我知道有很多这种性质的问题,但我需要使用JavaScript来做到这一点。我使用Dojo 1.8并在数组中拥有所有属性信息,它看起来像这样:

[["name1", "city_name1", ...]["name2", "city_name2", ...]]

知道我如何在客户端将此导出为CSV吗?


当前回答

一个极简但功能完整的解决方案:)

/** Convert a 2D array into a CSV string
 */
function arrayToCsv(data){
  return data.map(row =>
    row
    .map(String)  // convert every value to String
    .map(v => v.replaceAll('"', '""'))  // escape double colons
    .map(v => `"${v}"`)  // quote it
    .join(',')  // comma-separated
  ).join('\r\n');  // rows starting on new lines
}

例子:

let csv = arrayToCsv([
  [1, '2', '"3"'],
  [true, null, undefined],
]);

结果:

"1","2","""3"""
"true","null","undefined"

现在将其下载为文件:


/** Download contents as a file
 * Source: https://stackoverflow.com/questions/14964035/how-to-export-javascript-array-info-to-csv-on-client-side
 */
function downloadBlob(content, filename, contentType) {
  // Create a blob
  var blob = new Blob([content], { type: contentType });
  var url = URL.createObjectURL(blob);

  // Create a link to download it
  var pom = document.createElement('a');
  pom.href = url;
  pom.setAttribute('download', filename);
  pom.click();
}

下载:

downloadBlob(csv, 'export.csv', 'text/csv;charset=utf-8;')

其他回答

基于上面的答案,我创建了这个函数,并在IE 11、Chrome 36和Firefox 29上进行了测试

function exportToCsv(filename, rows) {
    var processRow = function (row) {
        var finalVal = '';
        for (var j = 0; j < row.length; j++) {
            var innerValue = row[j] === null ? '' : row[j].toString();
            if (row[j] instanceof Date) {
                innerValue = row[j].toLocaleString();
            };
            var result = innerValue.replace(/"/g, '""');
            if (result.search(/("|,|\n)/g) >= 0)
                result = '"' + result + '"';
            if (j > 0)
                finalVal += ',';
            finalVal += result;
        }
        return finalVal + '\n';
    };

    var csvFile = '';
    for (var i = 0; i < rows.length; i++) {
        csvFile += processRow(rows[i]);
    }

    var blob = new Blob([csvFile], { type: 'text/csv;charset=utf-8;' });
    if (navigator.msSaveBlob) { // IE 10+
        navigator.msSaveBlob(blob, filename);
    } else {
        var link = document.createElement("a");
        if (link.download !== undefined) { // feature detection
            // Browsers that support HTML5 download attribute
            var url = URL.createObjectURL(blob);
            link.setAttribute("href", url);
            link.setAttribute("download", filename);
            link.style.visibility = 'hidden';
            document.body.appendChild(link);
            link.click();
            document.body.removeChild(link);
        }
    }
}

例如: https://jsfiddle.net/jossef/m3rrLzk0/

上面的答案是可行的,但请记住,如果你以.xls格式打开,列~~可能会用'\t'而不是','分隔,答案https://stackoverflow.com/a/14966131/6169225对我来说很好,只要我在数组上使用.join('\t')而不是.join(',')。

这里有许多将数据转换为CSV的解决方案,但几乎所有的解决方案都有各种各样的注意事项,即在不出错的情况下正确格式化数据类型。

为什么不使用一些经过验证的东西:Papa Parse

Papa.unparse(data[, config])

然后只需结合这与本地下载解决方案之一在这里,如。@ArneHB的那个看起来不错。

如果你正在寻找一个真正快速的解决方案,你也可以给这个小库一个机会,它将为你创建和下载CSV文件:https://github.com/mbrn/filefy

用法非常简单:

import { CsvBuilder } from 'filefy';

var csvBuilder = new CsvBuilder("user_list.csv")
  .setColumns(["name", "surname"])
  .addRow(["Eve", "Holt"])
  .addRows([
    ["Charles", "Morris"],
    ["Tracey", "Ramos"]
  ])
  .exportFile();
//It work in Chrome and IE ... I reviewed and readed a lot of answer. then i used it and tested in both ... 

var link = document.createElement("a");

if (link.download !== undefined) { // feature detection
    // Browsers that support HTML5 download attribute
    var blob = new Blob([CSV], { type: 'text/csv;charset=utf-8;' });
    var url = URL.createObjectURL(blob);            
    link.setAttribute("href", url);
    link.setAttribute("download", fileName);
    link.style = "visibility:hidden";
}

if (navigator.msSaveBlob) { // IE 10+
   link.addEventListener("click", function (event) {
     var blob = new Blob([CSV], {
       "type": "text/csv;charset=utf-8;"
     });
   navigator.msSaveBlob(blob, fileName);
  }, false);
}

document.body.appendChild(link);
link.click();
document.body.removeChild(link);

//Regards