在SQl Server 2005中,我是否可以通过删除所有的表和存储过程、触发器、约束以及SQl语句中的所有依赖项来清理数据库?

要求理由:

我想有一个DB脚本清理现有的DB,这不是在使用,而不是创建新的,特别是当你必须把一个请求到你的DB管理员,并等待一段时间才能完成!


当前回答

删除oracle中的所有对象:

1)动态

DECLARE
CURSOR IX IS
SELECT * FROM ALL_OBJECTS WHERE OBJECT_TYPE ='TABLE' 
AND OWNER='SCHEMA_NAME';
 CURSOR IY IS
 SELECT * FROM ALL_OBJECTS WHERE OBJECT_TYPE 
IN ('SEQUENCE',
'PROCEDURE',
'PACKAGE',
'FUNCTION',
'VIEW') AND  OWNER='SCHEMA_NAME';
 CURSOR IZ IS
 SELECT * FROM ALL_OBJECTS WHERE OBJECT_TYPE IN ('TYPE') AND  OWNER='SCHEMA_NAME';
BEGIN
 FOR X IN IX LOOP
   EXECUTE IMMEDIATE('DROP '||X.OBJECT_TYPE||' '||X.OBJECT_NAME|| ' CASCADE CONSTRAINT');
 END LOOP;
 FOR Y IN IY LOOP
   EXECUTE IMMEDIATE('DROP '||Y.OBJECT_TYPE||' '||Y.OBJECT_NAME);
 END LOOP;
 FOR Z IN IZ LOOP
   EXECUTE IMMEDIATE('DROP '||Z.OBJECT_TYPE||' '||Z.OBJECT_NAME||' FORCE ');
 END LOOP;
END;
/

2)静态

    SELECT 'DROP TABLE "' || TABLE_NAME || '" CASCADE CONSTRAINTS;' FROM user_tables
        union ALL
        select 'drop '||object_type||' '|| object_name || ';' from user_objects 
        where object_type in ('VIEW','PACKAGE','SEQUENCE', 'PROCEDURE', 'FUNCTION')
        union ALL
        SELECT 'drop '
        ||object_type
        ||' '
        || object_name
        || ' force;'
        FROM user_objects
        WHERE object_type IN ('TYPE');

其他回答

还有一个样本

declare @objectId int,  @objectName varchar(500), @schemaName varchar(500), @type nvarchar(30), @parentObjId int, @parentObjName nvarchar(500)
declare cur cursor 
for 

select obj.object_id, s.name as schema_name, obj.name, obj.type, parent_object_id
from sys.schemas s
    inner join sys.sysusers u
        on u.uid = s.principal_id
        JOIN
        sys.objects obj on obj.schema_id = s.schema_id
WHERE s.name = 'schema_name' and (type = 'p' or obj.type = 'v' or obj.type = 'u' or obj.type = 'f' or obj.type = 'fn')

order by obj.type

open cur
fetch next from cur into @objectId, @schemaName, @objectName,  @type, @parentObjId
while @@fetch_status = 0
begin
    if @type = 'p'
    begin
        exec('drop procedure ['+@schemaName +'].[' + @objectName + ']')
    end

    if @type = 'fn'
    begin
        exec('drop FUNCTION ['+@schemaName +'].[' + @objectName + ']')
    end

    if @type = 'f'
    begin
        set @parentObjName = (SELECT name from sys.objects WHERE object_id = @parentObjId)
        exec('ALTER TABLE ['+@schemaName +'].[' + @parentObjName + ']' + 'DROP CONSTRAINT ' +  @objectName)
    end

    if @type = 'u'
    begin
        exec('drop table ['+@schemaName +'].[' + @objectName + ']')
    end

    if @type = 'v'
    begin
        exec('drop view ['+@schemaName +'].[' + @objectName + ']')
    end
    fetch next from cur into  @objectId, @schemaName, @objectName,  @type, @parentObjId
end
close cur
deallocate cur

在我看来这是一个相当危险的功能。如果你要实现这样的东西,我会确保以一种你不能每次事故都运行它的方式正确地保护它。

如前所述,您可以自己创建某种存储过程。 在SQL Server 2005中,您可以查看这个系统表来确定和查找您想要删除的对象。

select * from sys.objects

在这里我找到了新的查询删除所有sp,函数和触发器

declare @procName varchar(500)
declare cur cursor 

for select [name] from sys.objects where type = 'p'
open cur
fetch next from cur into @procName
while @@fetch_status = 0
begin
    exec('drop procedure ' + @procName)
    fetch next from cur into @procName
end
close cur
deallocate cur

我会在两个语句中做到:DROP DATABASE ??

然后创建数据库??

我正在使用Adam Anderson编写的脚本,该脚本已更新为支持dbo以外的其他模式中的对象。

declare @n char(1)
set @n = char(10)

declare @stmt nvarchar(max)

-- procedures
select @stmt = isnull( @stmt + @n, '' ) +
    'drop procedure [' + schema_name(schema_id) + '].[' + name + ']'
from sys.procedures


-- check constraints
select @stmt = isnull( @stmt + @n, '' ) +
'alter table [' + schema_name(schema_id) + '].[' + object_name( parent_object_id ) + ']    drop constraint [' + name + ']'
from sys.check_constraints

-- functions
select @stmt = isnull( @stmt + @n, '' ) +
    'drop function [' + schema_name(schema_id) + '].[' + name + ']'
from sys.objects
where type in ( 'FN', 'IF', 'TF' )

-- views
select @stmt = isnull( @stmt + @n, '' ) +
    'drop view [' + schema_name(schema_id) + '].[' + name + ']'
from sys.views

-- foreign keys
select @stmt = isnull( @stmt + @n, '' ) +
    'alter table [' + schema_name(schema_id) + '].[' + object_name( parent_object_id ) + '] drop constraint [' + name + ']'
from sys.foreign_keys

-- tables
select @stmt = isnull( @stmt + @n, '' ) +
    'drop table [' + schema_name(schema_id) + '].[' + name + ']'
from sys.tables

-- user defined types
select @stmt = isnull( @stmt + @n, '' ) +
    'drop type [' + schema_name(schema_id) + '].[' + name + ']'
from sys.types
where is_user_defined = 1


exec sp_executesql @stmt

来源:Adam Anderson的博客文章