我有这个功能来验证一个电子邮件地址:
function validateEMAIL($EMAIL) {
$v = "/[a-zA-Z0-9_-.+]+@[a-zA-Z0-9-]+.[a-zA-Z]+/";
return (bool)preg_match($v, $EMAIL);
}
这样可以检查电子邮件地址是否有效吗?
我有这个功能来验证一个电子邮件地址:
function validateEMAIL($EMAIL) {
$v = "/[a-zA-Z0-9_-.+]+@[a-zA-Z0-9-]+.[a-zA-Z]+/";
return (bool)preg_match($v, $EMAIL);
}
这样可以检查电子邮件地址是否有效吗?
当前回答
我准备了一个检查电子邮件有效性的函数:
function isValidEmail($email)
{
$re = '/([\w\-\.]+)@((\[[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}\.)|(([\w-]+\.)+))([a-zA-Z]{2,4}|[0-9]{1,3})(\]?)/m';
preg_match_all($re, $email, $matches, PREG_SET_ORDER, 0);
if(count($matches) > 0) return $matches[0][0] === $email;
return false;
}
FILTER_VALIDATE_EMAIL的问题是,它甚至认为无效的电子邮件是有效的。
以下是例子:
if(isValidEmail("foo@gmail.com")) echo "valid";
if(!isValidEmail("fo^o@gmail.com")) echo "invalid";
其他回答
在FILTER_VALIDATE_EMAIL中有一个更好的正则表达式,但任何正则表达式都可能给出糟糕的结果。
例如. .
// "not an email" is invalid so its false.
php > var_export(filter_var("not an email", FILTER_VALIDATE_EMAIL));
false
// "foo@a.com" looks like an email, so it passes even though its not real.
php > var_export(filter_var("foo@a.com", FILTER_VALIDATE_EMAIL));
'foo@a.com'
// "foo@gmail.com" passes, gmail is a valid email server,
// but gmail require more than 3 letters for the address.
var_export(filter_var("foo@gmail.com", FILTER_VALIDATE_EMAIL));
'foo@gmail.com'
你可能会考虑使用像Real Email这样的API,它可以进行深入的邮箱检查,以检查电子邮件是否真实。
有点像…
$email = "foo@bar.com";
$api_key = ???;
$request_context = stream_context_create(array(
'http' => array(
'header' => "Authorization: Bearer " . $api_key
)
));
$result_json = file_get_contents("https://isitarealemail.com/api/email/validate?email=" . $email, false, $request_context);
if (json_decode($result_json, true)['status'] == "valid") {
echo("email is valid");
} else if (json_decode($result_json, true)['status'] == "invalid") {
echo("email is invalid");
} else {
echo("email was unknown");
}
看完这里的答案后,我得出了以下结论:
public static function isValidEmail(string $email) : bool
{
if (!filter_var($email, FILTER_VALIDATE_EMAIL)) {
return false;
}
//Get host name from email and check if it is valid
$email_host = array_slice(explode("@", $email), -1)[0];
// Check if valid IP (v4 or v6). If it is we can't do a DNS lookup
if (!filter_var($email_host,FILTER_VALIDATE_IP, [
'flags' => FILTER_FLAG_NO_PRIV_RANGE | FILTER_FLAG_NO_RES_RANGE,
])) {
//Add a dot to the end of the host name to make a fully qualified domain name
// and get last array element because an escaped @ is allowed in the local part (RFC 5322)
// Then convert to ascii (http://us.php.net/manual/en/function.idn-to-ascii.php)
$email_host = idn_to_ascii($email_host.'.');
//Check for MX pointers in DNS (if there are no MX pointers the domain cannot receive emails)
if (!checkdnsrr($email_host, "MX")) {
return false;
}
}
return true;
}
您可以为此使用filter_var。
<?php
function validateEmail($email) {
return filter_var($email, FILTER_VALIDATE_EMAIL);
}
?>
如果你只是在寻找一个实际的正则表达式,允许各种点,下划线和破折号,它如下:[a-zA-z0-9.-]+\@[a-zA-z0-9.-]+.[a-zA-Z]+。这将允许像tom_anderson.1-neo@my-mail_matrix.com这样看起来相当愚蠢的电子邮件被验证。
根据我的经验,regex解决方案有太多的假阳性,而filter_var()解决方案有假阴性(特别是对于所有新的tld)。
相反,最好是确保地址具有电子邮件地址的所有必需部分(用户、“@”符号和域),然后验证域本身是否存在。
无法确定(服务器端)外部域是否存在电子邮件用户。
这是我在Utility类中创建的一个方法:
public static function validateEmail(string $email): bool {
// SET INITIAL RETURN VARIABLE
// ENSURE -> EMAIL ISN'T EMPTY | AN @ SYMBOL IS PRESENT
$emailIsValid = FALSE;
if (
!empty($email) &&
strpos($email, '@') !== FALSE
) {
// GET EMAIL PARTS
$email = explode('@', $email);
$user = $email[0];
$domain = $email[1];
// VALIDATE EMAIL ADDRESS
if (
count($email) === 2 &&
!empty($user) &&
!empty($domain) &&
checkdnsrr($domain)
) {
$emailIsValid = TRUE;
}
}
// RETURN RESULT
return $emailIsValid;
}