AngularJS有&参数,你可以把一个回调传递给一个指令(例如AngularJS的回调方式)。是否可以将回调函数作为@Input传递给Angular组件(如下所示)?如果不是,那最接近AngularJS的功能是什么?
@Component({
selector: 'suggestion-menu',
providers: [SuggestService],
template: `
<div (mousedown)="suggestionWasClicked(suggestion)">
</div>`,
changeDetection: ChangeDetectionStrategy.Default
})
export class SuggestionMenuComponent {
@Input() callback: Function;
suggestionWasClicked(clickedEntry: SomeModel): void {
this.callback(clickedEntry, this.query);
}
}
<suggestion-menu callback="insertSuggestion">
</suggestion-menu>
在某些情况下,您可能需要由父组件执行业务逻辑。在下面的例子中,我们有一个子组件,它根据父组件提供的逻辑来呈现表行:
@Component({
...
template: '<table-component [getRowColor]="getColor"></table-component>',
directives: [TableComponent]
})
export class ParentComponent {
// Pay attention on the way this function is declared. Using fat arrow (=>) declaration
// we can 'fixate' the context of `getColor` function
// so that it is bound to ParentComponent as if .bind(this) was used.
getColor = (row: Row) => {
return this.fancyColorService.getUserFavoriteColor(row);
}
}
@Component({...})
export class TableComponent{
// This will be bound to the ParentComponent.getColor.
// I found this way of declaration a bit safer and convenient than just raw Function declaration
@Input('getRowColor') getRowColor: (row: Row) => Color;
renderRow(){
....
// Notice that `getRowColor` function holds parent's context because of a fat arrow function used in the parent
const color = this.getRowColor(row);
renderRow(row, color);
}
}
所以,我想在这里演示两件事:
胖箭头(=>)代替.bind(this)来保存正确的上下文;
子组件中回调函数的类型安全声明。
与Max Fahl给出的答案不同。
你可以将回调函数定义为父组件中的箭头函数,这样你就不需要绑定它了。
@Component({
...
// unlike this, template: '<child [myCallback]="theCallback.bind(this)"></child>',
template: '<child [myCallback]="theCallback"></child>',
directives: [ChildComponent]
})
export class ParentComponent {
// unlike this, public theCallback(){
public theCallback = () => {
...
}
}
@Component({...})
export class ChildComponent{
//This will be bound to the ParentComponent.theCallback
@Input()
public myCallback: Function;
...
}
更新
这个答案是在Angular 2还处于alpha阶段的时候提交的,当时很多特性都无法使用/没有文档记录。虽然下面的方法仍然有效,但这种方法现在已经完全过时了。我强烈推荐下面接受的答案。
原来的答案
是的,事实上它是,但是你要确保它的作用域是正确的。为此,我使用了一个属性来确保这意味着我想要的。
@Component({
...
template: '<child [myCallback]="theBoundCallback"></child>',
directives: [ChildComponent]
})
export class ParentComponent{
public theBoundCallback: Function;
public ngOnInit(){
this.theBoundCallback = this.theCallback.bind(this);
}
public theCallback(){
...
}
}
@Component({...})
export class ChildComponent{
//This will be bound to the ParentComponent.theCallback
@Input()
public myCallback: Function;
...
}