如果我有一个JavaScript对象，如:
var list = {
"you": 100,
"me": 75,
"foo": 116,
"bar": 15
};
是否有一种方法可以根据值对属性进行排序?最后得到
list = {
"bar": 15,
"me": 75,
"you": 100,
"foo": 116
};
当前回答
将它们移动到一个数组中，对该数组进行排序，然后将该数组用于您的目的。这里有一个解决方案:
let maxSpeed = {
car: 300,
bike: 60,
motorbike: 200,
airplane: 1000,
helicopter: 400,
rocket: 8 * 60 * 60
};
let sortable = [];
for (var vehicle in maxSpeed) {
sortable.push([vehicle, maxSpeed[vehicle]]);
}
sortable.sort(function(a, b) {
return a[1] - b[1];
});
// [["bike", 60], ["motorbike", 200], ["car", 300],
// ["helicopter", 400], ["airplane", 1000], ["rocket", 28800]]
有了数组之后，就可以按照自己喜欢的顺序从数组重新构建对象，从而完全实现您想要做的事情。这在我所知道的所有浏览器中都可以工作，但它将依赖于一个实现的怪癖，并且随时可能崩溃。永远不要假设JavaScript对象中元素的顺序。
let objSorted = {}
sortable.forEach(function(item){
objSorted[item[0]]=item[1]
})
在ES8中，你可以使用object .entries()将对象转换为数组:
const maxSpeed = { 车:300, 自行车:60岁 摩托车:200, 飞机:1000, 直升机:400, 火箭:8 * 60 * 60 }; const sortable = Object.entries(maxSpeed) .sort([，a]，[，b]) => a-b) .reduce((r， [k, v]) =>({…R， [k]: v})， {}); console.log(合适的);
在ES10中，你可以使用object. fromentries()将数组转换为对象。然后代码可以简化为:
const maxSpeed = { 车:300, 自行车:60岁 摩托车:200, 飞机:1000, 直升机:400, 火箭:8 * 60 * 60 }; const sortable = Object.fromEntries( Object.entries(maxSpeed).sort(([，a]，[，b]) => a-b) ）; console.log(合适的);
其他回答
let toSort = {a:2323, b: 14, c: 799}
let sorted = Object.entries(toSort ).sort((a,b)=> a[1]-b[1])
输出:
[ [ "b", 14 ], [ "c", 799 ], [ "a", 2323 ] ]
我已经用自己的方式尝试过了
var maxSpeed = {
car: 300,
bike: 60,
motorbike: 200,
airplane: 1000,
helicopter: 400,
rocket: 8 * 60 * 60
};
var sorted = {}
Object.keys(maxSpeed).sort ((a,b) => maxSpeed[a] - maxSpeed[b]).map(item => sorted[item] = maxSpeed[item]);
console.log(sorted)
如果我有一个这样的对象，
var dayObj = {
"Friday":["5:00pm to 12:00am"] ,
"Wednesday":["5:00pm to 11:00pm"],
"Sunday":["11:00am to 11:00pm"],
"Thursday":["5:00pm to 11:00pm"],
"Saturday":["11:00am to 12:00am"]
}
我想按天排序，
我们应该先有daySorterMap，
var daySorterMap = {
// "sunday": 0, // << if sunday is first day of week
"Monday": 1,
"Tuesday": 2,
"Wednesday": 3,
"Thursday": 4,
"Friday": 5,
"Saturday": 6,
"Sunday": 7
}
初始化一个单独的对象sortedDayObj，
var sortedDayObj={};
Object.keys(dayObj)
.sort((a,b) => daySorterMap[a] - daySorterMap[b])
.forEach(value=>sortedDayObj[value]= dayObj[value])
你可以返回sortedDayObj
下划线。js或Lodash.js用于高级数组或对象排序
var data = { "models": { "LTI": [ "TX" ], "Carado": [ "A", "T", "A(пасс)", "A(груз)", "T(пасс)", "T(груз)", "A", "T" ], "SPARK": [ "SP110C 2", "sp150r 18" ], "Autobianchi": [ "A112" ] } }; var arr = [], obj = {}; for (var i in data.models) { arr.push([i, _.sortBy(data.models[i], function(el) { return el; })]); } arr = _.sortBy(arr, function(el) { return el[0]; }); _.map(arr, function(el) { return obj[el[0]] = el[1]; }); console.log(obj); <script src="https://cdn.jsdelivr.net/npm/lodash@4.17.21/lodash.min.js" integrity="sha256-qXBd/EfAdjOA2FGrGAG+b3YBn2tn5A6bhz+LSgYD96k=" crossorigin="anonymous"></script>
另一种解决方法:-
var res = [{"s1":5},{"s2":3},{"s3":8}].sort(function(obj1,obj2){
var prop1;
var prop2;
for(prop in obj1) {
prop1=prop;
}
for(prop in obj2) {
prop2=prop;
}
//the above two for loops will iterate only once because we use it to find the key
return obj1[prop1]-obj2[prop2];
});
//res将有结果数组
