在SQL Server中,可以使用insert将行插入到表中。。SELECT语句:

INSERT INTO Table (col1, col2, col3)
SELECT col1, col2, col3 
FROM other_table 
WHERE sql = 'cool'

是否也可以使用SELECT更新表?我有一个包含这些值的临时表,并希望使用这些值更新另一个表。也许是这样的:

UPDATE Table SET col1, col2
SELECT col1, col2 
FROM other_table 
WHERE sql = 'cool'
WHERE Table.id = other_table.id

当前回答

通过CTE进行更新比此处的其他答案更具可读性:

;WITH cte
     AS (SELECT col1,col2,id
         FROM   other_table
         WHERE  sql = 'cool')
UPDATE A
SET    A.col1 = B.col1,
       A.col2 = B.col2
FROM   table A
       INNER JOIN cte B
               ON A.id = B.id

其他回答

UPDATE YourTable 
SET Col1 = OtherTable.Col1, 
    Col2 = OtherTable.Col2 
FROM (
    SELECT ID, Col1, Col2 
    FROM other_table) AS OtherTable
WHERE 
    OtherTable.ID = YourTable.ID

以下解决方案适用于MySQL数据库:

UPDATE table1 a , table2 b 
SET a.columname = 'some value' 
WHERE b.columnname IS NULL ;

最佳实践:更新行并保存在公司使用的SQL Server中

 WITH t AS
         (
           SELECT UserID, EmailAddress, Password, Gender, DOB, Location,
           Active  FROM Facebook.Users
         )
 UPDATE t SET Active = 0

这是更新记录的最安全的方式,这是您可以看到我们将要更新的内容的方式。来源:URL

UPDATE table AS a
INNER JOIN table2 AS b
ON a.col1 = b.col1
INNER JOIN ... AS ...
ON ... = ...
SET ...
WHERE ...

单向

UPDATE t 
SET t.col1 = o.col1, 
    t.col2 = o.col2
FROM 
    other_table o 
  JOIN 
    t ON t.id = o.id
WHERE 
    o.sql = 'cool'