从移动库中获取图像uri的完整方法。

protected void onActivityResult(int requestCode, int resultCode, Intent data) {
        super.onActivityResult(requestCode, resultCode, data);

  if (requestCode == PICK_IMAGE_REQUEST && resultCode == RESULT_OK && data != null && data.getData() != null) {
                Uri filePath = data.getData();

     try { //Getting the Bitmap from Gallery
           Bitmap bitmap = MediaStore.Images.Media.getBitmap(getContentResolver(), filePath);
           rbitmap = getResizedBitmap(bitmap, 250);//Setting the Bitmap to ImageView
           serImage = getStringImage(rbitmap);
           imageViewUserImage.setImageBitmap(rbitmap);
      } catch (IOException e) {
           e.printStackTrace();
      }


   }
}

你可以像这样从uri中检索位图

Bitmap bitmap = null;
try {
    bitmap = MediaStore.Images.Media.getBitmap(this.getContentResolver(), imageUri);
} catch (IOException e) {
    e.printStackTrace();
}

下面是正确的做法:

protected void onActivityResult(int requestCode, int resultCode, Intent data)
{
    super.onActivityResult(requestCode, resultCode, data);
    if (resultCode == RESULT_OK)
    {
        Uri imageUri = data.getData();
        Bitmap bitmap = MediaStore.Images.Media.getBitmap(this.getContentResolver(), imageUri);
    }
}

如果你需要加载非常大的图像，下面的代码将以tile的形式加载它(避免大的内存分配):

BitmapRegionDecoder decoder = BitmapRegionDecoder.newInstance(myStream, false);  
Bitmap region = decoder.decodeRegion(new Rect(10, 10, 50, 50), null);

点击这里查看答案

这是最简单的解决方案:

Bitmap bitmap = MediaStore.Images.Media.getBitmap(this.getContentResolver(), uri);

private fun setImage(view: ImageView, uri: Uri) {
        val stream = contentResolver.openInputStream(uri)
        val bitmap = BitmapFactory.decodeStream(stream)
        view.setImageBitmap(bitmap)
}

Uri imgUri = data.getData();
Bitmap bitmap = MediaStore.Images.Media.getBitmap(this.getContentResolver(), imgUri);