您也可以使用pyplot。文本(见这里)。

def plot_embeddings(M_reduced, word2Ind, words):
    """ 
        Plot in a scatterplot the embeddings of the words specified in the list "words".
        Include a label next to each point.
    """
    for word in words:
        x, y = M_reduced[word2Ind[word]]
        plt.scatter(x, y, marker='x', color='red')
        plt.text(x+.03, y+.03, word, fontsize=9)
    plt.show()

M_reduced_plot_test = np.array([[1, 1], [-1, -1], [1, -1], [-1, 1], [0, 0]])
word2Ind_plot_test = {'test1': 0, 'test2': 1, 'test3': 2, 'test4': 3, 'test5': 4}
words = ['test1', 'test2', 'test3', 'test4', 'test5']
plot_embeddings(M_reduced_plot_test, word2Ind_plot_test, words)

您也可以使用pyplot。文本(见这里)。

def plot_embeddings(M_reduced, word2Ind, words):
    """ 
        Plot in a scatterplot the embeddings of the words specified in the list "words".
        Include a label next to each point.
    """
    for word in words:
        x, y = M_reduced[word2Ind[word]]
        plt.scatter(x, y, marker='x', color='red')
        plt.text(x+.03, y+.03, word, fontsize=9)
    plt.show()

M_reduced_plot_test = np.array([[1, 1], [-1, -1], [1, -1], [-1, 1], [0, 0]])
word2Ind_plot_test = {'test1': 0, 'test2': 1, 'test3': 2, 'test4': 3, 'test5': 4}
words = ['test1', 'test2', 'test3', 'test4', 'test5']
plot_embeddings(M_reduced_plot_test, word2Ind_plot_test, words)

如果有人试图将上述解决方案应用于.scatter()而不是.subplot()，

我尝试运行以下代码

import matplotlib.pyplot as plt
y = [2.56422, 3.77284, 3.52623, 3.51468, 3.02199]
z = [0.15, 0.3, 0.45, 0.6, 0.75]
n = [58, 651, 393, 203, 123]

fig, ax = plt.scatter(z, y)

for i, txt in enumerate(n):
    ax.annotate(txt, (z[i], y[i]))

但是遇到了“不能解包不可迭代的PathCollection对象”的错误，错误具体指向代码线图，ax = plt。散射(z, y)

我最终用下面的代码解决了这个错误

import matplotlib.pyplot as plt
plt.scatter(z, y)

for i, txt in enumerate(n):
    plt.annotate(txt, (z[i], y[i]))

我没想到.scatter()和.subplot()之间有区别 我早该知道的。

对于有限的值集，matplotlib很好。但是当你有很多值时，工具提示开始与其他数据点重叠。但由于空间有限，你不能忽略这些值。因此，最好是缩小或放大。

使用图

import plotly.express as px
import pandas as pd

df = px.data.tips()

df = px.data.gapminder().query("year==2007 and continent=='Americas'")


fig = px.scatter(df, x="gdpPercap", y="lifeExp", text="country", log_x=True, size_max=100, color="lifeExp")
fig.update_traces(textposition='top center')
fig.update_layout(title_text='Life Expectency', title_x=0.5)
fig.show()

作为一个使用列表理解和numpy的一行程序:

(ax。注释(x [0] (x[1],[2]))的x np.array ([n, z, y]) .T]

设置与Rutger的答案相同。

Python 3.6 +:

coordinates = [('a',1,2), ('b',3,4), ('c',5,6)]
for x in coordinates: plt.annotate(x[0], (x[1], x[2]))