInt(val) + fraction) / Math.pow(10, decPlaces);
    return val;
}

例子:

function inprecise_round(value, decPlaces) { return Math.round(value * Math.pow(10, decPlaces)) / Math.pow(10, decPlaces); } function precise_round(value, decPlaces) { var val = value * Math.pow(10, decPlaces); var fraction = (Math.round((val - parseInt(val)) * 10) / 10); //this line is for consistency with .NET Decimal.Round behavior // -342.055 => -342.06 if (fraction == -0.5) fraction = -0.6; val = Math.round(parseInt(val) + fraction) / Math.pow(10, decPlaces); return val; } // This may produce different results depending on the browser environment console.log("342.055.toFixed(2) :", 342.055.toFixed(2)); // 342.06 on Chrome & IE10 console.log("inprecise_round(342.055, 2):", inprecise_round(342.055, 2)); // 342.05 console.log("precise_round(342.055, 2) :", precise_round(342.055, 2)); // 342.06 console.log("precise_round(-342.055, 2) :", precise_round(-342.055, 2)); // -342.06 console.log("inprecise_round(0.565, 2) :", inprecise_round(0.565, 2)); // 0.56 console.log("precise_round(0.565, 2) :", precise_round(0.565, 2)); // 0.57