我正在使用Adam Anderson编写的脚本，该脚本已更新为支持dbo以外的其他模式中的对象。

declare @n char(1)
set @n = char(10)

declare @stmt nvarchar(max)

-- procedures
select @stmt = isnull( @stmt + @n, '' ) +
    'drop procedure [' + schema_name(schema_id) + '].[' + name + ']'
from sys.procedures


-- check constraints
select @stmt = isnull( @stmt + @n, '' ) +
'alter table [' + schema_name(schema_id) + '].[' + object_name( parent_object_id ) + ']    drop constraint [' + name + ']'
from sys.check_constraints

-- functions
select @stmt = isnull( @stmt + @n, '' ) +
    'drop function [' + schema_name(schema_id) + '].[' + name + ']'
from sys.objects
where type in ( 'FN', 'IF', 'TF' )

-- views
select @stmt = isnull( @stmt + @n, '' ) +
    'drop view [' + schema_name(schema_id) + '].[' + name + ']'
from sys.views

-- foreign keys
select @stmt = isnull( @stmt + @n, '' ) +
    'alter table [' + schema_name(schema_id) + '].[' + object_name( parent_object_id ) + '] drop constraint [' + name + ']'
from sys.foreign_keys

-- tables
select @stmt = isnull( @stmt + @n, '' ) +
    'drop table [' + schema_name(schema_id) + '].[' + name + ']'
from sys.tables

-- user defined types
select @stmt = isnull( @stmt + @n, '' ) +
    'drop type [' + schema_name(schema_id) + '].[' + name + ']'
from sys.types
where is_user_defined = 1


exec sp_executesql @stmt

来源:Adam Anderson的博客文章

试试这个

Select 'ALTER TABLE ' + Table_Name  +'  drop constraint ' + Constraint_Name  from Information_Schema.CONSTRAINT_TABLE_USAGE

Select 'drop Procedure ' + specific_name  from Information_Schema.Routines where specific_name not like 'sp%' AND specific_name not like 'fn_%'

Select 'drop View ' + table_name  from Information_Schema.tables where Table_Type = 'VIEW'

SELECT 'DROP TRIGGER ' + name FROM sysobjects WHERE type = 'tr'

Select 'drop table ' + table_name  from Information_Schema.tables where Table_Type = 'BASE TABLE'

为了补充Ivan的回答，我还需要删除所有用户定义的类型，所以我在脚本中添加了以下内容:

/* Drop all user-defined types */
DECLARE @name VARCHAR(128)
DECLARE @SQL VARCHAR(254)

SELECT @name = (select TOP 1 [name] from sys.types where is_user_defined = 1)

WHILE @name IS NOT NULL
BEGIN
    SELECT @SQL = 'DROP TYPE [dbo].[' + RTRIM(@name) +']'
    EXEC (@SQL)
    PRINT 'Dropped Type: ' + @name
    SELECT @name = (select TOP 1 [name] from sys.types where is_user_defined = 1)
END
GO

没有一种单一的说法可以用来实现这一目标。

当然，您可以自己创建一个存储过程，用于执行这些不同的管理任务。

然后可以使用这条语句执行过程。

Exec sp_CleanDatabases @DatabaseName='DBname'

我会在两个语句中做到:DROP DATABASE ??

然后创建数据库??

删除oracle中的所有对象:

1)动态

DECLARE
CURSOR IX IS
SELECT * FROM ALL_OBJECTS WHERE OBJECT_TYPE ='TABLE' 
AND OWNER='SCHEMA_NAME';
 CURSOR IY IS
 SELECT * FROM ALL_OBJECTS WHERE OBJECT_TYPE 
IN ('SEQUENCE',
'PROCEDURE',
'PACKAGE',
'FUNCTION',
'VIEW') AND  OWNER='SCHEMA_NAME';
 CURSOR IZ IS
 SELECT * FROM ALL_OBJECTS WHERE OBJECT_TYPE IN ('TYPE') AND  OWNER='SCHEMA_NAME';
BEGIN
 FOR X IN IX LOOP
   EXECUTE IMMEDIATE('DROP '||X.OBJECT_TYPE||' '||X.OBJECT_NAME|| ' CASCADE CONSTRAINT');
 END LOOP;
 FOR Y IN IY LOOP
   EXECUTE IMMEDIATE('DROP '||Y.OBJECT_TYPE||' '||Y.OBJECT_NAME);
 END LOOP;
 FOR Z IN IZ LOOP
   EXECUTE IMMEDIATE('DROP '||Z.OBJECT_TYPE||' '||Z.OBJECT_NAME||' FORCE ');
 END LOOP;
END;
/

2)静态

    SELECT 'DROP TABLE "' || TABLE_NAME || '" CASCADE CONSTRAINTS;' FROM user_tables
        union ALL
        select 'drop '||object_type||' '|| object_name || ';' from user_objects 
        where object_type in ('VIEW','PACKAGE','SEQUENCE', 'PROCEDURE', 'FUNCTION')
        union ALL
        SELECT 'drop '
        ||object_type
        ||' '
        || object_name
        || ' force;'
        FROM user_objects
        WHERE object_type IN ('TYPE');