我如何在0和1之间迭代0.1步?
这表示step参数不能为零:
for i in range(0, 1, 0.1):
print(i)
我如何在0和1之间迭代0.1步?
这表示step参数不能为零:
for i in range(0, 1, 0.1):
print(i)
当前回答
More_itertools是一个第三方库,它实现了numeric_range工具:
import more_itertools as mit
for x in mit.numeric_range(0, 1, 0.1):
print("{:.1f}".format(x))
输出
0.0
0.1
0.2
0.3
0.4
0.5
0.6
0.7
0.8
0.9
这个工具也适用于十进制和分数。
其他回答
import numpy as np
for i in np.arange(0, 1, 0.1):
print i
Start和stop是包含的,而不是一个或另一个(通常不包括stop),并且没有导入,并使用生成器
def rangef(start, stop, step, fround=5):
"""
Yields sequence of numbers from start (inclusive) to stop (inclusive)
by step (increment) with rounding set to n digits.
:param start: start of sequence
:param stop: end of sequence
:param step: int or float increment (e.g. 1 or 0.001)
:param fround: float rounding, n decimal places
:return:
"""
try:
i = 0
while stop >= start and step > 0:
if i==0:
yield start
elif start >= stop:
yield stop
elif start < stop:
if start == 0:
yield 0
if start != 0:
yield start
i += 1
start += step
start = round(start, fround)
else:
pass
except TypeError as e:
yield "type-error({})".format(e)
else:
pass
# passing
print(list(rangef(-100.0,10.0,1)))
print(list(rangef(-100,0,0.5)))
print(list(rangef(-1,1,0.2)))
print(list(rangef(-1,1,0.1)))
print(list(rangef(-1,1,0.05)))
print(list(rangef(-1,1,0.02)))
print(list(rangef(-1,1,0.01)))
print(list(rangef(-1,1,0.005)))
# failing: type-error:
print(list(rangef("1","10","1")))
print(list(rangef(1,10,"1")))
Python 3.6.2 (v3.6.2:5fd33b5, july 8 2017, 04:57:36) [MSC v.1900 64 . 位(AMD64)]
我的解决方案:
def seq(start, stop, step=1, digit=0):
x = float(start)
v = []
while x <= stop:
v.append(round(x,digit))
x += step
return v
sign = lambda x: (1, -1)[x < 0]
def frange(start, stop, step):
i = 0
r=len(str(step).split('.')[-1])
args=(start,stop,step)
if not step :return []
if all(int(i)==float(i) for i in args):
start,stop,step=map(int,args)
if sign(step)==1:
while start + i * step < stop:
yield round(start + i * step,r)
i += 1
else:
while start + i * step > stop:
yield round(start + i * step,r)
i += 1
在'xrange([start], stop[, step])'基础上,你可以定义一个生成器,它接受并生成你选择的任何类型(坚持支持+和<的类型):
>>> def drange(start, stop, step):
... r = start
... while r < stop:
... yield r
... r += step
...
>>> i0=drange(0.0, 1.0, 0.1)
>>> ["%g" % x for x in i0]
['0', '0.1', '0.2', '0.3', '0.4', '0.5', '0.6', '0.7', '0.8', '0.9', '1']
>>>