考虑:

var myArray = ['January', 'February', 'March'];    

如何使用JavaScript从这个数组中选择一个随机值?


当前回答

下面是一个如何做到这一点的例子:

$scope.ctx.skills = data.result.skills;
    $scope.praiseTextArray = [
    "Hooray",
    "You\'re ready to move to a new skill", 
    "Yahoo! You completed a problem", 
    "You\'re doing great",  
    "You succeeded", 
    "That was a brave effort trying new problems", 
    "Your brain was working hard",
    "All your hard work is paying off",
    "Very nice job!, Let\'s see what you can do next",
    "Well done",
    "That was excellent work",
    "Awesome job",
    "You must feel good about doing such a great job",
    "Right on",
    "Great thinking",
    "Wonderful work",
    "You were right on top of that one",
    "Beautiful job",
    "Way to go",
    "Sensational effort"
  ];

  $scope.praiseTextWord = $scope.praiseTextArray[Math.floor(Math.random()*$scope.praiseTextArray.length)];

其他回答

为了寻找一句真正的俏皮话,我得出了这个结论:

['January', 'February', 'March'].reduce((a, c, i, o) => { return o[Math.floor(Math.random() * Math.floor(o.length))]; })

方法1:

使用Math.random()函数获取(0- 1,1)之间的随机数 独家)。 将其乘以数组长度得到数字 (0-arrayLength)之间。 使用Math.floor()获取索引范围 从(0到arrayLength-1)。

Const arr = ["foo","bar"]; const randomlyypickedstring =arr[Math.floor(Math.random() * arr.length)]; console.log (randomlyPickedString);

方法2:

random(a, b)方法用于生成(a到b, b不排除)之间的数字。 取下限值,使数字范围从(1到arrayLength)。 减去1得到从(0到arrayLength-1)的下标。

const arr = [“foo”,“bar”]; const randomlyPickedString=arr[Math.floor(random(1, 5))-1]; console.log(randomlyPickedString);

这是一个简单的一行代码:

const randomElement = array[Math.floor(Math.random() * array.length)];

例如:

const月=(“1”,“2”,“3”、“4”,“可能”,“6”,“7”); const random = Math.floor(Math.random() * months.length); console.log(随机、几个月(随机));

如果您有固定的值(如月份名称列表),并且想要一行解决方案

var result = ['January', 'February', 'March'][Math.floor(Math.random() * 3)]

数组的第二部分是一个访问操作,如在JavaScript中为什么[5,6,8,7][1,2]= 8所描述的那样?

获取随机元素的通用方法:

让some_array =[‘简’,2月,3月,4月,“可能”); Let months = random_elems(some_array, 3); console.log(个月); 函数random_elems(arr, count) { 让len = arrr .length; 让查找= {}; Let TMP = []; If (count > len) Count = len; 对于(设I = 0;I < count;我+ +){ 让指数; {做 index = ~~(Math.random() * len); } while(查找中的索引); 查找[index] = null; tmp.push (arr(指数)); } 返回tmp; }