是否有一种内置的方法来测量Windows命令行上命令的执行时间?


当前回答

我使用的是Windows XP,由于某些原因,time .exe不适合我。我找到了另一种选择——PTIME。这工作得很好。

http://www.pc-tools.net/win32/ptime/

的例子,

C:\> ptime

ptime 1.0 for Win32, Freeware - http://www.pc-tools.net/
Copyright(C) 2002, Jem Berkes <jberkes@pc-tools.net>

Syntax: ptime command [arguments ...]

ptime will run the specified command and measure the execution time
(run time) in seconds, accurate to 5 millisecond or better. It is an
automatic process timer, or program timer.


C:\> ptime cd

ptime 1.0 for Win32, Freeware - http://www.pc-tools.net/
Copyright(C) 2002, Jem Berkes <jberkes@pc-tools.net>

===  cd ===
C:\

Execution time: 0.015 s

其他回答

在Perl安装了可用的雇佣解决方案后,运行:

C:\BATCH>time.pl "echo Fine result"
0.01063
Fine result

STDERR出现在被测量的秒之前

#!/usr/bin/perl -w

use Time::HiRes qw();
my $T0 = [ Time::HiRes::gettimeofday ];

my $stdout = `@ARGV`;

my $time_elapsed = Time::HiRes::tv_interval( $T0 );

print $time_elapsed, "\n";
print $stdout;

用潜水艇返回百分之一秒的时间

::tiemeit.cmd
@echo off
Setlocal EnableDelayedExpansion

call :clock 

::call your_command  or more > null to pipe this batch after your_command

call :clock

echo %timed%
pause
goto:eof

:clock
if not defined timed set timed=0
for /F "tokens=1-4 delims=:.," %%a in ("%time%") do ( 
set /A timed = "(((1%%a - 100) * 60 + (1%%b - 100)) * 60 + (1%%c - 100))  * 100 + (1%%d - 100)- %timed%"
)
goto:eof

如果你安装了CMake,你可以运行下面的命令。

cmake -E time <the_command_to_measure_run_time>

不像Unix上的一些功能那样优雅,但是创建一个cmd文件,看起来像这样:

@echo off
time < nul
yourexecutable.exe > c:\temp\output.txt
time < nul
rem on newer windows system you can try time /T

将显示开始和停止时间,如下所示:

The current time is: 10:31:57.92
Enter the new time:
The current time is: 10:32:05.94
Enter the new time:

呵呵,最简单的解决办法可能是:

echo %time%
YourApp.exe
echo %time%

这适用于所有开箱即用的Windows。


在应用程序使用控制台输出的情况下,将开始时间存储在临时变量中可能会很方便:

set startTime=%time%
YourApp.exe
echo Start Time: %startTime%
echo Finish Time: %time%