我正在用logging.error将Python异常消息打印到日志文件:
import logging
try:
1/0
except ZeroDivisionError as e:
logging.error(e) # ERROR:root:division by zero
是否可以打印有关异常和生成异常的代码的更详细信息,而不仅仅是异常字符串?行号或堆栈跟踪之类的东西会很棒。
我正在用logging.error将Python异常消息打印到日志文件:
import logging
try:
1/0
except ZeroDivisionError as e:
logging.error(e) # ERROR:root:division by zero
是否可以打印有关异常和生成异常的代码的更详细信息,而不仅仅是异常字符串?行号或堆栈跟踪之类的东西会很棒。
当前回答
我把所有的函数都包在我的自定义设计的日志记录器周围:
import json
import timeit
import traceback
import sys
import unidecode
def main_writer(f,argument):
try:
f.write(str(argument))
except UnicodeEncodeError:
f.write(unidecode.unidecode(argument))
def logger(*argv,logfile="log.txt",singleLine = False):
"""
Writes Logs to LogFile
"""
with open(logfile, 'a+') as f:
for arg in argv:
if arg == "{}":
continue
if type(arg) == dict and len(arg)!=0:
json_object = json.dumps(arg, indent=4, default=str)
f.write(str(json_object))
f.flush()
"""
for key,val in arg.items():
f.write(str(key) + " : "+ str(val))
f.flush()
"""
elif type(arg) == list and len(arg)!=0:
for each in arg:
main_writer(f,each)
f.write("\n")
f.flush()
else:
main_writer(f,arg)
f.flush()
if singleLine==False:
f.write("\n")
if singleLine==True:
f.write("\n")
def tryFunc(func, func_name=None, *args, **kwargs):
"""
Time for Successfull Runs
Exception Traceback for Unsuccessful Runs
"""
stack = traceback.extract_stack()
filename, codeline, funcName, text = stack[-2]
func_name = func.__name__ if func_name is None else func_name # sys._getframe().f_code.co_name # func.__name__
start = timeit.default_timer()
x = None
try:
x = func(*args, **kwargs)
stop = timeit.default_timer()
# logger("Time to Run {} : {}".format(func_name, stop - start))
except Exception as e:
logger("Exception Occurred for {} :".format(func_name))
logger("Basic Error Info :",e)
logger("Full Error TraceBack :")
# logger(e.message, e.args)
logger(traceback.format_exc())
return x
def bad_func():
return 'a'+ 7
if __name__ == '__main__':
logger(234)
logger([1,2,3])
logger(['a','b','c'])
logger({'a':7,'b':8,'c':9})
tryFunc(bad_func)
其他回答
使用exc_info选项可能更好,允许你选择错误级别(如果你使用exception,它将总是在错误级别):
try:
# do something here
except Exception as e:
logging.critical(e, exc_info=True) # log exception info at CRITICAL log level
日志记录有一个好处。SiggyF的答案没有显示的异常是,你可以传递一个任意的消息,日志仍然会显示所有异常细节的完整跟踪:
import logging
try:
1/0
except ZeroDivisionError:
logging.exception("Deliberate divide by zero traceback")
默认情况下(在最近的版本中)只是将错误打印到sys. log行为。Stderr,它看起来像这样:
>>> import logging
>>> try:
... 1/0
... except ZeroDivisionError:
... logging.exception("Deliberate divide by zero traceback")
...
ERROR:root:Deliberate divide by zero traceback
Traceback (most recent call last):
File "<stdin>", line 2, in <module>
ZeroDivisionError: integer division or modulo by zero
在日志模块(如果是自定义模块)中启用stack_info。
api_logger.exceptionLog("*Input your Custom error message*",stack_info=True)
记录器。异常将在错误消息旁边输出堆栈跟踪。
例如:
import logging
try:
1/0
except ZeroDivisionError:
logging.exception("message")
输出:
ERROR:root:message
Traceback (most recent call last):
File "<stdin>", line 2, in <module>
ZeroDivisionError: integer division or modulo by zero
@Paulo支票笔记,“注意在python3中你必须调用日志记录。except部分中的异常方法。如果在任意位置调用此方法,可能会得到一个奇怪的异常。医生对此提出了警告。”
这个答案是建立在上述优秀答案之上的。
在大多数应用程序中,您不会直接调用logging.exception(e)。很可能你已经为你的应用程序或模块定义了一个自定义记录器,如下所示:
# Set the name of the app or module
my_logger = logging.getLogger('NEM Sequencer')
# Set the log level
my_logger.setLevel(logging.INFO)
# Let's say we want to be fancy and log to a graylog2 log server
graylog_handler = graypy.GELFHandler('some_server_ip', 12201)
graylog_handler.setLevel(logging.INFO)
my_logger.addHandler(graylog_handler)
在这种情况下,只需使用记录器调用异常(e),如下所示:
try:
1/0
except ZeroDivisionError, e:
my_logger.exception(e)