我如何在0和1之间迭代0.1步?

这表示step参数不能为零:

for i in range(0, 1, 0.1):
    print(i)

当前回答

import numpy as np
for i in np.arange(0, 1, 0.1): 
    print i 

其他回答

sign = lambda x: (1, -1)[x < 0]
def frange(start, stop, step):
    i = 0
    r=len(str(step).split('.')[-1])
    args=(start,stop,step)
    if not step :return []
    if all(int(i)==float(i) for i in args):
        start,stop,step=map(int,args)
    if sign(step)==1:
        while start + i * step < stop:
            yield round(start + i * step,r)
            i += 1
    else:
        while start + i * step > stop:
            yield round(start + i * step,r)
            i += 1

在步骤中添加可能出现错误符号的自动更正:

def frange(start,step,stop):
    step *= 2*((stop>start)^(step<0))-1
    return [start+i*step for i in range(int((stop-start)/step))]
[x * 0.1 for x in range(0, 10)] 

在Python 2.7x中给出的结果为:

[0.0, 0.1, 0.2, 0.30000000000000004, 0.4, 0.5, 0.6000000000000001, 0.7000000000000001, 0.8, 0.9]

但如果你用:

[ round(x * 0.1, 1) for x in range(0, 10)]

给你想要的:

[0.0, 0.1, 0.2, 0.3, 0.4, 0.5, 0.6, 0.7, 0.8, 0.9]

Start和stop是包含的,而不是一个或另一个(通常不包括stop),并且没有导入,并使用生成器

def rangef(start, stop, step, fround=5):
    """
    Yields sequence of numbers from start (inclusive) to stop (inclusive)
    by step (increment) with rounding set to n digits.

    :param start: start of sequence
    :param stop: end of sequence
    :param step: int or float increment (e.g. 1 or 0.001)
    :param fround: float rounding, n decimal places
    :return:
    """
    try:
        i = 0
        while stop >= start and step > 0:
            if i==0:
                yield start
            elif start >= stop:
                yield stop
            elif start < stop:
                if start == 0:
                    yield 0
                if start != 0:
                    yield start
            i += 1
            start += step
            start = round(start, fround)
        else:
            pass
    except TypeError as e:
        yield "type-error({})".format(e)
    else:
        pass


# passing
print(list(rangef(-100.0,10.0,1)))
print(list(rangef(-100,0,0.5)))
print(list(rangef(-1,1,0.2)))
print(list(rangef(-1,1,0.1)))
print(list(rangef(-1,1,0.05)))
print(list(rangef(-1,1,0.02)))
print(list(rangef(-1,1,0.01)))
print(list(rangef(-1,1,0.005)))
# failing: type-error:
print(list(rangef("1","10","1")))
print(list(rangef(1,10,"1")))

Python 3.6.2 (v3.6.2:5fd33b5, july 8 2017, 04:57:36) [MSC v.1900 64 . 位(AMD64)]

More_itertools是一个第三方库,它实现了numeric_range工具:

import more_itertools as mit


for x in mit.numeric_range(0, 1, 0.1):
    print("{:.1f}".format(x))

输出

0.0
0.1
0.2
0.3
0.4
0.5
0.6
0.7
0.8
0.9

这个工具也适用于十进制和分数。