在SQL Server中,可以使用insert将行插入到表中。。SELECT语句:

INSERT INTO Table (col1, col2, col3)
SELECT col1, col2, col3 
FROM other_table 
WHERE sql = 'cool'

是否也可以使用SELECT更新表?我有一个包含这些值的临时表,并希望使用这些值更新另一个表。也许是这样的:

UPDATE Table SET col1, col2
SELECT col1, col2 
FROM other_table 
WHERE sql = 'cool'
WHERE Table.id = other_table.id

当前回答

UPDATE table AS a
INNER JOIN table2 AS b
ON a.col1 = b.col1
INNER JOIN ... AS ...
ON ... = ...
SET ...
WHERE ...

其他回答

SQLite3对我很有用,在INNER SELECT之后用SELECT更新行。

UPDATE clients
SET col1 = '2023-02-02 18:51:30.826621'
FROM (
      SELECT * FROM clients dc WHERE dc.phone NOT IN (
               SELECT do.phone FROM dclient_order do WHERE do.order_date > '2023-01-01' GROUP BY do.phone
               )
      ) NewTable
WHERE clients.phone = NewTable.phone;

Oracle SQL(使用别名):

UPDATE Table T 
SET T.col1 = (SELECT OT.col1 WHERE OT.id = T.id),
T.col2 = (SELECT OT.col2 WHERE OT.id = T.id);

如果你想加入表本身(这不会经常发生):

update t1                    -- just reference table alias here
set t1.somevalue = t2.somevalue
from table1 t1               -- these rows will be the targets
inner join table1 t2         -- these rows will be used as source
on ..................        -- the join clause is whatever suits you

从select语句更新的另一种方法:

UPDATE A
SET A.col = A.col,B.col1 = B.col1
FROM  first_Table AS A
INNER JOIN second_Table AS B  ON A.id = B.id WHERE A.col2 = 'cool'

如果使用MySQL而不是SQL Server,语法为:

UPDATE Table1
INNER JOIN Table2
ON Table1.id = Table2.id
SET Table1.col1 = Table2.col1,
    Table1.col2 = Table2.col2