你打算怎么处理这个文件?这个文件是否存在于人类，或其他具有明确互操作性要求的程序?

如果您只是试图将列表序列化到磁盘，以便稍后由同一python应用程序使用，则应该pickle该列表。

import pickle

with open('outfile', 'wb') as fp:
    pickle.dump(itemlist, fp)

再读一遍:

with open ('outfile', 'rb') as fp:
    itemlist = pickle.load(fp)

我建议这个解决方案。

with open('your_file.txt', 'w') as f:        
    list(map(lambda item : f.write("%s\n" % item),my_list))   

你还可以通过以下步骤:

例子:

my_list=[1,2,3,4,5,"abc","def"]
with open('your_file.txt', 'w') as file:
    for item in my_list:
        file.write("%s\n" % item)

输出:

在your_file.txt中，项目的保存方式如下:

1

2

3

4

5

abc

def

您的脚本也按上述方式保存。

否则，你可以用泡菜

import pickle
my_list=[1,2,3,4,5,"abc","def"]
#to write
with open('your_file.txt', 'wb') as file:
    pickle.dump(my_list, file)
#to read
with open ('your_file.txt', 'rb') as file:
    Outlist = pickle.load(file)
print(Outlist)

输出: [1,2,3,4,5， 'abc'， 'def']

它保存转储列表，就像一个列表，当我们加载它时，我们能够读取。

同样由simplejson可能输出与上面相同的结果

import simplejson as sj
my_list=[1,2,3,4,5,"abc","def"]
#To write
with open('your_file.txt', 'w') as file:
    sj.dump(my_list, file)

#To save
with open('your_file.txt', 'r') as file:
    mlist=sj.load(file)
print(mlist)

你为什么不试试

file.write(str(list))

更简单的是:

with open("outfile", "w") as outfile:
    outfile.write("\n".join(itemlist))

要确保项目列表中的所有项目都是字符串，请使用生成器表达式:

with open("outfile", "w") as outfile:
    outfile.write("\n".join(str(item) for item in itemlist))

记住，项目列表占用内存，所以要注意内存消耗。

序列化列表到文本文件与逗号分隔值

mylist = dir()
with open('filename.txt','w') as f:
    f.write( ','.join( mylist ) )