下面的脚本模拟*nix纪元时间，但它是本地和区域性的。它应该处理日历边缘情况，包括闰年。如果Cygwin可用，则可以通过指定Cygwin选项来比较epoch值。

我在EST，报告的差异是4小时，这是相对正确的。有一些有趣的解决方案可以删除TZ和区域依赖，但我注意到没有什么微不足道的。

@ECHO off
SETLOCAL EnableDelayedExpansion

::
::  Emulates local epoch seconds
::

:: Call passing local date and time
CALL :SECONDS "%DATE%" "%TIME%"
IF !SECONDS! LEQ 0 GOTO END

:: Not testing - print and exit
IF NOT "%~1"=="cygwin" (
    ECHO !SECONDS!
    GOTO END
)

:: Call on Cygwin to get epoch time
FOR /F %%c IN ('C:\cygwin\bin\date +%%s') DO SET EPOCH=%%c

:: Show the results
ECHO Local Seconds: !SECONDS!
ECHO Epoch Seconds: !EPOCH!

:: Calculate difference between script and Cygwin
SET /A HOURS=(!EPOCH!-!SECONDS!)/3600
SET /A FRAC=(!EPOCH!-!SECONDS!)%%3600

:: Delta hours shown reflect TZ
ECHO Delta Hours: !HOURS! Remainder: !FRAC!

GOTO END

:SECONDS
SETLOCAL  EnableDelayedExpansion

    :: Expecting values from caller
    SET DATE=%~1
    SET TIME=%~2

    :: Emulate Unix epoch time without considering TZ
    SET "SINCE_YEAR=1970"

    :: Regional constraint! Expecting date and time in the following formats:
    ::   Sun 03/08/2015   Day MM/DD/YYYY
    ::   20:04:53.64         HH:MM:SS
    SET VALID_DATE=0
    ECHO !DATE! | FINDSTR /R /C:"^... [0-9 ][0-9]/[0-9 ][0-9]/[0-9][0-9][0-9][0-9]" > nul && SET VALID_DATE=1
    SET VALID_TIME=0
    ECHO !TIME! | FINDSTR /R /C:"^[0-9 ][0-9]:[0-9 ][0-9]:[0-9 ][0-9]" > nul && SET VALID_TIME=1
    IF NOT "!VALID_DATE!!VALID_TIME!"=="11" (
        IF !VALID_DATE! EQU 0  ECHO Unsupported Date value: !DATE! 1>&2
        IF !VALID_TIME! EQU 0  ECHO Unsupported Time value: !TIME! 1>&2
        SET SECONDS=0
        GOTO SECONDS_END
    )

    :: Parse values
    SET "YYYY=!DATE:~10,4!"
    SET "MM=!DATE:~4,2!"
    SET "DD=!DATE:~7,2!"
    SET "HH=!TIME:~0,2!"
    SET "NN=!TIME:~3,2!"
    SET "SS=!TIME:~6,2!"
    SET /A YEARS=!YYYY!-!SINCE_YEAR!
    SET /A DAYS=!YEARS!*365

    :: Bump year if after February  - want leading zeroes for this test
    IF "!MM!!DD!" GEQ "0301" SET /A YEARS+=1

    :: Remove leading zeros that can cause octet probs for SET /A
    FOR %%r IN (MM,DD,HH,NN,SS) DO (
        SET "v=%%r"
        SET "t=!%%r!"
        SET /A N=!t:~0,1!0
        IF 0 EQU !N! SET "!v!=!t:~1!"
    )

    :: Increase days according to number of leap years
    SET /A DAYS+=(!YEARS!+3)/4-(!SINCE_YEAR!%%4+3)/4

    :: Increase days by preceding months of current year
    FOR %%n IN (31:1,28:2,31:3,30:4,31:5,30:6,31:7,31:8,30:9,31:10,30:11) DO (
        SET "n=%%n"
        IF !MM! GTR !n:~3! SET /A DAYS+=!n:~0,2!
    )

    :: Multiply and add it all together
    SET /A SECONDS=(!DAYS!+!DD!-1)*86400+!HH!*3600+!NN!*60+!SS!

:SECONDS_END
ENDLOCAL & SET "SECONDS=%SECONDS%"
GOTO :EOF

:END
ENDLOCAL

这是对Luke Sampson的nice timecmd.bat的评论/编辑并回复

出于某种原因，这只给我整秒的输出…这对我来说毫无用处。我的意思是，我运行timecmd pause，结果总是1秒，2秒，4秒……甚至是0.00秒!Windows 7。- Camilo Martin 13年9月25日16:00

在某些配置上，分隔符可能不同。以下变化至少应该涵盖大多数西方国家。

set options="tokens=1-4 delims=:,." (added comma)

在添加'，'后，%time%毫秒在我的系统上工作

(*因为网站不允许匿名评论，没有很好地跟踪身份，即使我总是使用相同的客人电子邮件，结合ipv6 ip和浏览器指纹应该足以唯一识别没有密码)

我在Windows Server 2008 R2中使用的一行程序是:

cmd /v:on /c "echo !TIME! & *mycommand* & echo !TIME!"

