还有一种变化。。。

SELECT 
  Count(*) AS existFlag 
FROM 
  sys.columns 
WHERE 
  [name] = N 'ColumnName' 
  AND [object_id] = OBJECT_ID(N 'TableName')

您可以使用信息模式系统视图来查找有关您感兴趣的表的任何信息：

SELECT *
  FROM INFORMATION_SCHEMA.COLUMNS
 WHERE TABLE_NAME = 'yourTableName'
 ORDER BY ORDINAL_POSITION

您还可以使用Information_schema视图查询视图、存储过程以及数据库的几乎所有内容。

试试这个。。。

IF NOT EXISTS(
  SELECT TOP 1 1
  FROM INFORMATION_SCHEMA.COLUMNS
  WHERE 
    [TABLE_NAME] = 'Employees'
    AND [COLUMN_NAME] = 'EmployeeID')
BEGIN
  ALTER TABLE [Employees]
    ADD [EmployeeID] INT NULL
END

这在SQL Server 2000中对我有效：

IF EXISTS
(
    SELECT *
    FROM INFORMATION_SCHEMA.COLUMNS
    WHERE table_name = 'table_name'
    AND column_name = 'column_name'
)
BEGIN
...
END

IF EXISTS(SELECT 1 FROM sys.columns
      WHERE Name = N'columnName'
      AND Object_ID = Object_ID(N'schemaName.tableName'))

这应该是解决这个问题的比较简单和直接的方法。我曾多次在类似的场景中使用过这种方法。毫无疑问，它就像一种魅力。

if exists (
  select * 
  from INFORMATION_SCHEMA.COLUMNS 
  where TABLE_NAME = '<table_name>' 
  and COLUMN_NAME = '<column_name>'
) begin
  print 'Column you have specified exists'
end else begin
  print 'Column does not exist'
end