我们不想复制整个数据结构，也不想在需要关联数组的地方使用数组。

这里有另一种方法来做与bonna相同的事情:

var列表={“我”“你”:100:75年,“foo”:116年,“酒吧”:15}; keysSorted = Object.keys(list).sort(function(a,b){返回list[a]-list[b]}) console.log (keysSorted);/ /酒吧,我,你,foo

我为此做了一个插件，它接受1个arg，这是一个未排序的对象，并返回一个对象，已排序的道具值。这将适用于所有二维对象，如{"Nick": 28， "Bob": 52}…

var sloppyObj = {
    'C': 78,
    'A': 3,
    'B': 4
};

// Extend object to support sort method
function sortObj(obj) {
    "use strict";

    function Obj2Array(obj) {
        var newObj = [];
        for (var key in obj) {
            if (!obj.hasOwnProperty(key)) return;
            var value = [key, obj[key]];
            newObj.push(value);
        }
        return newObj;
    }

    var sortedArray = Obj2Array(obj).sort(function(a, b) {
        if (a[1] < b[1]) return -1;
        if (a[1] > b[1]) return 1;
        return 0;
    });

    function recreateSortedObject(targ) {
        var sortedObj = {};
        for (var i = 0; i < targ.length; i++) {
            sortedObj[targ[i][0]] = targ[i][1];
        }
        return sortedObj;
    }
    return recreateSortedObject(sortedArray);
}

var sortedObj = sortObj(sloppyObj);

alert(JSON.stringify(sortedObj));

下面是该函数按预期工作的演示 http://codepen.io/nicholasabrams/pen/RWRqve?editors=001

如果我有一个这样的对象，

var dayObj = {
              "Friday":["5:00pm to 12:00am"] ,
              "Wednesday":["5:00pm to 11:00pm"],
              "Sunday":["11:00am to 11:00pm"], 
              "Thursday":["5:00pm to 11:00pm"],
              "Saturday":["11:00am to 12:00am"]
           }

我想按天排序，

我们应该先有daySorterMap，

var daySorterMap = {
  // "sunday": 0, // << if sunday is first day of week
  "Monday": 1,
  "Tuesday": 2,
  "Wednesday": 3,
  "Thursday": 4,
  "Friday": 5,
  "Saturday": 6,
  "Sunday": 7
}

初始化一个单独的对象sortedDayObj，

var sortedDayObj={};
Object.keys(dayObj)
.sort((a,b) => daySorterMap[a] - daySorterMap[b])
.forEach(value=>sortedDayObj[value]= dayObj[value])

你可以返回sortedDayObj

下划线。js或Lodash.js用于高级数组或对象排序

var data = { "models": { "LTI": [ "TX" ], "Carado": [ "A", "T", "A(пасс)", "A(груз)", "T(пасс)", "T(груз)", "A", "T" ], "SPARK": [ "SP110C 2", "sp150r 18" ], "Autobianchi": [ "A112" ] } }; var arr = [], obj = {}; for (var i in data.models) { arr.push([i, _.sortBy(data.models[i], function(el) { return el; })]); } arr = _.sortBy(arr, function(el) { return el[0]; }); _.map(arr, function(el) { return obj[el[0]] = el[1]; }); console.log(obj); <script src="https://cdn.jsdelivr.net/npm/lodash@4.17.21/lodash.min.js" integrity="sha256-qXBd/EfAdjOA2FGrGAG+b3YBn2tn5A6bhz+LSgYD96k=" crossorigin="anonymous"></script>

输入是对象，输出是对象，使用lodash & js内置库，降序或升序选项，不改变输入对象

Eg输入输出

{
  "a": 1,
  "b": 4,
  "c": 0,
  "d": 2
}
{
  "b": 4,
  "d": 2,
  "a": 1,
  "c": 0
}

实现

const _ = require('lodash');

const o = { a: 1, b: 4, c: 0, d: 2 };


function sortByValue(object, descending = true) {
  const { max, min } = Math;
  const selector = descending ? max : min;

  const objects = [];
  const cloned = _.clone(object);

  while (!_.isEmpty(cloned)) {
    const selectedValue = selector(...Object.values(cloned));
    const [key, value] = Object.entries(cloned).find(([, value]) => value === selectedValue);

    objects.push({ [key]: value });
    delete cloned[key];
  }

  return _.merge(...objects);
}

const o2 = sortByValue(o);
console.log(JSON.stringify(o2, null, 2));

找出每个元素的频率，并按频率/值进行排序。

Let response =["苹果"，"橘子"，"苹果"，"香蕉"，"橘子"，"香蕉"，"香蕉"]; 设frequency = {}; response.forEach(函数(项){ 频率[项目]=频率[项目]?频率[项]+ 1:1; })； console.log(频率); let intents = Object.entries(frequency) .sort((a, b) => b[1] - a[1]) . map(函数(x) { 返回x [0]; })； console.log(意图);

输出:

{ apple: 2, orange: 2, banana: 3 }
[ 'banana', 'apple', 'orange' ]