更简单的是:

with open("outfile", "w") as outfile:
    outfile.write("\n".join(itemlist))

要确保项目列表中的所有项目都是字符串，请使用生成器表达式:

with open("outfile", "w") as outfile:
    outfile.write("\n".join(str(item) for item in itemlist))

记住，项目列表占用内存，所以要注意内存消耗。

在Python 3中，你可以使用print和*进行参数解包:

with open("fout.txt", "w") as fout:
    print(*my_list, sep="\n", file=fout)

设avg为列表，则:

In [29]: a = n.array((avg))
In [31]: a.tofile('avgpoints.dat',sep='\n',dtype = '%f')

您可以根据自己的需求使用%e或%s。

因为我很懒....

import json
a = [1,2,3]
with open('test.txt', 'w') as f:
    f.write(json.dumps(a))

#Now read the file back into a Python list object
with open('test.txt', 'r') as f:
    a = json.loads(f.read())

这个逻辑首先将list中的项转换为字符串(str)。有时列表包含一个元组，如

alist = [(i12,tiger), 
(113,lion)]

这个逻辑将把每个元组写入一个新行。我们可以在读取文件时加载每个元组时使用eval:

outfile = open('outfile.txt', 'w') # open a file in write mode
for item in list_to_persistence:    # iterate over the list items
   outfile.write(str(item) + '\n') # write to the file
outfile.close()   # close the file 

使用numpy。Savetxt也是一个选项:

import numpy as np

np.savetxt('list.txt', list, delimiter="\n", fmt="%s")