只要mycommand不需要引号(这会影响cmd的引号处理)。on允许两个不同的TIME值独立计算，而不是在执行命令时一次计算。

“精益和平均”计时器与区域格式，24小时和混合输入支持 调整Aacini的替换方法体，没有IF，只有一个FOR(我的区域修复)

1:文件timer.bat放置在%PATH%或当前目录的某处

@echo off & rem :AveYo: compact timer function with Regional format, 24-hours and mixed input support
if not defined timer_set (if not "%~1"=="" (call set "timer_set=%~1") else set "timer_set=%TIME: =0%") & goto :eof
(if not "%~1"=="" (call set "timer_end=%~1") else set "timer_end=%TIME: =0%") & setlocal EnableDelayedExpansion
for /f "tokens=1-6 delims=0123456789" %%i in ("%timer_end%%timer_set%") do (set CE=%%i&set DE=%%k&set CS=%%l&set DS=%%n)
set "TE=!timer_end:%DE%=%%100)*100+1!"     & set "TS=!timer_set:%DS%=%%100)*100+1!"
set/A "T=((((10!TE:%CE%=%%100)*60+1!%%100)-((((10!TS:%CS%=%%100)*60+1!%%100)" & set/A "T=!T:-=8640000-!"
set/A "cc=T%%100+100,T/=100,ss=T%%60+100,T/=60,mm=T%%60+100,hh=T/60+100"
set "value=!hh:~1!%CE%!mm:~1!%CE%!ss:~1!%DE%!cc:~1!" & if "%~2"=="" echo/!value!
endlocal & set "timer_end=%value%" & set "timer_set=" & goto :eof

用法: Timer & echo start_cmds & timeout /t 3 & echo end_cmds & Timer 计时器&计时器“23:23:23,00” 计时器“23:23:23,00”&计时器 计时器“13.23.23,00”&计时器“03:03:03.00” 定时器&定时器“0:00:00.00”no & CMD /v:on /c echo until midnight=!timer_end! 对于执行过程中不太可能但可能发生的时间格式更改，现在可以混合输入

2:函数:与批处理脚本绑定的定时器(示例用法如下):

@echo off
set "TIMER=call :timer" & rem short macro
echo.
echo EXAMPLE:
call :timer
timeout /t 3 >nul & rem Any process here..
call :timer
echo.
echo SHORT MACRO:
%TIMER% & timeout /t 1 & %TIMER% 
echo.
echo TEST INPUT:
set "start=22:04:04.58"
set "end=04.22.44,22"
echo %start% ~ start & echo %end% ~ end
call :timer "%start%"
call :timer "%end%"
echo.
%TIMER% & %TIMER% "00:00:00.00" no 
echo UNTIL MIDNIGHT: %timer_end%
echo.
pause 
exit /b

::要测试它，复制粘贴上面和下面的代码段

rem :AveYo: compact timer function with Regional format, 24-hours and mixed input support 
:timer Usage " call :timer [input - optional] [no - optional]" :i Result printed on second call, saved to timer_end 
if not defined timer_set (if not "%~1"=="" (call set "timer_set=%~1") else set "timer_set=%TIME: =0%") & goto :eof
(if not "%~1"=="" (call set "timer_end=%~1") else set "timer_end=%TIME: =0%") & setlocal EnableDelayedExpansion
for /f "tokens=1-6 delims=0123456789" %%i in ("%timer_end%%timer_set%") do (set CE=%%i&set DE=%%k&set CS=%%l&set DS=%%n)
set "TE=!timer_end:%DE%=%%100)*100+1!"     & set "TS=!timer_set:%DS%=%%100)*100+1!"
set/A "T=((((10!TE:%CE%=%%100)*60+1!%%100)-((((10!TS:%CS%=%%100)*60+1!%%100)" & set/A "T=!T:-=8640000-!"
set/A "cc=T%%100+100,T/=100,ss=T%%60+100,T/=60,mm=T%%60+100,hh=T/60+100"
set "value=!hh:~1!%CE%!mm:~1!%CE%!ss:~1!%DE%!cc:~1!" & if "%~2"=="" echo/!value!
endlocal & set "timer_end=%value%" & set "timer_set=" & goto :eof

CE,DE和CS,DS代表冒号结束，点结束和冒号集合，点集合-用于混合格式支持

driblio的答案可以短一点(虽然可读性不高)

@echo off

:: Calculate the start timestamp
set _time=%time%
set /a _hours=100%_time:~0,2%%%100,_min=100%_time:~3,2%%%100,_sec=100%_time:~6,2%%%100,_cs=%_time:~9,2%
set /a _started=_hours*60*60*100+_min*60*100+_sec*100+_cs


:: yourCommandHere


:: Calculate the difference in cSeconds
set _time=%time%
set /a _hours=100%_time:~0,2%%%100,_min=100%_time:~3,2%%%100,_sec=100%_time:~6,2%%%100,_cs=%_time:~9,2%
set /a _duration=_hours*60*60*100+_min*60*100+_sec*100+_cs-_started

:: Populate variables for rendering (100+ needed for padding)
set /a _hours=_duration/60/60/100,_min=100+_duration/60/100%%60,_sec=100+(_duration/100%%60%%60),_cs=100+_duration%%100

echo Done at: %_time% took : %_hours%:%_min:~-2%:%_sec:~-2%.%_cs:~-2%

::prints something like:
::Done at: 12:37:53,70 took: 0:02:03.55

根据Luke Sampson的评论，这个版本是八进制安全的，尽管任务应该在24小时内完成。

这是凯西对答案的扩展。关于使用PowerShell中的Measure-Command:

您可以从标准的命令提示符调用PowerShell，如下所示: powershell -Command "Measure-Command {echo hi}" 这将消耗标准输出，但你可以通过从PowerShell添加| Out-Default来防止这种情况: 测量命令{echo hi | Out-Default} 或者从命令提示符: powershell -Command "Measure-Command {echo hi | Out-Default}"

当然，您可以自由地将其包装在脚本文件*中。Ps1或*.bat。