我想了解从另一个数组的所有元素中过滤一个数组的最佳方法。我尝试了过滤功能，但它不来我如何给它的值，我想删除。喜欢的东西:
var array = [1,2,3,4];
var anotherOne = [2,4];
var filteredArray = array.filter(myCallback);
// filteredArray should now be [1,3]
function myCallBack(){
return element ! filteredArray;
//which clearly can't work since we don't have the reference <,<
}
如果过滤器函数没有用处，您将如何实现它? 编辑:我检查了可能的重复问题，这可能对那些容易理解javascript的人有用。如果答案勾选“好”，事情就简单多了。
当前回答
你的问题有很多答案，但我没有看到任何人使用lambda表达式:
var array = [1,2,3,4];
var anotherOne = [2,4];
var filteredArray = array.filter(x => anotherOne.indexOf(x) < 0);
其他回答
你可以设置过滤器函数来遍历“过滤器数组”。
var arr = [1, 2, 3 ,4 ,5, 6, 7];
var filter = [4, 5, 6];
var filtered = arr.filter(
function(val) {
for (var i = 0; i < filter.length; i++) {
if (val == filter[i]) {
return false;
}
}
return true;
}
);
OA也可以在ES6中实现，如下所示
ES6:
const filtered = [1, 2, 3, 4].filter(e => {
return this.indexOf(e) < 0;
},[2, 4]);
下面是当数组中的项是对象时的操作方法。
其思想是使用map函数在内部数组中查找仅包含键的数组
然后检查这些键的数组是否包含外层数组中的特定元素键。
const existsInBothArrays = array1.filter((element1) =>
array2.map((element2) => element2._searchKey).includes(element1._searchKey),
);
函数的arr (arr1 arr2) { 函数filt(价值){ 返回arr2.indexOf(value) == -1; ｝ 返回arr1.filter (filt) ｝ . getelementbyid (p)。innerHTML = arr([1,2,3,4]，[2,4]) < p id = p > < / p >
/* Here's an example that uses (some) ES6 Javascript semantics to filter an object array by another object array. */ // x = full dataset // y = filter dataset let x = [ {"val": 1, "text": "a"}, {"val": 2, "text": "b"}, {"val": 3, "text": "c"}, {"val": 4, "text": "d"}, {"val": 5, "text": "e"} ], y = [ {"val": 1, "text": "a"}, {"val": 4, "text": "d"} ]; // Use map to get a simple array of "val" values. Ex: [1,4] let yFilter = y.map(itemY => { return itemY.val; }); // Use filter and "not" includes to filter the full dataset by the filter dataset's val. let filteredX = x.filter(itemX => !yFilter.includes(itemX.val)); // Print the result. console.log(filteredX);
